Unary one dimensional equation problem 25 formulas have answers to urgent!!!

1）(3x+1)^2=7

Solution: (3x+1) 2=7 (3x+1) 2=7 3x+1= 7 (be careful not to lose the solution) x= ( 7-1) 3

2）9x^2-24x+16=11

Solution: 9x 2-24x+16=11 (3x-4) 2=11 3x-4= 11 x= ( 11+4) 3 The solution of the original equation is x1=( 11+4) 3 x2=(- 11+4) 3

3) (x+3)(x-6)=-8

Solution: (x+3)(x-6)=-8 Simplified x 2-3x-10=0 (the left side of the equation is a quadratic trinomial, and the right side is zero) (x-5)(x+2)=0 (the left side of the equation is factored) x-5=0 or x+2=0 (converted into two unary linear equations) x1=5, x2=-2 is the solution of the original equation.

4) 2x^2+3x=0

Solution: 2x 2+3x=0 x(2x+3)=0 (factor the left side of the equation by the common factor method) x=0 or 2x+3=0 (convert into two unary equations) x1=0, x2=-3 2 is the solution of the original equation. Note:

Some students tend to lose the solution of x=0 when doing this kind of problem, and should remember that there are two solutions to a quadratic equation.

5) 6x 2+5x-50=0 (elective).

Solution: 6x2+5x-50=0 (2x-5)(3x+10)=0 (pay special attention to the symbols when factoring the cross multiplication) 2x-5=0 or 3x+10=0 x1=5 2, x2=-10 3 is the solution of the original equation.

6) x 2-4x+4=0 (elective).

Solution: x 2-4x+4 =0 ( 4 can be decomposed into 2 ·2 , this problem can be factored by factoring) (x-2) (x-2 )=0 x1=2 , x2=2 is the solution of the original equation.

7)（x-2）^2=4（2x+3）^2

Untie. (x-2)^2-4(2x+3)^2=0. [x-2+2(2x+3)][x-2-2(2x+3)=0.

5x+4)(-5x-8)=0.

x1=-4/5, x2=-8/5

8）y^2+2√2y-4=0

Solution(y+2) 2-2-4=0

y+ √2)^2=6.

y+√2=√6.

y=-√2±√6.

y1=-√2+√6；

y2=-√2-√6.

9）（x+1）^2-3（x+1)+2=0

solution (x+1-1)(x+1-2)=0.

x(x-1)=0.

x1=0,x2=1.

10) x 2+2ax-3a 2=0 (a is constant).

solution (x+3a)(x-a)=0.

x1=-3a,x2=a.

From the meaning of the title, a2+3a+1=0 can be converted into a2(a2+3a+1)-2a(a2+3a+1)-(a2+3a+1)+6=6

.(x+2) 2=16 x+2=+-4 x=-6 and x=22 3x 2-2x-1=0 (3x+1)x(x-1)=0 x=-1 3 x=1

The rest is counted with a universal formula! When b 2-4ac>=0, the equation has a solution so x=[-b+sqrt(b 2-4ac)] 2a

The other x=[-b-sqrt(b 2-4ac)] 2a, where b 2-4ac is under the root number! That is, sqrt lookout.

/2(x+2)ˆ2-8=0

1/2(x+2)ˆ2=8

x+2)ˆ2=16

x+2=+4 or -4

x = 2 or -6

Count yourself for something similar.

Such a simple question can be calculated by yourself. /

8: Set: The original amount of coal is x?

x－15）÷（15÷3×1／2）＋3－10＝x÷（15÷3）（x－15）×2／5－7＝x／5

2x／5－6－7＝x／5

x／5＝13

x 6510: Tree planting this year x(1 20)11: Which of the following statements is incorrect: c

14: The two-digit numbers are: b and c

20: The ** price needs to be a9% off. (1 8 ) 1 20 ) 23: Set: Apple bought x kilograms?

4x＋（5－x）×3＝17

4x＋15－3x＝17

x 2 pears 5 2 3 kg.