About the Heavenly Ninja Sect D High Finger Point

Updated on technology 2024-03-15
11 answers
  1. Anonymous users2024-02-06

    。。The entrance from the second floor to the third floor is at the exit from the second floor to the first floor, and it was just unavailable when it came to the second floor, because you have to kill the void to activate the entrance, since you have killed all the people, then you can go down to the third floor, but you have to be cautious and blind, because, after going down to the third floor, you can't turn back.

  2. Anonymous users2024-02-05

    No, you can take a closer look to see if there are still people who haven't finished killing.

  3. Anonymous users2024-02-04

    nd, if you play fb, the glyph activation must and then be quick** Wild growth, I think so! Talent 57 14 60 11 is casual, it's better to point out the freshman 3 points! **Technique 5 + 1 5 rejuvenation 1 wild growth Swift** For people with less blood, nourishment can also be read Bears are not clear!

    It's not always a heavy beating, laceration and so on.

  4. Anonymous users2024-02-03

    Don't copy it? It's the best plan summarized by the master.,WOW has developed to this day.,The techniques are pretty much the same.,It's just that adjustments will be made according to personal preferences and specific bosses.。 There are all the essence posts of the NGA German area, from talents, loadouts, to operation cycles.

  5. Anonymous users2024-02-02

    d$2:d2="Head of household"Get an array of true and false, and this data is divided by dao0 to an array of "divide 0 error" and 0; Genus.

    The implication of the whole formula: find the non-erroneous value (0) in the array obtained above, and get the corresponding a$2:a2 data.

    One thing to note about the lookup function is that the second parameter must be in ascending order; When it is not sorted in ascending order, the last eligible value will be obtained, which is why the formula uses the reference method of d$2:d2, after the next pull-down, the last line of reference can only be this line, which ensures that the result is correct.

  6. Anonymous users2024-02-01

    =lookup(1,0/(d$2:d2="Head of household"),a$2:a2)0/(d$2:d2="Head of household")

    Returns a single-column array.

    lookup(1,0/(d$2:d2="Head of household"), a$2:a2) in 0 (d$2:

    d2="Head of household") to find 1 in the single-column array, and return the next value of the nearest 1, that is, the last 0 value corresponds to the value of column A in row.

  7. Anonymous users2024-01-31

    This is a reading function, if column D shows the head of household, then directly in column E to display the content of column A, not the specified other cell content.

  8. Anonymous users2024-01-30

    Find the closest 1 in column D2 and return the value of column A in the same row (Zhang San).

    d$2:d2="Head of household"Get a true and false, found as true, found as false

    0/d$2:d2="Head of household"Found as 0, not found as error.

  9. Anonymous users2024-01-29

    Parallelograms (excluding rectangles, squares).

    Diamond shape (excluding the special form of square).

    This is not an inscribed quadrilateral.

    The following is how to determine whether a quadrilateral is an inner quadrilateral of the garden, if the diagonal diagonal of a quadrilateral complements each other, then the four vertices of this quadrilateral are on the same circle.

    An outer angle equal to its inner diagonal quadrilateral is bordered by a circle.

    If the other vertex is on the same side of the base and the vertex angles are equal, then the two triangles have a common circumscribed circle.

    The four vertices are equidistant from a fixed point, and the quadrilateral is enclosed in a circle.

  10. Anonymous users2024-01-28

    No, a quadrilateral with 180° diagonal addition is required to be attached to a circle, according to the determination of a four-point contour.

    You can go to the encyclopedia to see it.

  11. Anonymous users2024-01-27

    In fact, it is very simple to think of it this way: the triangle must be connected to the circle, and the remaining point is on the circle, so the quadrilateral is also connected to the circle, and if it is not there, it is not connected to the ......

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