High School Basic Chemistry Questions, High School Chemistry Basic Questions

Updated on educate 2024-03-05
10 answers
  1. Anonymous users2024-02-06

    You studied chemistry? I don't think it's like anybody, how can anyone learn like this! You'd be a genius if you could remember these ions!

    But at the same time, it's stupid! In fact, it is enough to remember the principle of reaction, that is the fundamental! No matter how the topic changes, the theory will never change!

    You must know that you are studying science, and no one will study science as a liberal arts! Figure out what you're going to learn first!

  2. Anonymous users2024-02-05

    1fe3+,fe2+,cu2+,al3+,mg2+,nh4+

    2[Al(OH)4]- (so-called ALO2-), CO32-, SO32-, S2-

    2. The formation of precipitates or complexes, the production of gases or the occurrence of redox reactions cannot coexist.

  3. Anonymous users2024-02-04

    Answering this type of question should pay special attention to the questions:

    1. "Avogadro's constant" is a very large value, which is only suitable for measuring microscopic particles, that is, the object of Avogadro's constant can be the number of particles contained in a certain amount of matter (such as molecules, atoms, ions, protons, neutrons, electrons, etc. or their combinations); It can also be the number of electrons transferred in a chemical reaction or the number of chemical bonds broken, etc.

    2. When using the "Avogadro constant" to measure the substance, it should be noted that the substance is stored in a wide state under normal or standard conditions (such as SO3, CHCL3, benzene, etc. are liquids under standard conditions);

    3. Whether the chemical reaction of Wang Yan can occur when the two gases are mixed (including the formation of equilibrium, such as 2NO2 N2O4);

    4. The essence of the redox reaction of the substance under the given conditions (such as 1mol Na2O2 reacts with a sufficient amount of CO2 or H2O, and the number of transferred electrons is only Na);

    5. The true form of particles or atomic clusters in solution or crystal (it should be considered whether the molecule is completely ionized or whether the ions are hydrolyzed or whether something is put into water to react with water, etc., such as in Na2O2 crystals, oxygen exists in the form of O22-. )

  4. Anonymous users2024-02-03

    That's right.

    Chloride ions refer to chlorine that can be ionized, and negative 1 valent chlorine is ionized, for example, there is negative 1 valent chlorine ionized by water in hydrochloric acid solution.

    The other valence states of chlorine are atomic clusters formed by being together with other atoms, such as: hypochlorous acid and clo- chloric acid with clo3 2- and perchloric acid with clo4 + These three acid groups are atomic clusters, and the chlorine in them cannot be ionized, in other words, it cannot exist alone.

    So only chlorine, which is reduced to minus 1 valence, can be ionized, i.e., only it is an ion, and then it must have one more electron than the chlorine atom.

  5. Anonymous users2024-02-02

    The Cl ion is said to have 8 electrons outside the nucleus, that is, one more electron than the Cl atom.

    As for the valency of Cl, it is manifested when Cl and other atoms form an atomic cluster, such as Clo

  6. Anonymous users2024-02-01

    The outermost shell of the chlorine atom has seven electrons, and when one electron is added, it becomes the chloride ion Cl-, and when the chlorine atom becomes Cl+, it does not lose electrons, but forms a shared electron pair with the electrons in other atoms (such as hydrogen). The electron pair is biased towards hydrogen, so the chloride ion at this point still has one more electron than the chlorine atom. By analogy, this sentence is correct.

  7. Anonymous users2024-01-31

    The chloride ion is cl-, so there is one more electron than the chlorine atom, don't think too much.

  8. Anonymous users2024-01-30

    Other valences are represented in atomic clusters.

  9. Anonymous users2024-01-29

    The first one, in general, is a strong base and a weak salt, such as sodium carbonate, and the second one should be based on what you are doing, and according to what you say, there are two kinds of precipitates.

    The third quark can't, because the atom is the smallest particle in a chemical change, and the fourth highest positive price is the number of electrons in the outermost shell, and its highest positive price is a few, for example, if cl has seven electrons in the outermost shell, then its highest positive price is 7

    The fifth Na ion is positive monovalent, and the CO3 ion is negative bivalent, and when it is written, it is Na2CO3, and the two of the negative bivalent ions of the carbonate ion run below the Na, and when you read it, it is sodium carbonate.

  10. Anonymous users2024-01-28

    It corresponds to Na2CO3, SO2 corresponds to Na2SO3, and SO3 corresponds to Na2SO4.

    2.It is an oxide that does not react with acids and bases, and there are three types of high schools: NO, CO, and H2O

    3.It may be that there are both AGCL and BASO4, and it should be judged according to the specific topic. There are other precipitates such as Ag2CO3 because part of the precipitate dissolves, Ag2CO3 reacts with nitric acid to dissolve.

    4.There are protons, neutrons, quarks, etc., which will not appear in chemical changes, junior high school content.

    5.The highest positive valence is the number of electrons in the outermost shell, for example, the highest positive valence of Cl is +7, and there are 7 electrons in the outermost shell of Cl.

    6.This is the content of junior high school. For example, the valency of Na2SO4 is +1, and the valency of SO4 is -2.

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In this reaction, there is only the electron gain and loss of nitrogen element, the valency has risen and decreased, so C is wrong, the increase of nitrogen in metadimethylhydrazine is oxidized, it is a reducing agent, so a is wrong, the reaction is the recombination of atoms, so there is an endothermic and exothermic process, C is wrong, D is left, of course, there are eight electrons transferred from two N2O4 to N2 D is correct.