High School Super Easy Math Problems, High School Math Super Easy

Daughter-in-law, I think.

That's how it should be, you get the idea.

Forget it, I'll repeat it again.

x+1=u x=u-1

Substitution. f(u)=(u-1)2+3（u-1）+1u2+u-1

Actually, I guess you haven't figured this out yet.

The correspondence of functions.

f: Represents a rule, like this.

F (Xiao Si): Xiao Si is my daughter-in-law.

At this time, the f stands for my daughter-in-law in parentheses.

So. Ditto.

f(u)=u2+u-1

The f in this: means that the square of the letter or number in parentheses plus this number, and then subtract 1 daughter-in-law, do you understand?

That's right, f(x)=x 2+1 and f(y)=y 2+1 are a function, just think about it.

Because the function has nothing to do with the letters used, the variables of this function can be represented by x, and can also be represented by u, x and u can be used universally, both represent a variable, and the front x+1 and the back x are not the same, x+1 is a subfunction of f(x) understand it slowly, mainly rely on your own understanding, read more, do more questions, don't drill the horns, I wish you a happy study, come on (

I forgot all about high school math, I can't do it.

a+b=（0，x^2+1)

The abscissa is 0, which is the point on the y-axis, which is parallel to the y-axis.

So choose C

a+b=(0,1+x 2), which is infinite from the slope, i.e., a straight line perpendicular to the x-axis and parallel to the y-axis.

It should be c, because a+b=(0, x 2+1) is on the y-axis!

It can be seen that e1 = (a +b) a and e2 = (a +b) b

1/e1²+1/e2²=a²/(a²+b²)+b²/(a²+b²)=1

Therefore 1=1 e1 +1 e2 2 (e1e2)=e1e2 Trace 2 equal sign is obtained only when e1=e2= 2. ∴e1+e2≥2√(e1e2)≥2√2.

The number of equals is only obtained when e1 = e2 = Bi Nian 2.

e1+e2)min=2√2.

The distance from the focal point to the asymptote is always b

Prove. Asymptote equations.

y=+-bx/a

So bx+-ay=0

Focus (c, 0).

Distance from focus to asymptote = |bc|The quadratic root (A 2 + B 2) = bc c = b theorem is what I forgot.

The answer is 3.

Finding the Inverse Function The domain of the inverse function is the domain of the original function.

x=3y+3/2-2y

2-2y is not equal to 0

2 is not equal to 2y

Y is not the same as 1 to B

2x+3 is not equal to 0, x is not equal to three-half of the negative, how to calculate how not to equal -6...

You have to understand that the standard answer given by the reference book will be wrong.

The answer is b

No, such a conversion should be done.

f(2x+3)=3x+4=

So f(x)=

It's not x

If you want to change it to the form of f(x).

It is necessary to replace x into (x-3) 2

So f(x)=3(x-3) 2+4=

1) According to the induction formula, cos75 degrees = sin(90-75) degrees = sin15 degrees, (2) sin15cos75 = the square of sin15 (3), according to the square of double sinx = 1-cos2x, sin15 = positive and negative root numbers (cos30 + 1) 2 The last step can be calculated.

Turn 15 into 45 30

Turn 75 into 45+30

Forget it.

Integrative sum difference formula: sina*sinb=-1 2[cos(a+b)-cos(a-b)];

It can also be converted into sin(45-30)*cos(45+30) reuse and angle formulas.

Solution b: x=2 or x=3. Solution c: x=2 or x=-4

Because A intersects B≠ empty set, it means that A and B have the same.

A intersects c = empty set, indicating that a and c are not the same.

Assuming that a intersects b = 2, then a intersects c also = 2Off topic.

So, a crosses b = 3

Take x=3 into the equation of set a, and solve a.

a=5 or a=-2

Of course, it can't be done here, test.

Bring a=5 into equation a and solve x=2 or x=3. At this time, a crosses c=2, which is not in line with the topic. So give it up.

In summary, a=-2

What I said above is all explanation, if you write it on the paper, delete it yourself.

(x-1 2) 2=19-3 4*a 2x=1 2+root number (19-3 4*a 2).

or x=1 2-root number (19-3 4*a 2)19-3 4*a 2>=0

From b we get x=2 x=3

From c we get x=-4 x=2

A intersects b ≠ empty set, and a intersects c = empty set.

So 1 2 + root number (19-3 4*a 2) = 3 or 1 2 - root number (19-3 4*a 2) = 3 should be considered a no-brainer!

Finding b gives b=[2,3], and finding c gives c={2,-4} and a intersects b≠ empty set, and a intersects c = empty set.

So there must be 3 in a, bring x=3 in.

Target. The square of a-3a-10=0

A is 5 and -2