A bundle of anchor cables requires a tensile strength of 500KN, how many steel strands should there

1. The tensile strength of the anchor cable.

It should be 1860MPa and the tensile force should be 500kN.

2. Anchor cable

When the main cable is anchored in the side hole in the suspension bridge, the main cable should be divided into many strands of steel bundles and anchored in the anchor ingots respectively, and these steel bundles are called anchor cables. The anchor cable is a prestressed steel strand that is fixed to the slope surface at the outer end and the other end is anchored in the stable rock mass within the sliding surface through the slope sliding surface.

Directly produce anti-slip resistance on the sliding surface, increase the anti-slip friction resistance, and make the structural plane in a compact state, so as to improve the integrity of the slope rock mass, so as to fundamentally improve the mechanical properties of the rock mass, effectively control the displacement of the rock mass, promote its stability, and achieve the purpose of remediating the bed, landslide and dangerous rock and dangerous rock.

One is on the line, the tensile strength of the anchor cable should be 1860MPa, the tensile force should be 500kN, we have a special anchor cable tensioning machine with 500kN.

Two strands of 1860 are also available.

The actual domestic production intensity is 1770

The anchor cable is basically made of steel strands with a diameter of 7 steel wires with a diameter of 5 mm. The ultimate tensile load pu: 1860*139=259kN.

Design load pa: pa<=. Generally, the anchorage force of the single bundle anchor cable design is 100-120kn.

The complete set of drawings of the design institute is (relatively conservative): the tensile strength of 4 bundles of anchor cables is 400kN, the tensile strength of 6 bundles of anchor cables is 500kN, and the tensile strength of 8 bundles of anchor cables is 600kN

Summary. MPA, which stands for megapascals, is one million N per square metre (or 1000 kN per square metre) and is a unit of stress. If the tensile stress of the bolt is 1MPa, then multiply 1MPa by 1000 and multiply the cross-sectional area of the bolt (converted to square meters), which is the tensile force of the bolt (kn).

For the anchor rod with a diameter of 22, the anchoring force design requirement is greater than 100kN, and how many MPa should the bolt tensile test reach

Pro, the anchor rod with a diameter of 22 is required to be more than 100kN, and the anchor tensile test should reach 60MPa.

MPA stands for megapascals, or 1 million Nius per square meter (or 1000 kN per square meter), which is a unit of stress. If the tensile stress of the bolt is 1MPa, then multiply 1MPa by 1000 in multiplying the cross-sectional area of the bolt (the change bucket is calculated as square meters of empty auspiciousness), which is the tensile force of the bolt (kn).

The pull-out force value of the bolt is specified:

1. At least one group (3) of each 300 bolts installed will be randomly sampled, and another set of pull-out force tests will be carried out when the design is changed or the material is changed.

2. The average value of the anchoring force or pulling force of the same group of anchors should be greater than or equal to the design value.

3. The anchoring force or pulling force of a single anchor in the same group shall not be less than 90 of the design Kaibi value. Highway belt Sunyan tunnel bolt pull-out force test regulations: The commonly used equipment for bolt pull-out test is hollow jack, manual hydraulic pump, oil pressure gauge, dial gauge.

The result index of the relay test is the pull-out force in kn. If you want to ask how much MPA the reading of the puller should be, check the conversion curve of your puller (the manufacturer's manual has it, if not, it needs to be calibrated by a qualified verification unit). For the design of 100kN, the pull-out test value of the bolt should not be less than 120kN

TB T3209-2008 is a yield strength of 335, ultimate strength 455, yield force of 127, maximum force 172, elongation 17

In the case of rock bolts, the maximum test load should not be less than twice the design load of the bolts.

In the case of soil anchors, the stress generated by the maximum test load should not exceed the standard value of the strength of the rebar, strand or wire.

Take a look at the Code for the Design of Building Foundations GB50007-2002, Appendix M, Appendix X

Specifically, look up the GB50086 standard, and meet the design requirements, there are two indicators, one is the ultimate tensile force of the rod body, and the other is the design value.

How many megapascals is the anchor cable aperture 150 and the internal force value of the anchor cable is 200kn! You're good sailing, and I'm glad to answer your <>

The aperture of the pro-anchor cable is 150, the internal force value of the anchor cable is 200kn, and the cross-sectional area of the anchor cable is 2000 square millimeters. The drawings require the anchor cable tension lock 200kN, and the tension pressure gauge should show 100MPa. The calculation is as follows:

1n/mm²=1mpa；200000÷2000=100mpa；Hopefully, my limb plexus can help you <>

Do you have any other questions?

Summary. Pro, if it is known that the area of the anchor cable and the pressure on the stressed surface is 1MPa, the pressure can be converted to force by the following formula: f = p a, where f is the force on the stressed surface, p is the pressure, and a is the area of the force.

Substituting 1MPa into the formula, we get: f = 1MPa A, if A is 1 square meter, then F = 1MPa 1m = 10 Pa 1m = 10 N = 1,000kN. Therefore, if the cable is subjected to a force area of 1 square meter and the pressure is 1 MPa, the pull-out resistance of the anchor cable is 1,000 kN.

Hello dear, happy to answer your <>

Poke the face and crack the feast]: 1MPa is a unit of pressure, not a unit of force. The pull-out force of the anchor cable is generally expressed in Newton (N) or Kn, not MPA.

If it is known that the area of the anchor cable and the pressure on the stressed surface are 1MPa, the pressure can be converted into force by the following formula: f = p a, where f is the force on the stressed surface, p is the pressure, and a is the area of the force. Substituting 1mpa into the public stare style, you can get:

f = 1 mpa a, if a is 1 square meter, then f = 1 mpa 1m = 10 pa 1m = 10 n = 1,000 kN. Therefore, if the stress area of the anchor cable is 1 square meter and the pressure is 1 MPa, the pull-out resistance of the anchor cable is 1,000 kN. <>

Summary. <>

Hello, dear, very happy to you your question, how much MP should be pulled by the anchor cable tensioning 200kn, help you find out, 100MPa

How many MP should be pulled by the anchor cable tensioning 200kn

Hello, pro-ant ant ride, very happy for your question, anchor rope virtual take Zhang Wu Yuan pull 200kn how much MP, help you find out, 100MPa

The calculation is as follows: 1n mm?=1mpa; 200000÷2000=100mpa;KN cannot be directly converted to MPa, KN is the unit of force, MPA is the unit of pressure orange, and the cross-sectional area of the force is equal to the pressure.