Please have a mental question, can you help? 5

Updated on society 2024-03-04
11 answers
  1. Anonymous users2024-02-06

    In fact, there are still a few plastic surgery now, and now there are more beautiful women because they will dress up now, in fact, it is wrong to say that beauties are fake, or we should be optimistic.

  2. Anonymous users2024-02-05

    No, people are beautiful because of this, not cute because of beauty!

  3. Anonymous users2024-02-04

    Landlord, can you please talk about Bao'er??

    Compare your age to your age or your 20s? What can you see about this??

    Bao'er is **** at the age of 12, so busy every day, the whole ghost!

  4. Anonymous users2024-02-03

    Nowadays, makeup technology is very developed, and hairstyles can cover up some shortcomings, plus blind herd mentality...

  5. Anonymous users2024-02-02

    I believe that no matter how beautiful a person is, he will have a ** photo that is not good-looking. No one is perfect, Tiffany used to be fatter, Sica wore braces, and they didn't wear makeup before their debut, so there will be some anti to find those who don't wear makeup and take smashed**, by the way, a little ps, just compare it with good makeup and fat loss**, which is called plastic surgery. Actually, they are not so exaggerated.

    Even in China, double eyelid cutting is a common thing. Take 10,000 steps back, even if cutting the double eyelids is plastic surgery, Yuri is just a double eyelid. It has nothing to do with plastic surgery.

    It's all about girlhood when I was a child.**

  6. Anonymous users2024-02-01

    Hehe, it's just a joke.

    Insert: China's plastic surgery industry is not yet developed, Chinese do not have such strong economic capabilities, and 99% of the beauties on the streets of China have not undergone plastic surgery. And 99% of South Korea has been rectified.

  7. Anonymous users2024-01-31

    People are getting prettier the longer they get.

  8. Anonymous users2024-01-30

    Because of the search for Zhang **, so you came to a conclusion?

  9. Anonymous users2024-01-29

    c Article 42 of the Insurance Law amended on February 28, 2009 adds a paragraph related to inheritance, which stipulates that "if the beneficiary and the insured die in the same event, and the order of death cannot be determined, the beneficiary shall be presumed to have died first." ”

  10. Anonymous users2024-01-28

    Hello: The answer is C.

    If the beneficiary and the insured die in the same event, and the order of death cannot be determined, the beneficiary is presumed to have died first.

  11. Anonymous users2024-01-27

    1. 1)

    n^2+n+41=n(n+1)+41

    It can be seen as two adjacent natural numbers adding 41

    So the most straightforward conclusion:

    When n=40, 40*41+41=41 2=1681

    When n=41, 41*42+41=41*43=1763

    So: let n=41k-1 (k is an arbitrary positive integer).

    n^2+n+41=n(n+1)+41 =(41k-1)*41k+41=41[(41k-1)k+1]

    So: there are infinitely many n, so that the polynomial n2 + n ten 41 denotes the composite number.

    2) n2+n ten41=n2+n-2+43=(n+2)(n-1)+43

    Let n=43k+1 (k is an arbitrary positive integer).

    n2+n ten, 41 = (n + 2) (n - 1) + 43 = (43k + 3) * 43k + 43 = 43 [(43k + 3) k + 1].

    i.e., there are infinitely many n so that the polynomial n2 + n ten 41 is a multiple of 43

    2.Solution: pq+11 is a prime number and pq+11 must be an odd number.

    pq must be even.

    p and q are both prime numbers p=2, or q=2

    If p=2, since 7p+q and pq+11 are prime numbers.

    Q+14 and 2q+11 are both prime numbers.

    Obviously, q cannot be a natural number of the 3k+1 and 3k+2 types, because then q+14 or 2q+11 will be a multiple of 3 instead of a prime number, and q can only be 3

    If q=2, then 7p+2 and 2p+11 should be prime numbers

    Let p=3k+l, then 7(3k+1)+2=21k+9 is divisible by 3.

    Let p=3k+2, then 2(3k+2)+11=6k+15 is divisible by 3

    p can only be a multiple of 3, i.e. p = 3

    To sum up, p and q are 2 and 3

    pq+qp)÷(2p+2q)

    3.Each number can be thought of as the first term 1, the common ratio is 100, and the sum of the proportional number series is the expression of these numbers.

    n=1x(1-q^n)/(1-q)

    n is the numerical value of the first number, q is the common ratio, and n is the first number, to the power of the multiple.

    n=100^n-1/99

    Only when n = 1 does the number not be factored into a prime number.

    When n = other numbers, they can be decomposed from the previous formula, so the proposition is proved.

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