How to calculate the beam load and how to calculate the load on the lintel

When calculating, assuming that the wall is two or four walls, take the bulk density of ordinary bricks 18 (if it is an ordinary machine brick, take 19) kn square meters, and take 17 (lime mortar or mixed mortar) kn square meters for the ash layer, therefore, the load generated per square wall is:

19 * kn square meters (because the ash layer is generally 20 thick, double-sided ash should be multiplied by 2.) Finally, multiply by the area of the wall on the beam, which is the load on the beam.

For the foundation beam under the wall, the existing view is that the wall above the cap beam is a semi-infinite plane elastomer, the foundation beam and the wall (semi-infinite elastomer) are deformed together, the foundation beam is regarded as the inverted elastic foundation beam under the load of the pile top, the reaction force of the foundation beam is solved according to the elastic theory, and the load acting on the foundation beam is simplified after simplification, and then the internal force is calculated according to the ordinary continuous beam. For the strip foundation beam under the column, the existing view is that it can be regarded as the calculation of the elastic foundation beam, that is, the pile top reaction force acts on the beam as a concentrated force, the column is the support of the beam, and the internal force is analyzed according to the ordinary continuous beam, and the pile top reaction force is calculated and determined according to the elastic foundation frame. For the foundation beam in the above two different cases, the existing views have regarded it as an elastic foundation beam in the calculation process, but the difference is that the foundation beam under the wall is regarded as an inverted elastic foundation beam, and the foundation beam under the column is regarded as an elastic foundation beam.

However, it should be pointed out that the above treatment method of the existing view is inconsistent with the definition of elastic foundation beam.

Calculated according to the uniform load.

When calculating, set the wall as two or four walls.

Take the bulk density of ordinary bricks 18kn square meters, take 17kn square meters of gray layer, the load generated per square wall is: 19 * kn square meters, and finally, multiply the wall area on the beam to get the load on the beam.

According to the size of the applied surface, the load is divided into point load, object line load and surface load. Loads that are distributed over a large area and cannot be regarded as concentrated forces are called distributed loads. If the distributed load is distributed, it can be reduced to a parallel force distributed along the centerline of the object.

Failure form: reinforced brick lintel.

Under the action of bending moment and shear force, when the tensile stress in the tensile zone of the lintel exceeds the tensile strength of the brick sliding body.

, vertical cracks will appear in the tension zone in the middle of the span; When the main tensile stress of the oblique section at the support exceeds the tensile strength of the brick masonry along the tooth joint, oblique cracks will appear near the support, which are manifested as stepped oblique cracks in masonry materials.

Horizontal thrust occurs when brick flat arch and arc arch lintels crack in the middle of the span. This horizontal thrust is absorbed by the walls at the ends of the supports. When the shear strength of the plaster joint of this wall.

When insufficient, it will cause the bearing to slide and fail, which is more likely to occur at the wall at the end of the house.

The failure form of reinforced concrete lintel is the same as that of general flexural members, that is, bending and shear failure, and sometimes the local compressive failure of masonry at both ends of the support should be considered.

1. Standard value of beam self-weight=;

2. The design value of variable load is kn m; ( is the combined value coefficient of the live load) 3, the design value of the permanent load has two possibilities, a ；b. ；

4. If the basic combination value of the load is 40kn m, the maximum bending moment in the span is 40 5 8 = 125 kn·m;

5. If the basic combination value of the load is 40kN, the maximum shear force of the support side is 40 5 2=100kN.

1. Standard value of beam self-weight=; 2. The design value of variable load is kn m; ( is the combined value of the live load ridge only coefficient) 3, the design value of the permanent load has two possibilities, a ；b. ；4. If the basic combination value of the load is 40kN, the maximum bending moment in the span is 40 5 8=125kN·m (not kn m!).

or positive 5, if the basic combination value of the load is 40kNm, then the maximum shear force of the support side is 40 5 2 = 100kN. (Nor kn m ha!) ）。

When calculating, set the wall as two or four walls to take the bulk density of ordinary bricks 18 (generally used is an ordinary machine brick, take 19) kn square meters, touch the ash layer to take 17 (lime mortar, mixed mortar) kn square meters, so that the load generated per square wall is:

19* square meters.

The ash layer is generally 20 thick, and the ash is touched on both sides, so it should be multiplied by 2. Finally, multiply by the area of the wall on the beam to get the load on the beam.

According to the size of the applied surface, the loads are divided into point loads, line loads and surface loads. Loads that are distributed over a large area and cannot be regarded as concentrated forces are called distributed loads. If the distributed load is distributed, it can be reduced to a parallel force distributed along the centerline of the object.

The bulk density of the wall x the thickness of the wall x (floor height, beam height) + the load of the plaster.

According to the provisions of the current national standard "Code for Seismic Design of Buildings" GB50011-2010, in the ** area, the suitable construction height of the frame structure is related to the local fortification intensity. Because the lateral shift resistance of the frame structure is lower than that of the shear wall structure, the suitable construction height of the frame structure is lower than that of the shear wall structure, and the pure frame structure is rarely used in high-rise buildings.

The vertical loads borne by high-rise building structures for general purposes include self-weight (permanent loads) such as structures, infill walls, and decorations, and floor service loads, snow loads, etc. (variable loads); The horizontal load has the effect of wind load and **. Various loads may occur on the structure at the same time, but with different probabilities.

In general, the structural analysis is carried out separately under the action of various load indicators, and after the internal forces and displacements are obtained, they are combined with partial coefficients and combination coefficients.