Chemical pH Questions, about Chemistry Questions? PH value?

Analysis: This question examines the conservation of electric charge.

The solution is uncharged, while the ions in the solution are charged, so the anions and cations in the solution are bound to be neutralized.

According to the sum of the charges, it is 0Equations that can be columned:

As the solution does not know whether it is acidic or basic. So we can add up the charges of the cation and the anion separately. As follows:

Cation: Sodium =

Calcium ion = . So the sum of the charge numbers of the cations is :

Anion: sulfate =

Chloride ion = nitrate =

All of the above add up: sulfate *2 + chloride ion + nitrate =.

Apparently there are many cations. Therefore, the solution must be neutralized by anions. So the solution is alkaline.

The amount of hydroxide ion of the substance concentration c = cation - anion = 1 * 10 -3mol l.

So the hydrogen ions in the solution are equal to: 10 -11mol l (kw c hydroxide).

Therefore ph is equal to 11

The hydrogen ions and hydroxide ions ionized by pure water are the same, kw=2x10-7x2x10-7=4*10-14

After acid addition, KW = hydrogen ion concentration x hydroxide concentration.

kw just asked for it.

The h concentration is 5x10-6

substitution. 5*10-6*oh=4*10-14oh=8*10-9

1.Yes, there is.

The product of the concentration of OH- and H+ in the solution is a fixed value equal to 10 -14, and the H+ in the acidic solution has more OH-, and the opposite is true in the alkaline solution.

pH = 11 decreases, OH- increases.

H+ increases, oh- decreases.

Both have because H2O ionization emits OH

h ions. h﹢=10﹣11

pH = 11 [H] decreased by 100 times, OH increased by 100 times.

H] increase 1000 is OH decrease 1000 is adopted thank you.

1. Both.

Because there is an ionization equilibrium of water.

H2O = (reversible) OH-

H+, where c(oh-)*c(h+)=10 -14 (at room temperature)2, c(oh-)*c(h+)=10 -14, so c(h+)=10 -11mol l

ph=-lg(c（h+）)=11

3. The concentration of hydrogen ions is one percent of the original, the concentration of hydroxide ions is 100 times that of the original 1000 times of the original hydrogen ion concentration, and the original one-thousandth principle of hydroxide ion concentration is still a constant at room temperature.

The amount of OH-1 substance is:

The amount of molh+ substance is:

The remaining after the mol reaction is H+, and the amount of its substance is.

mol Therefore, the concentration of H+ in the solution is.

Its pH is 22, (m+16+1)g·mol-1=m, n=, and therefore the relative atomic mass of m is.

m=23g·mol-1

is an element of sodium.

Because the pH value of the solution is 11, it is known that the hydrogen ion concentration = 10 to the power of -11 mol l, and the hydroxide ion concentration = 10 to the power of -3 mol l: of which 10 to the power of 11 mol l is generated by water ionization [because the concentration of hydrogen ions generated by water ionization in this solution = the concentration of hydroxide ions generated by water ionization. The rest is produced by ionization of sodium hydroxide.

In this way, the ratio of hydroxide ions ionized by NaOH to hydroxide ions ionized by water in this solution is (10 to the 3rd power mol l to the 11th power of 10 mol l) 10 to the power of -11 mol l 10 to the 3rd power mol l 10 to the 8th power of 10 mol l = 10.

Solubility product of water at 25 °C 14. The number of hydrogen ions is 10 (-11), all of which are ionized by water. And H2O==H+ +OH-, the hydrogen ions ionized by water are equal to hydroxide, which is 10 (-11).

While the total amount of hydroxide ions is 10 (-3), we can know that the hydroxide ionized by sodium hydroxide is 10 (-3)-10 (-11).

It's good to compare the two: 10 (-3)-10 (-11) 10 (-11), do the math yourself.

I think this problem should be solved with the idea of ionization equilibrium, first of all, there is HCL HAC 1mol L in the mixed solution

Then use the three-part pose.

HAC = (reversible) AC-+H+

1-x x x+

This is the state of equilibrium, the hydrogen ions ionized by acetic acid and acetate should be equal, but there is hydrochloric acid in the solution, so the concentration of hydrogen ions is x+

Then you can list the equations.

Solve the equation to find [h+]=x= I don't know if the calculation is correct, the method should be correct, it is recommended that you calculate it again by yourself)

So ph=

pH is the commonly log-negative value of the concentration of hydrogen ions, i.e., pH=-LG[H+].h+].

For the hydrogen ion concentration, PoH is also a common log-negative value for the OH- ion concentration, i.e., POH=-LG[OH-].oh-].

It is water-soluble with a hydrogen ion concentration of 25 degrees Celsius.

In the container, the relationship between POH and pH value:

ph+poh=

So ph=

In calculating the pH of an alkaline solution, the POH of the solution must be calculated first, and then the pH of the solution must be calculated from pH =

3 or 11

The H+ concentration of water ionization is 10-11 mol L. The former pH = 3 and the latter pH = 11

For the former, the concentration of H+ ionized by HCl is, then the concentration of OH- is 10 -11 mol L, and these OH- are ionized by water, and every time water ionizes an OH-, it must ionize an H+ at the same time, so the concentration of H+ ionized by water is 10 -11 mol L

For the latter, the concentration of OH- ionized by NaOH is 10 -11 mol L, and these H+ are ionized by water.

pH = - log10 molar concentration of hydrogen ions in the solution, so the pH of this solution is 11 Gr.

1, C (H+) is indeed copied differently, the total ionization of hydrochloric acid is attacked, the incomplete of acetic acid, so Bai is smaller than Du; pH is directly linked to C(H+), so the ratio of acetic acid.

DAO hydrochloride is high (this is not much to explain, right?) high acidity poor); Since the total amount of H+ that can be ionized is the same, the ability to neutralize the base is the same (acetic acid will continue to ionize until the reaction is complete, so the amount of H+ participating in the reaction is still the total amount); In the case of reaction with Zn, the speed of hydrochloric acid is relatively fast (C(H+) is high, the instantaneous rate of the reaction is relatively fast, which is the relationship between concentration and rate), but the final amount of hydrogen is the same; The same dilution results are the same as those of the non-diluted one, except that for the acid itself, the data will vary.

2. The same pH, that is, the same C(H+), then the amount of acetic acid is more than hydrochloric acid, because acetic acid cannot be completely ionized, so the ability to neutralize the alkali, hydrochloric acid is not as good as acetic acid, and Zn reaction, because the value of C(H+) is the same, the rate is the same, but acetic acid can react with more Zn. If diluted, it will promote the ionization of acetic acid, so the pH of acetic acid will be lower than that of acetic acid after dilution.

1.Because hydrochloric acid is a strong electrolyte completely ionized, acetic acid is a weak electrolyte partially ionized, so when the DAO concentration is the same, the C (version H+) of hydrochloric acid is large and the pH is small, but if the reaction vinegar is made.

The right acid should be continuously ionized out of H+, so the ability to neutralize the base is the same, as much hydrogen as the excess Zn reaction, the same dilution factor, and the pH of hydrochloric acid is small.

high hydrochloric acid; high pH hydrochloric acid; The ability to neutralize alkali is strong, and hydrochloric acid is strong; Produce an equivalent amount of hydrogen; high acetic acid in a small area;

Same; pH the same; strong acetic acid; Yu = reacts with acetic acid to produce a large amount of hydrogen; high acetic acid in a small area;

High and low equal Equal After dilution, it depends on how much dilution is diluted, if it is not much, the hydrochloric acid is low, and if it is more, it is all 7