Senior 1 Chemistry Compulsory 1 P17 P18 After class Exercise Answers

1~4dbbb 5.Because it is in the range of normal blood sugar values, the person's blood sugar is normal 6As a result, the concentration of the prepared solution is low, because in the process of pouring some, the solute is poured out!

7.Let the volume of the solution be x, 18*x= x= 8 = :

140:35:2 9(1)m(CuCl2) N(CuCl2)27 135= (2) There is Cu + 10. in this solution

The density of the gas under standard condition = molar mass of the gas m =

You may have ...... in the teaching books hereOther books can also try this method.

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bcddac

Heating 2cuo cuo+h2so4=h2o+cuso4 cuso4+2naoh=cu(oh)2+na2so4 cu(oh)2=heating cuo+h2o cuso4+fe=feso4+cu

2-+H2O 2Al+2Oh-+2H2O=2alo2-+3H2 gas.

CaO+CO2 gas search for cao+h2o=ca(oh)2 na2co3+ca(oh)2=caCO3 precipitation+2NaOH

A small amount of solution is dipped in platinum wire and burned on the flame, the flame of the fire is purple K+ Take a small amount of solution in the test tube, add a small amount of caustic soda solution dropwise to produce a white precipitate, and then dissolve Al and then take a small amount of solution in the test tube, add BaCl2 solution dropwise to produce a white precipitate SO4 2-11Let the mass of magnesium be x, then the mass of aluminum is (

Mg+2HCl=mgCl+H2 gas.

x a24/2=x/a a=x/12

2al+6HCl=2alcl3+3h2 gas.

b54/6=( b=(

vm=v/n n=

m=nm=x/12+( x=

n1 = m1 m1 = world socks 24 =

n2=m2/m2=

n1:n2=1:1

First of all, I can't help but complain that the rookie's answer is just a copy of the options you gave (there are some errors in them, I marked them for you in square brackets) - -

1，……This has to be explained ......Read the book and look up the concept to ...... it yourselfBy the way, it means that the product after a dissolves in water and reacts with water is a weak electrolyte.

2. Chlorine is dissolved in water to form HCl + hypochlorous acid, the former makes it red, and the latter bleaches ......

3，……The basic concept is to look up the book to ......100nm is the demarcation &......

a. The unit of mass is wrong; b. It is not indicated whether it is a standard condition; c……Are you sure it's right? ...... in which the volume of the solution changes when the solute is dissolved in water; d correct.

5. That's right

6. Only there is a change in valency in d (zero price h to positive one; positive bivalent cu to zero).

7,A eg: calcium carbonate decomposition; b correct; C&D reducing agent is the reduction of oxidizing agent. The reducing agent itself is oxidized by the oxidant, and the oxidant undergoes a reduction reaction.

What I understood at the time was that the oxidant was receptive, accepting electrons; The reducing agent is tapping, giving the electron ......Not explained.

8. The water under standard condition A is not gaseous; b, whether it is marked or not; c Correct; The amount of solute Na2SO4 in the solution is 1mol, so the amount of Na2SO4 is 2Na

a does not coexist in large quantities, carbonic acid decomposes unstable CO2, and CO2 escapes.

b Generate barium sulfate precipitate.

c neutralized

d Although there are nitrate ions in acidic conditions, the ...... in solution is already the bestPick D

a Untrimmed. b Write one less precipitate of sulfate ions and barium ions.

c Before hydrogen ions act on calcium carbonate, no free carbonate ions are considered to be present in the solution, ......In other words, calcium carbonate cannot be disassembled.

d ……Did you make a mistake? The product is chloride ion, and the reaction conditions should be reversible--

So there is no right answer.

11. The valence state of A increases, that is, A is oxidized, so it is in line with the topic, and B and C do not meet (the price of the product is reduced).

d There is no change in valence.

Let the number of three ions be 3k, 2k, and k

They provide a 3k positive charge, a 6k positive charge, and a 1k negative charge, respectively – a negative charge from sulfate ions of 3k + 6k - 1k = 8k is required. And because each sulfate ion has two negative charges, there are 8k2=4k sulfate ions. At this point, a conclusion is drawn.

a 3 are white precipitates.

b White precipitation, no phenomenon, gas generation (provided that sufficient amount is added dropwise).

c No phenomenon, no phenomenon, same as b

d Ibid

Let's take a look at the concept of electrolytes.

The test strip is wet, and the chlorine is dissolved in water to form HCl + hypochlorous acid, the former makes it red, and the latter has a bleaching effect.

Less than 10 nm is the solution, between 10 and 100 nm is the colloid, and more than 100 nm is the turbidity.

x2+3y2=2xy3

The redox reaction must have a change in chemical valence.

c The atomic number of the same volume of HE gas and H2 is not the same.

H CO32 Cl to generate water and CO2CaCO3+2H+=CO2 +H2O+Ca2+ redox reaction concept.

Depending on the solution, it is electrically neutral.

a 3 are white precipitates.

b White precipitation, no phenomenon, gas generation.

c No phenomenon, no phenomenon, gas generation.

d No phenomenon, no phenomenon, gas generation.

Chapter 1: Chemistry from Experiments.

1-1 Basic methods of chemical experiments.

1 Application of C1-2 stoichiometry in experiments.

5. 65-110 mg／dl., which is within the normal range.

6 This is not the right practice and will result in low results. This is because the part of the solution that is poured out contains solutes, which results in a decrease in the solute in the volumetric flask, i.e., the amount of solute in the volumetric flask decreases, and the amount of solute species concentration also decreases.

7 14 ml.

8 The ratio of the amount of matter is ca:mg:cu:fe:=224:140:35:29(1) Copper ions, chloride ions.

Review questions. 1．c

6.(1) False (2) False (3) False (4) Correct.

The obvious unit is mmol l).

Volume ratio = ratio of the amount of matter, so the quantity ratio of matter = 1 16:4 32 = 1:2) concentrate) * v (concentrate) = c (diluted) * v (diluted) then c (dilute) = (30 * 10 -3) mol mol l).

The first question is C. AgNO3 solution must be used to test CL-, but there is SO42- in the solution, which will interfere, so SO42- must be tested with BA(NO3)2 first, and the excess SO42- should be removed, and then add AGNO3 solution to test CL-. BaCl2 cannot be used, Cl- is introduced, so that it is not possible to determine whether Cl- is present in the original solution.

Question 2 is selected b. It should be noted that the requirement is separation, and impurity ions can not be introduced, so sodium ions and nitrates can not be there, first add water to filter out barium sulfate, and then add potassium hydroxide to precipitate ferric chloride, filter, dissolve and precipitate iron chloride with hydrochloric acid, so that the three substances are separated.

1. Choose C, because Ag2SO4 is slightly soluble in water and is also a precipitation, so the sulfate should be precipitated, but barium chloride cannot be added, because it will bring chloride ions and interfere with the detection of chloride ions in the solution.

2. Select B, add water, barium sulfate is insoluble in water, can be filtered, add potassium hydroxide to generate iron hydroxide precipitation, can be filtered out, the remaining filtrate is potassium chloride and excess potassium hydroxide, add hydrochloric acid to convert iron hydroxide into water and iron chloride, and convert excess potassium hydroxide into potassium chloride and water in the filtrate.

a. Wrong, silver nitrate precipitates chloride ions, and it can't be **c. Wrong, nitric acid brings nitrate impurities and cannot be eliminated.

d. Error, sodium hydroxide brings sodium ion impurities that cannot be eliminated.