The more difficult chemical equation balancing problem who has

Updated on educate 2024-03-22
7 answers
  1. Anonymous users2024-02-07

    You can search for the leveling of redox equations, such as the reaction equation of potassium permanganate and sulfuric acid, hydrogen peroxide mixed solution.

  2. Anonymous users2024-02-06

    Chemical Equation Balancing: The equation of chemical reactions strictly adheres to the law of conservation of mass.

  3. Anonymous users2024-02-05

    Mainly look at the valency and atomic combination, generally speaking, the equation, the + valency on the left and right sides is consistent, and the - valency is also consistent.

  4. Anonymous users2024-02-04

    Let's introduce you to a simple way to trim chemical equations.

    Lee's equation:

    The method is as simple as setting an unknown number in front of each substance in the chemical equation, such as a, b, c, d, e....

    2) According to the law of conservation of atoms, write the ,.. of each atom in the chemical equation about the unknown numbers a, b, c, d, e, fso that we get a system of primary equations about the conservation of atoms;

    3) Set a, b, c, d, e, f,..Any one of the unknowns is equal to 1 (equal to other numbers is fine), and the system of equations is substituted to solve the unknowns a, b, c, d, e, f, ,..the value of ;

    4) Solve a, b, c, d, e, f,..value to its simplest form.

    For example, trim: KMno4 + HCl (concentrated) = KCl + MnCl2 + Cl2 + H2O

    Solution: (1) Let the coefficients in front of each substance be a, b, c, d, e, f, that is:

    A KMnO4 + B HCl (concentrated) = C KCl + D MnCl2 + E Cl2 + F H2O

    2) Get the system of equations for the conservation of atoms:

    k (potassium): a = c (a potassium atom on the left equals c potassium atoms on the right).

    Mn (manganese): a=d (a manganese atom on the left is equal to a manganese atom on the right).

    o(oxygen): 4a = f (4a oxygen atoms on the left equals f oxygen atoms on the right).

    h (hydrogen): b = 2f (b hydrogen atoms on the left equals 2f hydrogen atoms on the right).

    Cl (chlorine): b = c + 2d + 2e (b chlorine atoms on the left is equal to c + 2d + 2e chlorine atoms on the right).

    3) Now let a=1 and solve the above equation:

    a=1 ;b=8 ;c=1 ;d=1 ;e= ;f=4 ;

    4) The result of the solution is simplified (reduced to the least common divisor form of an integer).

    a=2 ;b=16 ;c=2 ;d=2 ;e=5 ;f=8 ;

    So the result of the chemical equation trimming is:

    2kmNO4+16HCl (concentrated)=2KCl+2mnCl2+5Cl2+8H2O

    This method is simple and straightforward, and is suitable for all chemical equations in high school, especially for more complex chemical equations.

  5. Anonymous users2024-02-03

    Once these three are paired, there will be no big problem.

    Reaction of ferric tetroxide and dilute nitric acid.

    Reaction of ferrous iodide and the same amount of chlorine.

    Reaction of ferrous bromide and equal amount chlorine.

  6. Anonymous users2024-02-02

    Turn left|Turn right (remember to adopt it).

  7. Anonymous users2024-02-01

    nh4no3—n2↑+ hno3 + h2o

    na2sx + naclo + naoh ——na2so4 + nacl + h2o

    fe3o4+kmno4+h2so4=k2so4+mnso4+fe2(so4)3+h2o

    Answer: 5NH4NO3 = 4N2 + 2NHO3 9H2O

    na2sx + 3x+1)naclo +(2x-2) naoh = x na2so4 + 3x+1) nacl +(x-1) h2o

    10) Socks Fe3O4 + (2) kmNO4 + (48) H2SO4 = (1) K2SO4 + (2) Slow MnSO4 + (not referring to 15) Fe2 (SO4) 3 + (48) H2O

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