Challenging wisdom? Believe in yourself and prove it

1.The algorithm is wrong. Guests pay 9 yuan per person, a total of 9 * 3 = 27 yuan.

Among them, 25 yuan was given to the boss as room fee, and the remaining 27-25 = 2 yuan was hidden by the waiter. In other words, the part that the waiter hides belongs to the guest and cannot be added to the part paid by the guest.

2.Buy whole onions**: 1 kg 1 yuan, buy ** :( yuan 1 kg separately. So the ** bought separately became cheaper.

3.Climb 3 meters on the last day, the remaining time = (7-3) (3-2) = 4 days. Total time = 4 + 1 = 5 days.

4.First of all, buy 10 peaches for 1 yuan. Take 9 of these peach hues for 9 3 = 3 peaches, and the remaining 1 peach hu.

Take 3 peach hus for 3 3 = 1 peach, and the remaining 1 peach hu. Borrow a peach hu, a total of 3 peach hu, exchange 3 3 = 1 peach, return 1 peach hu, no left. Total peach trees = 10 + 3 + 1 + 1 = 15.

7.Let each person get x in the end, then.

Before the penultimate steal, there are 1+(5x+1)*5 4=(25x+9) 4.

Before the penultimate steal, there were: 1 + (25 x + 9) 5 4 * 4 = (125 x + 61) 16.

Before the third steal, there were: 1 + (125 x + 61) * 5 16 * 4 = (625x+369) 64.

Before the second steal, there were: 1 + (625x+369)*5 64*4 = (3125x+2101) 256.

It turns out that there are: 1 + (3125x+2101)*5 256*4=(15625x+11529) 1024=15x+11+265(x+1) 1024.

To make the upper number an integer, x=1023, the total number of coconuts is 15621

Calculate 11 3 = 3 ......2. Eligible 11 multiples are: 11,44,77. The law is 11 + 33n = 44 + 33n n = -1,0,1 ......

11/5=2……1. Eligible 11 multiples are: 44,,99,154. The law is 44+55n n=0,1,2......

11/7=1……4. Eligible 11 multiples are: 55,132,209. The law is 55+77n n=0,1,2......

11/9=1……2. Eligible 11 multiples are: 44,,143,242. The law is 44+99n n=0,1,2......

Not counting 7 people per table, the remaining three together meet 44+495n

For a table of 7 people, the rule is 55+77N

Available: 495n 11 -1 is divisible by 77 11. Substituting gives n=5

So, the total number of people = 44 + 495 * 5 = 2519

10.Calculated: number of sets = 1 (1 21 + 1 28) = 1 (7 84) = 84 7 = 1211

There are 3 people to stay, 30 yuan a night. The three of them each paid 10 yuan, and 30 yuan was handed over to the boss.

Later, the boss said that today's discount was only 25 yuan, and he took out 5 yuan and ordered the waiter to return it to them, and the waiter secretly hid 2 yuan, and then distributed the remaining 3 yuan to the three people, each of whom received 1 yuan. In this way, at the beginning, each person paid 10 yuan, and now it is returned 1 yuan, that is, 10-1 = 9, and only 9 yuan per person, 9 yuan per person for 3 people, 3 x 9 = 27 yuan + 2 yuan hidden by the waiter = 29 yuan, and one yuan went to **???

ps: lz shouldn't count everyone out of 9 pieces.

If you think about it for yourself, in my mind, there is actually one person who is missing a block. If it's 10-1=9, which waiter's 2 yuan? Actually, 5 yuan can't be divided equally among 3 people.

Hypothesis: In fact, there is a person who is less than one yuan, and the real money is 9-8-8, which was originally 9 yuan for everyone, when the 1 yuan of the second person and the 1 yuan of the third person were taken by the waiter, according to my thinking, not everyone was out of 9 yuan.

30-5=25，5-2=3。The three are divided equally among three people, one yuan per person, the first one actually only has 9 yuan, the second person has 8 yuan, and the third person has 8 yuan. In addition to the 2 pieces taken by the waiter and the 3 pieces given to them by the boss. 9 + 8 + 8 + 2 + 3 = 30, the money is not less.

This question is actually very simple, but there is a problem with the question, and it is deliberately said that each person paid 9 yuan to mislead.

You. I've been misled about this question as well... I came up with it when I was in the bathroom.

1st Floor Your answer to question 4 is wrong It should be 14 There is no mention in the question to let you borrow It is known that the conditions that are not given are unavailable 10-3 = 7 3 Hu for a peach Plus the remaining peaches A total of 8 And so on.

This method is more single-cycle, but your idea is very good, (borrow one) o( ohaha, according to what you say, then directly eat a few peaches on credit.

Question 5 Twelve balls divided into three parts Measure two of them If the results are equal, weigh the remaining four twice for a total of three times But this is the ideal effect If not equal, swap two of the four balls in the two parts you measure, Now you just have to remember the balls and look at the results again You can narrow down the target range to two balls, and then measure them again, and the result is still three times.