Sequence Find the general term formula, how to find the general term formula for the number series

Updated on educate 2024-03-01
6 answers
  1. Anonymous users2024-02-06

    Is it (an-1) or (an-1)+1 under the score line?

  2. Anonymous users2024-02-05

    1. Constructing the method of equal difference number series.

    2. Constructing an equal proportional sequence method:

    1 Define the construction method. By defining q=a(n+1) an, the proportional sequence is constructed through transformation.

    is constant), which can be reduced to a proportional sequence of a(n+1)+x=a(an+x).

    is constant). It can be constructed as a proportional sequence of a(n+1)+x*c(n+1)=a(an+x*c n).

    into a proportional sequence of a(n+1)+x1n+x2=a(an+x1(n-1)+x2).

    3. Function constructor.

    For some more complex recursive formulas, by analyzing the structure, associating with formulas and functions similar to the recursive structure, and then constructing a bridge function to find the general term formula of the recursive formula.

    For example, the number series an, a1=1, a(n+1)=an 3-3an, find the general term formula an.

    Solution Consider the recursive relationship with the formula (a+b) 3=a 3+3a 2b+3ab 2+b 3.

  3. Anonymous users2024-02-04

    Write out the first 5 items first, find the pattern...

  4. Anonymous users2024-02-03

    This is not the first big question in the 2017 national college entrance examination number series in Paper 3, which is easy to find. In the second question, you can use the first n terms and sn of the proportional series

  5. Anonymous users2024-02-02

    In general, the general formula for finding a sequence of numbers has the following principles:

    1) If there are positive and negative in the known number series, then determine the positive and negative signs first, and generally use (-1) n or (-1) (n-1) to represent the positive and negative signs.

    where (-1) n indicates that the odd term is negative, and the other indicates that the odd term is positive, and 2) after the positive and negative signs are determined, the plus and minus signs are no longer considered, and the general terms are just found for the rest.

    If there are both integers and fractions in a given sequence, then the integers must be written as fractions, and then the numerator and denominator can be separated to find the general term.

    3) When the given series of numbers are integers, generally see whether the sum or difference between the adjacent two terms is the same, if it is different, there is a certain rule, such as the n power of a certain number, etc., if the above is not good, then look at the difference between the two The general term of the series is found first, and then the accumulation method can be used to find the general term of the original series.

  6. Anonymous users2024-02-01

    Solution: s2 = 2 2 * a2 = a1 + a2 = 1 2 + a2

    a2 = 1/6

    s3 = 3^2 * a3 = a1 + a2 + a3 = 1/2 + 1/6 + a3

    a3 = 1/12

    s4 = 4^2 * a4 = a1 + a2 + a3 + a4 = 1/2 + 1/6 + 1/12 + a4

    a4 = 1/20

    The general formula for guessing is an = 1 [n(n+1)].

    Certificate: When n = 2, there is.

    s2 = 2^2 * a2 = a1 + a2 = 1/2 + a2

    a2 = 1/6 = 1/[2*(2+1)]

    Suppose that when n = n, there is an = 1 [n(n+1)], sn = n 2 * an = n (n+1), then.

    When n = n+1, there is.

    sn+1 = n+1)^2 * an+1 = a1 + a2 + an + an+1 = n/(n+1) +an+1

    an+1 = n/(n+1)]/n+1)^2 - 1] =1/[(n+1)(n+2)]

    So when n = n+1, the formula holds.

    So, for any n, there is an+1 = 1 [(n+1)(n+2)], and the proposition is true.

    Proof is complete.

Related questions
10 answers2024-03-01

It is known that f(x)=a x+a x +a x +a n x , and a , a , a , a , .,a n is a series of equal differences, n is a positive and even number, and f(1)=n, f(-1)=n; Finding the general term of a n? >>>More

14 answers2024-03-01

Three numbers are equal differences, then.

a1+a3=2a2 >>>More

9 answers2024-03-01

Equal difference series sn=na1+n(n-1)d 2 or sn=n(a1+an) 2. The sum formula for the first n terms of the proportional series is: sn=[a1(1-q n)] (1-q) and the relation between any two terms am, an is an=am·q (n-m).

8 answers2024-03-01

Let's start by defining two concepts.

and a symbol. >>>More

10 answers2024-03-01

Since it is an equal difference series, so a8-a4=4d, d is the tolerance, then d=-4, from a4=a1+3d, we can know a1=a4-3d=24, from sn=na1+n(n-1)d 2 to get sn=-2n 2+26n >>>More