All points are presented, urgent C language programming Student Information Statistics 20

Hello, there hasn't been much time lately, so I can only remind you that the focus of this zhi topic is not dao

It is to calculate the integral, but to solve the non-version.

In , when n1 = 1 h1-(h1+u1) —e = 0, so —e = h1 (h1+u1).

Bringing in can be simplified.

, when n1=1 and j=1, you can simplify a version of the expression about x.

I can only help you get here.

right. It's all equations, what do you ask for?

Hello, there haven't been many times lately.

du, so I can only remind you about this topic.

1: It is known that a=13, b=6, and the decimal value of a%b is ().

a%b, integer % integer, means finding the remainder, so 13%6=1

2: If the value of x is 15 and the value of n is 2, then the value of x after the expression x%=(n+3) is ().

x%=(n+3) is equivalent to x=x%(n+3), x%=n+3 also means x=x%(n+3), similar to +=, so x=x%(n+3), x=15%5, x=0

3：intx=y=4,z=2;x=y==z;then the value of x is ().

x=y=4, the equal sign is combined to the right, that is, in this case, it is calculated from right to left, so it is equivalent to y=4; x=y;

And x=y==z,== has a higher priority than =, so it is equivalent to x=(y==z), y=4, z=2, so y==z is not true, so the value of y==z, the pure slag formula of the table is false, that is, 0, so x=0

4: If defined: int

a=10,b=9,c=8;Then the following statement is executed sequentially, and the value in variable b is ().

c=(a-=(b-5));

c=(a%11)+(b=3);

From the above questions, the basic pants height, c=(a-=(b-5)) is equivalent to c=(a=a-(b-5)), c=(a=10-(9-5)), c=(a=6), so a=6, c=6, b=9 (the expression b-5 does not change the value of b).

c = (a%11) + (b = 3) is equivalent to, c = 6% 11 + 3 = 6 + 3 = 9, so a = 6, c = 9, b = 3

5:intx=2,y=2,z=0;then the value of the expression x==y>z is ().

x==y>z, which is a composite logical expression, has a higher priority than ==, so it is equivalent to x==(y>z), y>z is true, so y>z==1, x==1 is not true, so the value of the expression is 0

6: If there is the following definition and statement int

a[4]=,p;

p=&a[2];Then the value of *--p is ().

p=&a[2];Indicates that p is the address of a[2].

p is equivalent to *(-p), that is, first subtract p by 1, which is the address of a[1], and then use the * operator to take out the value in the address, which is 1