Ask high school chemistry questions, ask for advice, and expect to have an analysis process

As concentrated sulfuric acid absorbs water, the quality of the water is.

From the chemical equation Cuo + Co = glowing Cu + CO2 can be obtained to reduce the mass of the O atom so.

CuO+Co=Glowing Cu+CO2 Difference.

x y gives x = that is, the amount of co substance is , and the resulting CO2 =

So the mass of CO2 produced by organic matter is.

That is, the amount of carbon dioxide in the organic matter is.

That is, so there is, and because the organic matter is, i.e., there is organic matter, so the molecular formula is C2H6O.

The structure is simplified ch3ch2oh, ch3och3

1) The weight gain of concentrated sulfuric acid indicates that the reaction product contains water, that is, the product contains water, and the copper oxide mass is reduced by calcining copper oxide, and CO+CuO = CO2+Cu

It shows that the copper oxide loses O in the reaction of CO reduction of copper oxide, which is just seized by CO, and the amount of CO and Cuo substances is 1:1,,, and the total weight of CO2 obtained by reducing copper oxide and the original product is explained by the weight gain of soda lime, that is, subtracting the total weight of CO2 obtained by reducing copper oxide and the original product, indicating that the product contains.

Through the above analysis, it can be known that the organic matter reacts with oxygen to generate, i.e., ,, minus the one involved in the reaction, i.e., 1molo, and the organic matter can be known to contain ,,4molC0, that is: 1mol organic matter contains 6molH,1molo,2molc, the chemical formula is C2H6O, and the molecular formula of organic matter is C2H6O

2) The organic matter with the molecular formula C2H6O may be ethanol with the structural formula CH3-CH2-OH, and the methyl ether structural formula CH3-O-CH3 are all consistent

Answer: The possible structure of this organic matter is CH3-CH2-OH or CH3-O-CH3

4. C atomic number = proton number = 272, so choose C

5. B mass = number of protons + number of neutrons, atomic number = number of protons = number of nuclear charges = number of electrons outside the nuclear number = 112, number of neutrons = 277-112 = 165, so choose b

6. There are 23 electrons outside the br 3+ nucleus, then there are 26 electrons outside the r nucleus, and the number of neutrons = 56-26 =30

7. B atomic number = number of protons = number of nuclear charges = number of electrons outside the nucleus, according to the number of nuclear charges can draw a schematic diagram of the atomic structure, so as to determine the number of outermost electrons of the atom, can not determine the number of neutrons, so choose b

8. For example, the proton number of CH4, H2O, and NH3 particles is 10

9. There are x electrons of silver excitation outside the nucleus of ar n + , then there are x + n electrons outside the nucleus of r atom, mass number = number of protons + number of neutrons, then a = x + n + number of neutrons, number of neutrons = a-x-n, so choose a

10. ax m + number of electrons outside the nucleus = a-m, y n - number of electrons outside the nucleus = b + n, because the electron configuration outside the nucleus of the two ions is the same, so a-m = b + n

a=b+n+m, so choose a

I hope mine will help you in your studies!

The precipitate formed by the reaction of A and water is a mixture of alumina and iron oxide, the precipitate B after adding sodium hydroxide is iron oxide, and the elemental C is aluminum. The reaction in (1) is: Al2O3 + 2NaOH = 2Naalo2 + H2O

1) The ion equation is: Al2O3 + 2OH - 2alo2 - H2O2) and the reaction is: Al3+ +3NH3'h2o = al(oh)3 + 3nh4+

Reaction (3) chemical equation: Fe2O3 + 2A L = Al2O3 + 2Fe

Solid E is a mixture, potassium sulfate and ammonium sulfate.

1) Let the atomic number of c be x, then a is x-8, b is x-1, c is x+1, a, b, c, d four elements have a total of 56 electrons outside the nucleus, then there are x+x-8+x-1+x+1=56, x=16, so c is the envy s element, a is the o element, b is the p element, d is the cl element, 1mole element and sufficient acid interaction, can be produced under standard conditions.

It can be seen that the valency of E is +3 valence, which should be the element Al, so the answer is: oxygen; Phosphorus; Sulfur; Chlorine; Aluminium;

2) It will be easy to write by the first question.

3) The product of the combustion of C element in the full size of a element is SO2, which is reducible and Cl2

A redox reaction occurs in water to form H2

SO4 and HCl, the equation for the reaction is SO2

cl22h2

o═h2so4

2HCl, so the answer is: SO2

cl22h2

o═h2so4

2hcl；4) The compound formed by A and E is Al2

O3 is an amphoteric oxide, so the answer is: Al2

O3 amphoteric oxide;

5) The compound formed by D and E is AlCl3

NaOH solution is added, and Al3+ occurs

3OH-Al(OH)3, there is a white precipitate generated, Al(OH)3 is amphoterical, and the NaOH solution is added to further react to generate NaALO2 and water, and the ion equation of the reaction is Al(OH)Lingjiao 3OH-ALO2

2H2O, so the answer is: there is a white precipitate generated, and when the maximum amount is reached, it gradually decreases, and finally the precipitate disappears completely and becomes a clear solution; al3+

3oh-al（oh）3

al（oh）3

oh-alo22h2o．

1: The ratio of the quantity of the substance represents the ratio of the number of molecules, then the mass ratio = 3 * : 2 * 95 (own month, * means multiplication).

2: Since the mass ratio of sodium and magnesium = 3:2, then the ratio of CI in sodium chloride and magnesium chloride = 3:4 respectively, a total of 28mol, then the mass of sodium chloride and magnesium chloride can be calculated separately.

3: NaOH is not a precipitation, so just look at the amount of magnesium element, and calculate the amount of magnesium chloride from 2 = the amount of magnesium hydroxide substance, so it can be calculated.

You calculate yourself, give you ideas (conservation of quantities).