Please answer a math Olympiad problem to calculate age, thank you

When x is equal to 43 and the square of x is 1849, then the person was 43 years old in 1836, then 2013 should be 207 years old, which is obviously wrong. When x is equal to 44, the square of x is 1936, then this person was 44 years old in 1936, indicating that this person was born in 1892, so 2013 is 121 years old, which satisfies the topic. When x is equal to 45, the square of x is 2025, which has not yet come and does not fit the topic.

To sum up, x is equal to 44, and the old birthday star is 121 years old in 2013 (the only year square number in the age problem so far is 44 squared 1936, and nothing else). Absolutely original, I wish you progress in your studies!

If you are over 100 years old, you should have been born between 1813 and 1913.

42 is 1764 43 is 1849 44 is 1936 45 is 2025

Therefore, his old birthday star was 44 years old in 1936, and it can be known that the old birthday star was 121 years old in 2013.

The old birthday boy should have been born in 1892 and was 121 years old in 2013.

He was born between 1800-2000, and if the full square number during this period is the former, then the birth is 1849-43 1806, 2013-1806 207 years old, it seems that he is not so old, and he is discarded.

So it should be 1936 when he was 44 years old, born in 1936-44 1892, 2013-1892 121 years old.

The birthday star was 121 years old in 2013.

Hello lz, I hope my answer can help you.

Suppose the son is x years old this year, then his father is (x+30) years old.

From the meaning of the title, Cong slippery square grinds Zheng Kucheng.

x+1）*3=x+30+1

3x+3=x+31

2x=28x=14

A: My son is 14 years old this year.

1. The conditions given by this topic are not enough.

I can name several groups of these ages at random.

2. In another 15 years, the sum of their ages will be equal to the age of the uncle, indicating that the age of the uncle is now 15 years older than the age of the two.

This year they are half the age of their uncle, so this year they are 15 years younger than Xiao Ming and 3 years younger than Xiao Hong.

So, this year, Xiao Ming's age (15 3) 2 6 years old.

The first question is that the conditions are not enough.

Question 2. After another 15 years their age and increased by 30, while the uncle's only increased by 15, and at this time the age was equal.

So this year they are 15 years younger than their uncle, and their age is just half of their uncle's, so half of their uncle's age this year is 15, that is, the age sum is 15, and Xiao Ming is 3 years younger than Xiao Hong, so Xiao Ming is 6 years old and Xiao Hong is 9 years old.

1.The conditions are not enough.

2.Let Xiao Ming be x years old, Xiao Hong (x + 3) years old, and the uncle will be y years old.

x+（x+3）=y/2

x+15+(x+3)+15=y+15

It can be found. Xiao Ming x = 6

Little red x+3=9

Uncle y=30

As can be seen from the title, this year's father's age is 2 times that of Xiaofang, 4 times that of a few years, and 6 times that of a few years ago.

Since the age difference between dad and firefighter is constant.

So dividing this number by 2, dividing by 4, and dividing by 6 all get an integer, and because this number is between 20 and 30. So the age difference is 24

So Xiaofang is 12 years old this year, and Dad is 36 years old this year.

This year's dad is 3 times the age of Xiaofang, and their age difference is between 20 and 30 years old, and there are only 6 possibilities from the analysis of these two conditions:

10-30, 11-33, 12-36, 13-39, 14-42, 15-45, and then compared with other conditions, a few years ago, Dad's age was 5 times Xiaofang's age, 5 years ago, 10-30 was established (5-25), 6 years ago, 12-36 was established (6-30), and 7 years ago, 14-42 was established (7-35).

In a few years, Dad's age will be 7 times that of Xiaofang's age, and the title will not hold true (as you get older, the multiplier should be smaller and smaller).

The title is wrong. Age multiples are getting smaller and smaller.

Personally, I feel that there is a problem with the topic.

The age of the father and son should be multiplier and smaller over time.

There is a problem with this question, this year's age is a 3-fold gap, how can it become a 7-fold gap in a few years? Is 5 and 7 written backwards?

Did you make a mistake?

It's inconvenient to draw.

The age of the elder sister after 2 years is the age difference of 12 years for the younger brother 3 years ago (the drawing is very simple) Regard the age of the younger brother 3 years ago as a copy, then the age of the elder sister after 2 years is 4 parts, the difference is 3 parts, corresponding to 12 years old, then one is 4 years old, that is, the age of the younger brother 3 years ago The age is 4 years old, and the younger brother is 7 years old this year; My sister's age in 2 years is 4 4 = 16 years old, and my sister's age this year is 14 years old.

Column: 7 + 2 + 3 = 12 (years).

12 (4-1) = 4 (years).

My brother's age this year: 4+3=7 (years).

My sister's age this year: 4 4-2 = 14 (years old).

My sister is two years older than now in two years, and my younger brother is 3 years younger than now 3 years ago, that is, the difference between sister and brother is 7+5=12, so 12 (4-1)=4, so three years ago, my younger brother was 4 years old, and now my younger brother is 4+3=7 years old, and my sister is 7+7=14 years old.

The difference between the age of the older sister after 2 years and the age of the younger brother 3 years ago is 7 + 2 + 3 = 12

So my brother's age 3 years ago was 12 (4-1)=4, so my younger brother is 4+3=7 years old this year, and my sister is 12+4-2=14 years old this year.

Suppose the younger sister is now x years old, and the older sister is known to be older (x-5) years older than the younger sister, so the older sister is x+ (x-5) years old.

26-(x-5)=x+(x-5)

26-x+5=2x+5

3x=36x=12

x+(x-5)

So my sister is 12 years old.

My sister is 19 years old.

Huh, do you understand?

The younger brother is x years old this year, and the elder brother is 2x years old.

2x-9=5(x-9)x=12

My younger brother is 12 years old. My brother is 24 years old.

Brother: Brother = 2:1 = 8:4

Brother: Brother = 5:1

Per serving: 9 (8-5) = 3 (years).

This year's brother's age: 3x8=24 (years).

This year's brother's age: 3x4=12 (years).

Let the age of the elder brother be x and the age of the younger brother be y, then the system of equations y=1 2x can be listed

y-9=1/5(x-9)

Solve the system of equations.

x=24y=12