32 mention. For a 2kb storage space, its address can be 000H to 7FFH 20

First understand what KB represents, address line: k=10, data line: b=8 bits, the calculation method is how many power of the address line according to 2, the data line is equal to the number of bits), and then the total storage space = the size of the address line * the size of the data line.

So2kb = 10 times of 2 * 3 times of 2 = 11 times of 2 = 2048

In understanding what an address is, the address starts from 0000h (h stands for 16 digits), and the calculation method is for example, ABCDH is the cubic of ax16 + the quadratic of bx16 + the first time of CX16 + the zero of DX16.

And 2048 can be regarded as the quadratic of 8*16, so the hexadecimal code of 2048 is 0800h, and the address is from 0000h, so the upper limit is reduced by one, that is, 07ffh (f stands for 15, hexadecimal is every hexadecimal).

In summary, the address of 2KB storage space can be from 0000h to 07ffh, a total of 2048 optional addresses (such as 0000 0000 0000 0000, this is one of them).

Because it is 2kb, you must have 2k-1024x2=2048 addresses to access all the addresses, 2047=7x16 2+15x16+15=2047, and then count 000, a total of exactly 2048 addresses.

KB stands for 1024 bytes, and each address in memory holds one word, and 2KB of storage space means that there are 2048 addresses, that is, its offset address is 000h to 7ffh in hexadecimal. That is, 0 to 2047 in decimal.

Is it a college to take the computer exam.

Summary. If the RAM address range is from 0x2000 0000 to 0x2000 2000, that is, there are 2000 memory addresses, and 1 memory address can store 8-bit binary numbers, how to calculate how many bytes of this space is in size?

First, use 0x2000 2000 -0x2000 0000=2000, and the resulting 2000 is a hexadecimal number.

Then convert 2000 in hexadecimal to decimal, what is it?

Use the calculator that comes with window, calculate, it is equal to 8192, that is, 8192 bytes, and then count to 1024 is equal to 8kb

If the memory address of a certain computer is 00000h to 7ffffh, the storage capacity is high.

Hello, an address can store 1 byte, the address is from 0000h to 7fffh, then the capacity is 7fffh + 1 byte; Converting to decimal is 32767+1=32768bytes, 1024byte=1kb, so that's 32kb

Hope mine is helpful to you.

But my answer is 512k

I'm sorry to look away, I'm missing a 0 and f

I won't, can you write down the steps.

Sorry, it's a bit slow to receive information here, so you can wait a minute.

If the RAM address range is from 0x2000 0000 to 0x2000 2000, that is, there are 2000 memory addresses, and 1 memory address can store 8-bit binary numbers, how to calculate how many bytes of this space is in size? First use 0x2000 2000 -0x2000 0000=2000, and then convert 2000 to decimal in hexadecimal system, what is it equal to? Use the calculator that comes with window, calculate, it is equal to 8192, that is, 8192 bytes, and then count to 1024 is equal to 8kb

Knowing that the starting address of a memory unit is 2001h and its capacity is 16kb, what is its last address?

Byte-addressed, 16k = 16384 = 4000h.

The starting address is 2001h.

That's 7ffffbyte, which is a total of 524,288 bytes.

A memoryaddress is the number of a storage cell in the memory. Due to the large number of memory cells in memory, each memory cell needs to be assigned a memory address in order to make a lookup.

The memory address is the number of the storage unit in the memory.

Each memory cell holds one byte of data

One byte (byte) 8 binary bits (bit).

Hexadecimal numbers are used to express addresses.

For example: Intel8086 has a memory capacity of 1 megabyte (1MB).

Four hexadecimal numbers are often used to represent an address.

where an uppercase h (or lowercase h) indicates that it is a hexadecimal number.

