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Anonymous users2024-02-071) When the total length of the two springs is equal to the sum of the original lengths of the two springs, it means that the deformation of the upper and lower springs is equal, and the deformation of the K1 light spring can be obtained by using the equilibrium condition of the force to obtain the equation.
2) The force analysis is carried out on the whole, and the elongation of the original upper spring is obtained according to the equilibrium condition of the common point force, and then the elongation of the current upper spring is subtracted as the distance of M1 moving upward;
3) The force analysis of M2 is carried out, and the magnitude of the force of the lower spring on M1 and M2 is equal according to the condition of the interaction force, and the magnitude of the thrust f is obtained according to the equilibrium condition of the common point force
Answer: Solution: (1) From the meaning of the question, the deformation of the upper and lower springs is equal, and the force analysis of M1 is shown in the following figure
From the equilibrium condition of the common point force, it can be obtained:
k1x+k2x=m1g, then the deformation of k1 light spring x=
m1gk1+k2
2) The overall force analysis when the force f that does not apply the upward slowly lifting M2 is shown in the figure below
From the equilibrium condition of the common point force, it can be obtained:
k1x1=(m1+m2)g, then the original deformation of k1 light spring x1=
m1+m2)g
k1 then the distance that m1 moves up x=x1-x=
m1+m2)gk1m1g
k1+k23) to perform a force analysis on m2, as shown in the figure below
From the equilibrium condition of the common point force, the magnitude of the thrust f is
f=m2g+k2x=m2g+
k2m1gk1+k2
Answer: (1) The deformation of K1 light spring is.
m1gk1+k2
2) The distance of m1 is .
m1+m2)gk1m1g
k1+k23) thrust f is of the magnitude of m2g+
k2m1gk1+k2
Comments: This question examines the calculation of spring elastic force, and the key is to use the integral method and isolation method to analyze the force of the object and the balance condition of the common point force, and it should be noted that when the total length of the two springs is equal to the sum of the original lengths of the two springs, the elongation of the upper spring and the compression of the lower spring are equal
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Anonymous users2024-02-06Answer: (1) The deformation of K1 light spring is.
m1gk1+k2
2) The distance of m1 is .
m1+m2)gk1m1g
k1+k23) thrust f is of the magnitude of m2g+
k2m1gk1+k2
Comments: This question examines the calculation of spring elastic force, and the key is to use the integral method and isolation method to analyze the force of the object and the balance condition of the common point force, and it should be noted that when the total length of the two springs is equal to the sum of the original lengths of the two springs, the elongation of the upper spring and the compression of the lower spring are equal
1) When the total length of the two springs is equal to the sum of the original lengths of the two springs, it means that the deformation of the upper and lower springs is equal, and the deformation of the K1 light spring can be obtained by using the equilibrium condition of the force to obtain the equation.
2) The force analysis is carried out on the whole, and the elongation of the original upper spring is obtained according to the equilibrium condition of the common point force, and then the elongation of the current upper spring is subtracted as the distance of M1 moving upward;
3) The force analysis of M2 is carried out, and the magnitude of the force of the lower spring on M1 and M2 is equal according to the condition of the interaction force, and the magnitude of the thrust f is obtained according to the equilibrium condition of the common point force
Answer: Solution: (1) From the meaning of the question, the deformation of the upper and lower springs is equal, and the force analysis of M1 is shown in the following figure
From the equilibrium condition of the common point force, it can be obtained:
k1x+k2x=m1g, then the deformation of k1 light spring x=
m1gk1+k2
2) The overall force analysis when the force f that does not apply the upward slowly lifting M2 is shown in the figure below
From the equilibrium condition of the common point force, it can be obtained:
k1x1=(m1+m2)g, then the original deformation of k1 light spring x1=
m1+m2)g
k1 then the distance that m1 moves up x=x1-x=
m1+m2)gk1m1g
k1+k23) to perform a force analysis on m2, as shown in the figure below
From the equilibrium condition of the common point force, the magnitude of the thrust f is
f=m2g+k2x=m2g+
k2m1gk1+k2
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Anonymous users2024-02-05solution, (1) the area of the footprint m = v
Area s= g=f=ps=(2) If standing upright, the area is one foot when calculating the pressure. The results of the speculation will be different.
Good luck with your progress.
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Anonymous users2024-02-0480× 80-19=61
56 yuan for store A and 61 yuan for store B.
Store A is more saving, saving 5 yuan.
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Anonymous users2024-02-03If you approve of me, please register in time, if you approve of me, please click the [for satisfaction] button in time.
Friends who ask questions on their mobile phones can comment on [Satisfied] in the upper right corner of the client.
Yours is my motivation to move forward.
o( o, remember to praise the disadvantages and things, and help each other.
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Anonymous users2024-02-02The first question 4 and the denominator 4 are about the minute, and the remaining numerator and denominator are left respectively, so as to get 6/5, and 1 and 1 2 after the approximation
1) CD AM CB AN CDA= ABC AC BISECTED MAN DAC= CAN=120° 2=60° AC=AC, SO ACD ACB AD=AB In rt adc, c=30° then AC=2AD and AD=AB, so AC=AD+AD=AD+AB (2) Do ce am CF an from (1) to get ace ACF then CE=CF......dac= caf=60° because e= f=90°......adc+∠cde=180° ∠adc+∠abc=180° ∴cde=∠abc……3 Ced CFB dc=bc from 1 2 3 Conclusion 1 is established AE=AC 2 in CEA, then AD=AE-DE=AC 2 - DE In the same way, AB=AF+FB=AC2 + BF is obtained from CED CFB BF=DE AD+AB=AC 2 +AC 2=AC Conclusion 2 is true, I played for half an hour, I was tired, and I did it myself.
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