Regarding geostationary satellite speed, what is the difference between geostationary satellite orbi

Updated on military 2024-04-04
12 answers
  1. Anonymous users2024-02-07

    First, the cosmic velocity is both the minimum launch velocity and the maximum orbital velocity, and the geostationary satellite is farther away from the ground, and the farther the distance is known from the law of gravitation, the smaller the orbiting velocity, so the geostationary satellite orbiting velocity is smaller. Because the geostationary satellite is synchronized with the rotation of the earth and is also moving in a circle around the earth, the gravitational force provides the centripetal force, so it does not fall.

  2. Anonymous users2024-02-06

    The reason why the velocity of the synchronous satellite is smaller than the first cosmic velocity, you think like this: the gravitational potential energy of the satellite will increase when it lifts off, and it will have to overcome the gravitational potential energy to do work, and at this time it only has kinetic energy, and after rising into the air, part of its kinetic energy on the ground is converted into the same amount of gravitational potential energy, so its speed is small!

  3. Anonymous users2024-02-05

    The first cosmic velocity is equal to the maximum orbital velocity and is also approximately equal to the orbital velocity of the near-Earth satellite. According to the law of gravitation, the larger the orbital radius, the smaller the orbital velocity, and the geostationary satellite is about 36,000 kilometers away from the Earth.

    Because the gravitational force experienced by the geostationary satellite is used to provide it with circular motion, it will not fall.

  4. Anonymous users2024-02-04

    The first cosmic velocity is both the minimum launch velocity.

    Again, the maximum orbital speed.

    The gravitational force acts as a centripetal force.

    GMM MV party.

    r square r shows that with the increase of the orbit radius, the linear velocity of the satellite in orbit decreases. Therefore, the first cosmic velocity is the maximum orbital velocity.

  5. Anonymous users2024-02-03

    If the gravitational potential energy of the satellite is to increase, it has to overcome the gravitational potential energy to do work, and at this time it only has kinetic energy, and after it rises into the air, part of its kinetic energy on the ground is converted into the same amount of gravitational potential energy, so its speed is small!

  6. Anonymous users2024-02-02

    According to the gravitational theorem, it is estimated that there is a gravitational equilibrium zone in space about 36,000 kilometers from the earth, which is often called "geostationary satellite geostationary orbit". Satellites rotate with the Earth as if they were "fixed" by the Earth.

  7. Anonymous users2024-02-01

    The first cosmic velocity refers to the radius of the Earth.

    Satellite radius

  8. Anonymous users2024-01-31

    1. The speed is different. The launch speed of the synchronous satellite must be greater than the first cosmic velocity and less than the second cosmic velocity, but the orbital velocity can be lower.

    2. The distance from the earth is different. When the launch speed of the synchronous satellite is large, it is in the earth's atmosphere, and when the synchronous satellite orbits the speed, the satellite is in the outer space of the earth.

    3. The centripetal force is different. The centripetal force of the geostationary satellite orbiting velocity is greater than the centripetal force of the launch velocity of the geostationary satellite.

  9. Anonymous users2024-01-30

    The linear velocities of geostationary satellite B and near-Earth satellite A are V1 and V2 respectivelyAngular velocity.

    w1、w2.The centripetal acceleration of period t1 and t2 a1 and a2 is v1 > v2 because v = root number gm r

    Because W = root number GM R cubic so W2 > W1 period t = 360 degrees divided by W

    So. t1>t2

    centripetal acceleration.

    Due to gravitational pull.

    Provides centripetal force.

    The central celestial body is the same.

    So a1=a2

    First cosmic velocity The near-Earth satellite velocity ≠ the geostationary satellite velocity.

    Please, thank you

  10. Anonymous users2024-01-29

    The period of the geostationary satellite is t = 24 hours, and the angular velocity is w. According to t=2 w, w. Let the radius of the earth r, and the satellite macro call the height h from the ground. Given r, find h.

    As follows: according to the law of gravitation gmm (r+h) = mv (r + h), i.e. v = gm (r + h).

    Because on earth mg = gmm r, i.e. gr = gm.

    1、v=gr/(r+h)

    2、v*t=2π(r+h)

    Synoptic to obtain v and height h

    Angular velocity = Angular velocity of rotation of the Earth = 2 (24*3600).

    The altitude of the geosynchronous satellite from the equator is about 36,000 kilometers, and the linear velocity is about kilometers per second. Angular velocity.

  11. Anonymous users2024-01-28

    Geostationary satellites, especially geosynchronous satellites, are a type of satellite that has the same orbital period as the Earth's rotation period, that is, they orbit the Earth once a day. This allows them to remain fixed over specific locations on the earth's surface.

    The earth rotates once a day, which is 360 degrees, so the speed of the earth's rotation angle is 360 degrees. Converted to more commonly used units, we can convert the slide to radian seconds.

    1 day = 24 hours = 1440 minutes = 86400 seconds.

    So, the angle of rotation of the earth per second is 360 86400 degree seconds.

    Then we need to convert the angle to radians. Since 360 degrees is equal to 2 radians, we can convert it like this:

    360 86400) *2 360) =2 86400 radian seconds.

    This is the angular velocity of the Earth's rotation and is also the angular velocity of the geostationary satellite, which is approximately equal to 10 -5 radian seconds.

  12. Anonymous users2024-01-27

    Satellites are gravity to provide centripetal force, which can be solved by substitute formulas, but the radius of the operation of geostationary satellites and near-Earth satellites is different. But the object that rotates with the earth is also supported by the earth, so it is not the gravitational force that provides the centripetal force, and the centripetal acceleration a=4 2r t can be found from the period.

    Centripetal acceleration of a geosynchronous satellite: g=gm (rh) 2=.

    1) For stationary satellites with the same orbital radius, their acceleration magnitude is equal. But the direction is definitely different, so the acceleration of geosynchronous satellites is not the same.

    2) Acceleration is a vector quantity, even if the magnitude is the same, but when the direction is different, their acceleration is not the same.

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