In RT ABC, C RT, note ABC, BC a 5

1, from a:c=1 2, obtain:c=2a

Substituting a2+b2=c2, and because b is greater than 0, we get: b=root number 3 * a: b:

c = (root number 3 * a): c = root number 3 22, from the condition: a = root number 2 * c root number 3 = root number 2 * 6 root number 3 = 2 * root number 3

From a2+b2=c2, we get:

b2 = c2 - a2 = 6 * 6 - 2 times the root number 3 * 2 times the root number 3 = 24 and because b is greater than 0, so b = 2 * root number 6

This seems to be based on Yu Xuan's theorem! , from a:c=1 2,:

c=2a is substituted for a2+b2=c2, and because b is greater than 0, we get: b=root number 3 * a: b:

c = (root number 3 * a): c = root number 3 22, from the condition: a = root number 2 * c root number 3 = root number 2 * 6 root number 3 = 2 * root number 3

From a2+b2=c2, we get:

b2 = c2-a2 = 6 * 6 - 2 times the root number 3 * 2 times the root number 3 = 24 and because b is greater than 0,

1。The root number is 3:2, and the Pythagorean theorem a2+b2=c2, then b = root number 3, so b:c = root number 3:2

Pythagorean theorem a2 + b2 = c2, then b: c = 1: root number 3, b: 6 root number 6 = 1: root number 3b = 2

Because abc is a triangle at right angles.

So a square + b trivial nuclear base = c square.

A square + 2AB + B square - 2AB = C square.

a+b) squared - 2ab = c squared.

100-10 = c squared.

c = 3 roots under 10

Because c is the length.

So 10,5 under the root number of c = 3, c * c = a * a + b * b = (a + b) * (a + b) - 2ab = 10 * 10 - 2 * 5 = 90

So C=,2, in the right triangle ABC, because the attitude change angle C is 90 degrees to the front sail, then there is A 2 + B 2 = C 2

and a+b=10 ab=5 a 2+b 2=(a+b) 2-2ab=100-10=90=c 2 3 and root number 10,1,

a: c=1 2, find b = root number (c 2 -a 2 ) root number 3 2 cb : c = root number 3 : 2

a: c = 2: 3, c = 6 3, a = 6 2b = root number (c 2 -a 2) 6

The Pythagorean theorem is very simple b:c=:3, if a:c== 2:3, c=6 3, then the value of b is 6, or the Pythagorean theorem!

Cosine theorem cosc=(a +b -c) 2ab

The Pythagorean theorem is a special case of the cosine theorem.

According to the Pythagorean theorem, the side corresponding to the angle of the 30° angle of the cavity difference is half of the hypotenuse), so BC = 2/2 c

ac = the root number of 2 thirds