Questions about electric fields, questions about electric fields

The relationship between induction and kinesis you mentioned, in a word, is that inductive generation is generated by the change of b, and kinesis is generated by the motion v of the conductor. In addition, there are very few (almost none) questions in the college entrance examination that need to be considered in vivid life. Of course, if you come across it, that is also simple, it is to put the two formulas together and find the sum of the last two.

To be honest, I've seen two or three times in the counseling books I bought. All in all, it is absolutely impossible to be wrong to see the change of b with emotion, and the change with v with motion.

As for this problem, there is no current in the loop, but there is a constant velocity v, so that the total magnetic flux remains constant. Let the length of the metal rod l, then b=b0l (l+vt).

I'll still tell you how to deal with it together, and the questions that you generally have to consider will clearly tell you that B is changing, and acceleration A. If b=kt, the acceleration is a, and the conductor rod is l, then the induced part e= t=kt· (1at 2)·l。 The animated part is e=blv (I'm not cumbersome, it's still that method).

Finally, it is a matter of finding the sum of the two.

Of course, if it is disgusting, there will be a condition that says what is the resistance per meter...

The electric field of the charge does not depend on motion

The term electric field is very new, but you think too much.

The generation of the magnetic field can be perfectly explained by Maxwell's equations. A changing electric field produces a magnetic field, which in turn produces an electric field.

A magnetic field is generated around the changing electric field.

An electric field is generated around the changing magnetic field.

This is Maxwell's theory of electromagnetic fields.

The so-called electrostatic field is not to think that something is not moving, just that it does not change with time. It's not that he moves, it's that he changes over time!

Let the angles between OA and AB and the electric field strength E of the thin wires be and , the tension forces in OA and AB are F1 and F2 respectively, and the electric field forces on A and B are 3F and F respectively. First, list the force equilibrium equations for the two balls

B: Horizontal f2*cos = f, vertical f2*sin =mg, compare the two formulas, tg = f mg

A: Horizontal F1*Cos +F2*Cos =3F, Vertical F1SIN =MG+F2*Sin, substituting the above two formulas into these two formulas, we get Tan =F mg so =, that is, the answer C is correct.

The helium nucleus has two units of positive charge that is twice that of a proton w=uq w is equal so the ratio of proton to particle voltage should be equal to 2:1

1 2mv = uq v equal v=(2uq) m proton mass is 1 helium nucleus mass 4 bring in and pour out voltage ratio of 1:2

Because the ball is positively charged, the field strength is to the right, so the electric field force f=qe, the square basis excitation to the right sail sock electric field force decomposes into a parallel inclined plane direction of the component force f1=f*cos perpendicular inclined plane The component of the front state direction f2=f*sin Because the gravity of the ball is decomposed into a parallel inclined plane.

The answer given upstairs is already very good, it's really amazing, the picture is well done, and I learned.

The work done by the electric field force on the object is zero, and the electric field force only works between b and c, because it is a uniform electric field, the electric field force remains unchanged and fast, and the electric force carried by the block is also unchanged, so the electric field force f changes in magnitude. The motion of the block in the electric field is zero from b--c--b, i.e., d=0

By the formula w=fd, so the work done by the electric field force is also zero. Of course, you can think about it separately and divide it into two stages: b--c and c--b. The result is the same.

Definitely not, in an electric field a charged object must be subjected to at least two forces, gravity and electric field. And the electric field force also does work on the object, and it also changes the velocity of the object, which in turn changes the mechanical energy of the object, so it is obviously wrong to say that the amount of change in mechanical energy is completely caused by the work done by gravity.

Mechanical energy refers to the energy possessed by an object due to mechanical motion. Including gravitational potential energy, elastic potential energy, and kinetic energy. Electric potential energy does not fall under the category of mechanical energy.

The change in mechanical energy is the work done by forces other than gravity and elasticity. The sub-concept is unclear.

Mechanical energy is a general term for kinetic energy and potential energy.

Not necessarily. Because there is a change in electric potential energy, mechanical energy is not conserved.

Electric potential energy is not mechanical energy.

Mechanical energy is only kinetic energy, gravitational potential energy, and elastic potential energy.

The embodiment of energy: Ming Sui such as a plate capacitor has an electrostatic field, to produce this electric field is required energy, for example, Huai Nao needs to separate the charge on the plate of the energy required.

Embodiment of mass: For example, photons do not have static mass, but have moving mass, and the electric field is a part of the electromagnetic field, and the photon is the electromagnetic field.

It is not reflected in the electrostatic field and needs to be moved.

The acceleration of ball A is the sum of the acceleration caused by gravity and the electric field force, and the size is g+qe 5m b and c balls are not charged, not affected by the electric field force, and the acceleration is equal to the gravitational acceleration g