Fourth grade Olympiad, don t use equations.

1. Use the method of profit and loss to answer the problem.

Cars have: (35+5) 5=8 (cars).

There are 30 8+5=245 (people) or (30+5) (8-1)=245 (people).

2. Draw a line diagram and solve the problem with the method of doubling.

Apricot trees: (780-120) (1+1+3)=132 (trees) Peach: 132+120=252 (trees).

Apple trees: 132 3 = 396 (trees).

3. Stipulate 3 2 = 3x4; 4△3=4x5x6。Excuse me: 2 3+5 2=?

Rule: m n=m(m+1)(m+2)......m+n-1) is the product of n consecutive natural numbers, starting with m as the smallest natural number.

1.(30+5+5) 5=8 cars.

8 30 + 5 = 245 people.

2 3 apple trees + 2 apricot trees +120=780660 5=132 (apricot trees).

132 3 = 396 (apple tree).

132 + 120 = 252 (peach tree).

I don't understand the third question.

1. Profit and loss issues.

35+5) 5=8 (vehicles).

2. (780-120) (3+1+1)=132 (lessons) 132 lessons for apricot trees, 396 lessons for apple trees, and 252 lessons for apricot trees.

1) The number of years of the grandson is changed to the number of months, which is exactly the same as the age of the grandfather--- and the age of the grandson is expanded by 12 times (there are 12 months in a year).

Grandchildren's age = 78 (12+1) = 6 years old

Grandpa age = 78-6 = 72 years.

2) Difference multiplier problem.

Age difference = 7 + 9 = 16 years.

B's age = (16 + 4) (3-1) = 10 years old, A's age = 10 + 16 = 26 years old.

The grandfather's age is 12 times the age of the grandson, 78 (12+1)=6, the grandson is 6 years old, the grandfather is 72 years old;

7+9）+4=20；20 2=10 is the age of B, and A is 10*3-4=26

Grandchildren's age = 78 (12+1) = 6 years old

Grandpa age = 78-6 = 72 years.

Age difference = 7 + 9 = 16 years.

B's age = (16 + 4) (3-1) = 10 years old, A's age = 10 + 16 = 26 years old.

The age of the grandfather and the grandson is 78 years old, and the age of the grandson is replaced by the number of months, which is exactly the same as the age of the grandfather. How old are grandsons and grandfathers?

78 (12+1) = 6 grandchildren.

78-6 = 72 (years old) grandfather.

A's age is 4 years younger than B's 3 times the age, A 7 years ago and B are the same age 9 years later, how old are A and B this year? 7+9=16 (years).

16+4) (3-1) = 10 (years) B.

10 + 16 = 26 (years) A.

The average age of Mom and Dad is 33 years old, 27 years older than Xiaoliang27 = 18

That is, when Xiaoliang was 18 years old, the average age of his parents was 45 years old, which was twice that of Xiaoliang. The sum of the ages of parents is 90 years old, which is 5 times that of Xiaoliang.

The answer is 12 years later.

(35+31-6x5) (5-2)=36 3=12 yearsIf you don't understand anything about this question, you can ask, if you are satisfied, remember to adopt, if there are other questions, please adopt this question, click to ask me for help, it is not easy to answer the question, please understand, thank you.

Good luck with your studies!

Solution: There are x people.

8*8+(x-8)*6+96=10*6+(x-10)*1064+6x-48+96=60+10x-1004x=152x=38

A: There are 38 people, 340 apples.

Solution: If there are x people, then there are [10 6+(x-10) 10] apples.

8×8+(x-8)×6+96=10×6+(x-10)×1064+6x-48+96=60+10x-1004x=152x=38

A: There are 38 people and 340 apples.

The number of tickets of 40 yuan and 50 yuan is equal, and the tickets of 40 yuan and 50 yuan can be regarded as (40 + 50) 2 (50) yuan, assuming that these 400 tickets are all 45 yuan, and 45 400 18000 yuan should be paid, so that 18000-15600 2400 (yuan) is less than the actual payment, so the 30 yuan tickets have 2400 (45-30) 160 (pieces), so 40 yuan and 50 yuan each have (400-160) 2 120 (pieces).

Because the number of tickets for 40 and 50 is equal, the number of tickets for 40 and 50 yuan is equivalent to the same number of tickets sold for 45 yuan.

