The hypotenuse of a right angled triangle is 6, and the difference between the two right angled side

Let the two right-angled sides of the right-angled triangle be a and b respectively, if a>b and the difference between the two right-angled sides is 1, then a=b+1

Pythagorean theorem: a 2 + b 2 = 6 2, b 2 + 2b + 1 + b 2 = 36, so 2 (b 2 + b) = 35

Triangle area = 1 2 ab = 1 2 (b+1)b = 1 2 (b 2 + b).

So the triangle area = 1 2 35 2 = 35 4 looks!

Let the short side be x and the long side be x+1

Rule. x^2+(x+1)^2=6^2

2x^2+2x+1=36

2x^2+2x-35=0

x=( -1 + root(71)) 2

x+1= ( 1 + root number(71) ) 2

Area = x(x+1) 2=(71-1) 8=70 8=35 4

Solution: Let the two right-angled sides have no a, b

Rule. a-b=1

a²+b²=36

a-1)²=a²-2ab+b²=1

So. 2ab=36-1=35

1/2ab=35/4

So the area of the triangle is 35 4

Let the two right-angled sides be x, x+1 respectively

x²+(x+1)²=6²

2x²+2x=35

Area = x(x+1) 2=

For a right-angled triangle, the difference between the two right-angled sides is only equal to 6, and the hypotenuse is 12 to find the area of the right-angled triangle.

Let the length of the three sides of the right-angled triangle Lu Minhao be a, b, and c from small to large, then according to the meaning of the title, it can be seen that c=12, a+6=b, and find the area of the triangle s=1 2ab. Then the system of equations can be obtained from the Pythagorean theorem (a 2 + b 2 = 144, a + 6 = b), the two equations are substituted into the one formula to get a 2 + 6a-54 = 0, the discriminant formula is greater than 0 so there is a solution in the range of real numbers, and then the first morning line - two equations 2 can be obtained 2ab = 108, so the area of the right triangle s = 1 2ab = 27

Let the two right-angled sides be x and y respectively

Then: x+y=6, xy=6, the required hypotenuse square x square + y square limb mu pei mu x square + 2xy + y square 2xy = (x+y) square 2xy 6 square 2 6 36 12 24

So hypotenuse 2 6

Let a right-angled side length be x,x*(x-5)] round rock 2=7

Therefore, x is 7, so the length of the hypotenuse of the cavity mill is: 53 under the root number

a+b=7

a^2+b^2=25

a+b) 2=a 2+b 2+2ab=49, so 2ab=24

Area=,6,It should be 6. Because the hypotenuse is suspicious of the 5....The two right-angled sides and are Qin Shen 7...It should be 3 and 4According to the Goeda mountain stock theorem.

It's easier to fill in the blanks. Otherwise, the process must be listed.

Something I learned in the last year. Forget all about it. ,1,3*4 2=6,0, it is known that the hypotenuse of a right-angled triangle is 5, and the sum of two right-angled sides is 7, find its area.

Can you write the process more clearly? That's a big question.

a^2+b^2=25

a+b=7 gives ab=12

then a, b are the equations.

x^2-7x+12=0

It is 3, 4, 10, and if the straight corner edge is x, then the other straight angle edge is 7-x, and the equation can be obtained from the Pythagorean theorem.

x square + (x-7) square = 25

Solve 3 and 4, 2,

Let the right-angled sides be a and b, then a-b=3, square it to get a squared-2ab+b squared=9

again a square + b square = c square = 81 so 2ab = 81 - 9 = 72 so 1 2ab = 18 i.e. the area is 18

The hypotenuse is 5, assuming that the two right-angled sides are a and b, from the title we can get a+b=7, ab=12, the right triangle is known to seep, the sum of squares of the right-angled sides is equal to the square of the hypotenuse, so the square of c = (a+b) of the square difference friend - 2ab = 49-24 = 25, and the hypotenuse of the ridge is 5

Let the two right-angled sides be a and b

Because the area is 6, ab2 = 6

So ab = 12

again a + b = 7

Both sides are squared:

a² +b² +2ab = 49

a² +b² +24 = 49

a² +b² = 25

And according to the Pythagorean theorem, get:

Hypotenuse = (a +b).

Let the two right-angled sides be a b

a+b=71/2a*b=6

a=3 b=4 or a=4 b=3

The square of the hypotenuse = the square of 3 + the square of 4.

Hypotenuse = 5

Two right-angled edges x,y

x+y=7xy=6

x(7-x)=6

x^2-7x+6=0

x-6)(x-1)=0

x-6=0x=6x-1=0

x=1y=7-x=7-6=1

Hypotenuse 2=6 2+1 2=37

Hypotenuse = root number 37