8KB = 8 x 1024 = 8192 byte addresses

First, convert 8192 to hexadecimal to 2000h address code, and subtract the starting address, that is, in 1000h+1fff=2fffh

The number can be from 1000h to 2fffh

The basic unit of storage capacity is bytes, and the address at the end is x, x-1h+1000h=1kb, and 1k is decimal and converted to hexadecimal. x-1000h+1h=1kb, x-1000h+1h=400h.

The capacity of memory in a computer is measured in bytes. In other words, a memory address represents one byte (8 bit) of storage space. A 32-bit operating system supports up to 4GB of memory space, which means that the CPU can only address 2 to the 32nd power (4GB), that is, there are 4G = 41024M (byte) = 410241024KB (byte) = 4102410241024 byte (8bit), that is, 2 is 2 to the 32nd power 8 bits.

It's like how many numbers are there from 2 to 9, =9- 2+1=8 The basic unit of storage capacity is bytes, the last address is x, x-1h+1000h=1kb, 1k is decimal, convert hexadecimal x-1h+1000h=400h, x=13ffh.

We hope we can help you.

It is 1fffffffff.

Get 512MB equals 2, 9MB to the power of 2 equals 2, 19KB to the power of 2 equals 29b to the power of 2, convert to binary 10....00 (1 followed by 29 zeros).

Because every forward calculation of this type of problem needs to be added by one bit, it should contain its own number, so it needs to be reversed at 1.

Get 29 1s (too many, for ease of understanding, can't write the entire binary number in Chinese) according to the conversion hexadecimal bit is equal to four binary bits:

29 4 7 remainder 1 (where 7 means a group of 4 1s, 1 means an extra 1, i.e. 0001) Four 1s in hexadecimal represent f, and one 0001 represents 1.

Starting at 0x, the following numbers are hexadecimal. and h mean the same thing, except that h is placed after the hexadecimal number, and 0x is placed before the hexadecimal number. (Hehe, isn't there a feeling of sudden realization, it turns out that there is more than one way to represent hexadecimal numbers!)

Now let's talk about the operation process, in fact, 512MB * 1024KB * 1024B = 536870912 = 1FFFFFFFFH is the standard operation process, it is not easy to explain in detail, first of all, the unit of 512MB is megabytes, you need to convert it into byte units, 1 trillion is equal to 1,000 1,000, in the computer field, 1,000 refers not to 1000 integers, but to 1024, so 1 megabyte is equal to 1024 1024 bytes, that is, 1MB=1024* 1024b, and 512mb = 512 * 1024 * 1024b, that is, 536870912 bytes, converted to hexadecimal is 2000 0000 bytes. 0000 0000h represents the first position of memory, and 0000 0001h represents the second position of memory. The law is:

Address ** is the memory location minus one, so the address of the last memory location, which is the 2000 0000h memory location, should be 2000 0000h minus one, 2000 0000h-1=1fff ffffh. Get answers! You should get the idea!

Hehehehe, I hope it can help you, I wish you a happy study!

Hello, when the capacity of the internal memory is 512MB, if the hexadecimal representation of the first address is 00000000h, then the hexadecimal representation of the last address.

512m=512*1024*1024=536870912=20000000h, so the last address is 20000000h-1=1fffffffh.

Sincerely answer every question for you! Best if you're satisfied! If you have any questions, please keep asking!

Have a great day! Happy every day.

5fff+1=6000

6000-5000=5000(h)

5000(h)

20kb for example: 4096 (4k) 20480 (20k) so, the storage space of 1000h 4fffh is 20-4 = 16k.

1000h 5fffh, a total of 5fffh + 1-1000h = 5000h addresses, that is, 4kb 5 = 20kb.

Very basic hexadecimal conversion ......5000h = 5×2^12。

1kb = 1024 bytes, hexadecimal is 400h, so its addressing range is 0 3ffh, knowing that the old 1-bit hexadecimal corresponds to 8-bit binary, and 3 corresponds to binary "11", so the binary addressing range is:

That is, 10-bit binary addressable 1kb space, and hexadecimal up to 3ffh. It's too much.