What components are needed for electronic design amplifier topics

First of all, you have a core controllable amplifier, such as VCA810, AD603, etc.; If you want to control it, you need a single-chip microcomputer; If you want to drive the circuit, you need a power amplifier; There are other amplifiers for detection circuits, and it should be possible to use an instrument amplifier, so choose it yourself! Good luck!

Electronic accessories、Is it a design circuit?。

Select Amplifier:

1. First of all, look at the single power supply application or dual power supply application. The amplifier is not indicated as a single power supply, and can generally only be used with dual power supply.

2. Secondly, look at the power supply voltage range.

3. Look at the working bandwidth again, the working bandwidth should be greater than the maximum working frequency * magnification.

4. The other is the noise index, do you need to check the zero? Almost negligible.

Look at your amplification components, I use a lot of transistors.

The open-loop amplification of the operator is infinite, and we use the amplifier to use the closed loop to get the required amplification, that is, the ratio of the connection mode and size of the input and feedback resistance, so you use the experiment box simulation, you can also claim to change the value of the resistance to achieve, as for the circuit design, I think you are very good at it!

1) A is an error amplification circuit, so there is un = uz when working normally;

2） uz = uo - iz*r3；Because a current (iz) is required for the regulator to work, iZ>0, then uz < uo;

And un = uo*(r2+r1''）/(r1+r2) ；

That is, the output voltage value of the circuit uo = un*(r1+r2) (r2+r1''）；

Then the maximum value is in r''= 0 (when the r1 tap slides to point b);

uomax = un*（r1+r2）/ r2；

The minimum value is in r''= r1 (when r1 taps slide to point a), then uo = un;

In this way, uz cannot be equal to un and the power supply will be out of control;

The minimum value should be uomin = uz + izmin *r3, and izmin is the minimum regulated current value;

In order to avoid the occurrence of un = uo, a resistor is also connected in series on top of r1;

So the output voltage range is: uomin---uomax ;

This problem can be found using circuit analysis:

1) Static working point: vb=, according to kcl:

ib=ib1-ib2=

ic=βib=

vce=ucc-icrc-uz=

2) Dynamic Parameters:

rbe=300+26mv/ib=200+358=558ωau=-βrc/rbe=-60x1k/

ri=rb1//rb2//rbe≈531ωro=rc=1k