x 2 ax 1 0 solution set High One Mathematical Inequality

y=x 2+ax+1 is the parabola with the opening upward.

When delta=a 2-4<0 of x 2+ax+1=0, x 2+ax+1>0 is constant, and the solution set is r

When delta=a 2-4=0 of x 2+ax+1=0, the solution set of x 2+ax+1>0 is x not equal to -a 2

For delta=a 2-4>0 with x 2+ax+1=0, the solution set for x 2+ax+1>0 is: x>-a 2+(sqrt(a 2-4)) 2, or x<-a 2-(sqrt(a 2-4)) 2

In the first case, a 2--4<0 is -20, that is, a>-2 or a>2, which is solved as xx2 (x1, x2 is x 2 + ax + 1 = 0, and x1

When|a|Less than or equal to 2 is, no solution; At that time, x<-a 2-((x>-a 2+((

Sequence shaft stub method.

It's just to draw a number line.

This solution is solved, i.e., 0, 1, 2 take a ratio to 0

2 are small numbers such as: -1

Bring in the value of the original inequality.

If it is less than 0, it will be worn from below.

And then according to the odd wear even back.

Find the part on the number line that is greater than 0.

The range of values of x can be obtained.

0 is less than x and less than 1

or x greater than 2.

I don't know, right.

(0,1) and (2,+infinity).

Start wearing from the right, because x is obviously greater than 0 when it's large, so go through 2 from top to bottom from the right, then wear it from 1, and then wear it from 0. Complete.

Hungry, a is -2, if a

If a is greater than 2, the solution set is not less than 0 but greater than 0, and if a is less than 2, a-2 is less than 0. Divide to the right is to change the sign, so divide 2 by a-2 is minus one.

So the solution is -2

Solution: Since the set of solutions of the original inequality is: x

Therefore: a because the direction of the unequal sign changes)2 (a

They are obtained by two formulas: a

A In summary, a

Hello, glad for your question!

First of all, the left and right *x get 2x+1>0

2x>-1

Solution x>-1 2

So the solution set of this inequality is x>-1 2

I hope it can help you, if you have any questions, please ask in the follow-up, thank you!

Its equivalent equation is 1 a,2. It is divided into three more cases: a is greater than 2, and the solution is negative infinity to 2 and 1 a to positive infinity; (2) all numbers except two when equal; (3) 2 is greater than Soshi 1 a similar to (1).

Solution: Both sides of the equation are formed together (x-1) to obtain:

When x-1) >0, x>(x-1)(1+a), that is, when Min Mengchun ax<1+a, when a=0, x>1 is solved

When a >0, the solution is 11+a

When a=0, the solution is x without the bridge resistance.

When a>0, the solution is x unsolvable.

When a<0, the solution is (1+a) a

Because x x = 1, the original Shenzen is 1-1> 1+a is 0>1+a, and the resulting silver is Fengdan.

a<-1