If you calculate the average ticket price, you will find that it is 39 yuan. 39-30 = 9, 45-39 = 6, so a 30 yuan ticket: a 45 yuan ticket = 6:9 = 2:3

Therefore, there are a total of 400 * 2 5 = 160 land tickets for 30 yuan, and the remaining 240 are 120 tickets, 40 tickets, 120 tickets, and 50 tickets.

40+50=3×30.

In other words, it can be seen that all the tickets sold are 30 yuan, and they are just different colors.

So how many of these "30 yuan" tickets were sold? That's 520 shots.

And only 1 4 of them are really 30 tickets, so 130 tickets for 30 yuan are sold. So 40 50 dollars each.

520-130) 2=195 sheets.

Problems that require a column of equations are placed in primary school, and the hypothetical method is always used.

Let's say a $30 ticket is 0.

40 * 200 + 50 * 200 = 18000 That is, the assumed income is 18000-15600=2400 The income is 2400 less than the hypothetical, which is caused by the existence of 30 yuan.

Since 40 and 50 are the same, the number of 30 is even.

For every 2 more tickets of 30 yuan, there is one less 40 and one less 50, which can reduce the income by 30 yuan.

80*2=160 That is, 30 yuan has 160, 40 has 120, and 50 has 120.

The title is wrong.,The last time it was given to the old man.,It should also be 32 copper plates backwards.。。。

After walking 5 back and forth, there are 32 on the body, just for the old man.

After walking 4 round-trips, the body has: 32 2 + 32 = 48 to complete 3 round-trips, and the body has: 48 2 + 32 = 56 to complete 2 round-trips, and the body has:

56 2 + 32 = 60 to complete 1 round trip, the body has: 60 2 + 32 = 62 The original has: 62 2 = 31.

It is more troublesome not to use the equation, but to extrapolate,

There is something wrong with the numbers in this question! In the end, there were 31 copper plates left on the wealth fan, which was an odd number. Every time he walked back and forth, the number of copper plates on his body would double, no matter how many copper plates he originally had, when he came back, the number of copper plates on his body should be an even number, and the 32 copper plates he gave the old man each time were also even numbers, even - even or even, and finally, his body should not be an odd number (31).

Unless there is still a half-copper plate to say.

There are 110 apples.

There are twice as many apples that have been eaten as pears, and in fact the number of apples is 4 times less than that of pears2

pieces, then the remaining 40 plus 2 is the multiple difference, that is, 42 is a multiple of the number of pears. Therefore, there are 28 pears. The next thing is good...

60 3 = 20 sentences.

95-20 = 75 sentences.

12 3 = 4 sentences of sail laughter.

75 (4+1) = 15 sentences.

1,000 words of silver defeated text).

95-15=80 sentences.

Don't forget to give the best answer.

Total area - the area of the four corners = the area of the sides of the 6 small squares multiplied by 1, and the small rectangle in the middle can be seen as 2 small squares.

So it can be done directly.

16-1x4=12

Because the width is 1 cm, the side of the small square is 2 1 = 2 cm, so that the side length of the small rectangle is 4 and 2

The sides of the large elongation are 6 and 4

With 24 8 = 3 times.

Shadow area = 16, remove the four corners to get 12. The area corresponding to each side:

Long side: 2*12 2 3=4, the side length is equal to 4.

Short side: 1*12 2 3=2, the side length is equal to 2.

Small rectangle area: 4*2=8.

The area of the large rectangle is (16+8) 8=3 times the area of the small rectangle.

It will be simpler to use equations, and if you don't use equations, the column formula is not easy to understand, so first find the width of the small rectangle.

The length of a small rectangle is 2*2=4

The area of a small rectangle is 2*4=8

The area of the large rectangle is 8+16=24

So the area of the large rectangle is 3 times that of the small rectangle.

3 times. Make auxiliary lines, extend the length and width of the small rectangle, remove the four corners (4 square centimeters) and leave four small rectangles. Because the length of the small rectangle is twice as long as the width, the four small rectangles can be divided into 6 parts, and the length and width of the small rectangle can be found by calculating the area of each part.

After that it's simple.

Not necessarily. Oral arithmetic. ）