How to solve a one dimensional equation in this problem?

1) Set up a cooperation for x hours.

2 x = 22 9, shared 4 and 4 9 hours.

Let one shift do x hours alone first, and cooperate for 4-x hours.

x x = hours of co-op time.

1) It takes a total of x hours before and after.

1 x-2--- multiplied by 2+--=1

The second possibility.

2) Set up one shift to do x hours (2) Two shifts to work together for --- hours.

x 4-x 1/

Set up a shift of one hour to water x trees. Then the second shift is one hour to water the tree.

Plus the previous 2 hours for a total of 40-9 hours.

Question 2: Does four hours in the morning mean that it will be completed within four hours? The two classes have been working together the fastest, and the shortest time is 10-3 hours.

1 Set up for a total of x hours.

1／x＝40／9

2. Set one shift for y hours and two shifts for 4 hours.

1／y＝5/2

1) Assuming that the whole task volume is 1, the speed at which the first shift is completed alone is 1, and the speed at which the second shift is completed separately is 1 6.

After the two classes worked together for t hours, then: 1

1. Assuming that the speed of the ship in still water is x kilometers per hour, then:

x+3）×8=（x-3）×12

2. Assuming that x workers should be assigned to produce round iron sheets, then:

120×x=80×（42-x）×2

3. Assuming that the ordinary road section is x kilometers, then:

x÷60+3x÷100=

4. Assuming that the full pool water is 1, and the pool water can be filled x hours after opening the C pipe, then: ,1 6+1 8) 2+(1 6+1 8-1 9) x=1

In fact, these questions are very simple, if you figure out how the above formula came about, I believe you don't need to ask similar questions in the future.

The difference between the upper and lower numbers on the calendar is 7, and the difference between the left and right numbers is 1

Therefore, the largest number is greater than the smallest number, 1+7=8

Let the minimum number be x

then x+8=3x+2

x=3, so these 4 numbers are 3, 4, 10, 11

Their sum is 3 + 4 + 10 + 11 = 28

It takes x seconds to get through and carry the ants.

15x=600+150

15x=750

x=50The time it takes for the fire stealth train to completely pass through the tunnel is 50 seconds.

600+150) 15=750 15=50 seconds.

The time required is 50 seconds.

The time it takes for this train to completely pass through the tunnel is x seconds.

15x=600+150

There are x people planting trees.

then 10x+6=12x-6

Solution x=6, a total of 66 people.

Solve Question 1 first.

If the list price x list price sales profit is 50%, then the cost is.

x=200/3

Question 2. If there are x people in class A, then the male student in class A (x+1) 2, the female student (x-1) 2 can find the male student in class B (x+1) 2*(100 115) and the female student in class B (x-1) 2*(100 110).

then x+(x+1) 2*(100 115)+(x-1) 2*(100 110)=85

Solving the equation yields x=45

There are 40 people in Class B.

Question 9. Let the length of the first rectangle be x, then the width of x-2 and the length of the second rectangle will be (40 2 x-2(x-2)+6) 2, and the width will be (40 2 x-2(x-2)-6) 2

The following equation is obtained.

x-2)-(40 2 x-2(x-2)-6) 2=2 The solution gives x=23 3 and the width is 17 3

The second rectangle is 29 3 long and 11 3 wide

The area and the sum of the 710 9

Send me the answer in my email.

Solution: Let x meet after the small eggplant front.

36+48）x+162=288

x = A: The distance between the two cars is 288km.

Let one person complete the amount of start and slow in one day as x

9 * 14*x=3/5

x=1/210

Set up resistant socks to increase the Y people Chang side excited.

y+9）* 4 *1/210=1- 3/5y=12

Solution: (1) Set up x students per minute at the main gate and Y students per minute at the side gate.

x+y=200

2(x+2y)=560 The solution is x=120, y=80(2) is safe.

The school has a total of 45 x 8 x 4 = 1440 (people) and 200 students can pass through every minute when opening a main gate and a side door at the same time.

Four gates, two main entrances and two side gates, can pass through 400 students per minute.

In case of emergency, 4 doors can pass in 5 minutes: 400 x 5 = 2000 (person), greater than 1440

Comply with safety.

On average, x students pass through one main gate and Y students through one side gate every minute.

x+y=200

x+2y=560÷2

The solution yields x=120 and y=80

2. Set up to pass Z students every minute to meet safety regulations.

z*（1-20%）*5=45*8*4

z=3602x+2y=400＞z

Therefore, whether the 4 gates built comply with safety regulations.