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(d) The address is on the network segment The slash has the meaning of "to" and "between".
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bThis is a network address.
This means the top 20.
That is, the network number is.
Subnet mask.
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Select C and E
The spacer between 255 and 20 is marked by the next 20 -- the number of digits of the subnet mask.
There are so many random answers, huh?
The answer is c and e
1, first of all, the one that starts with 192 is a private IP, option c is correct, option f is wrong2, 20 indicates that the network bit has 20 bits, and the network address of this network is ,, option e is correct, option d is wrong.
3. The broadcast address of this network is, but only a host address, not a broadcast address, so it is not a network address, and the options A and B are wrong.
So the correct answer is c and e
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This is a term for router configuration.
20 refers to the subnet mask 20 bits, so it is:
Therefore, e is correct.
It starts with a Class C private address.
Therefore, c is also correct.
The last bit, 255, is a broadcast address, not a network address.
Therefore, a is also correct.
Select: a, c, e
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I think it means or
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D, it seems to be right, A, C is obviously wrong, B is fine;
A Class A IP address consists of a 1-byte network address and a 3-byte host address, with the highest bit of the network address must be "0" and the address range is from to. There are 126 Class A networks available, each capable of accommodating more than 100 million hosts.
Based on the above, B and D seem to be legitimate IPs
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It should refer to the range of the IP address range after the subnet is divided.
For example, if you divide 8 subnets into 8 subnets, you will get the subnet mask by taking three digits in the third octect.
This division method is a theoretical division method, and in some cases, it may be necessary to use a mask to divide 16 theoretical subnets to get more than 8 available subnets.
If the subnet is divided according to the above method, the first and last address in each subnet are used as network addresses and broadcast addresses, and cannot be assigned to the host, so the host address range is:
…And so on.
In your environment, IP addresses can be divided into "private addresses" and "public addresses". >>>More
The conventional way is not good, because you can't communicate if you don't know the IP, and it's too troublesome to test them one by one, because there are too many IP addresses. Provide you with several methods, 1. Capture packets: Find a hub also called a hub (you can't use a switch), connect your computer to the hub, and then install a packet capture software on the computer (there is a famous packet capture software called sniffer, you can go to the network by yourself**), start to capture packets, and then connect the network cable of access control to the hub (be sure to open the packet capture software first, and then connect the access control), stop capturing packets after 10 seconds, and get the IP address of access control from the captured packets. >>>More
I'll come to your questions.
First of all, an answer can be drawn that your question is wrong. >>>More
Log in to the router, enable the firewall, and filter IP addresses
First of all, I want to tell you that there is --- a route that exists specifically for the end line offload. If you don't add something in the case of the existing setup, there is a way to achieve it, but it is relatively unreliable, and it has its drawbacks, which I will explain later. 1) Two routers are connected to two cats, and they are configured according to the normal single line. >>>More