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Mass fraction of sodium sulfate in Na2SO4 + BACl2 = BaSO4 + 2NaCl original mixture
Grams of precipitate produced per 5 grams of barium chloride.
Na2SO4 + BACL2 = BaSO4 + 2NaClX = g (BACl2).
Mass fraction of unknown barium chloride solution =
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The maximum mass of Baso4 is i.e. Description SO42- Max, so Na2SO4 is.
m (sodium sulfate) =
Mass fraction = the first two BACL2 reactions are completely taken and calculated as a random one.
According to the second part, baso4 corresponds to ba2+, then bacl2 is.
Mass Fraction = (.
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Do the math yourself. It's been too long since I calculated.
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1. If A is a solid, the chemical formula of A is S (sulfur).
Chemical formula of DB: Cu + 2H2SO4 (concentrated) == Heating == CuSO4 + SO2 + 2H2O
2. If a is the chemical formula N2 (nitrogen) of gas a
d b: 3cu + 8hnO3 (dilute) == 3cu(no3)2 + 2NO + 4H2O
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1 If A is a solid A, the chemical formula of A: S, B: SO2, C: SO3, D: H2SO4D B: Cu + 2H2SO4 (concentrated) = = CuSO4 + SO2 + 2H2O
2 If a is the chemical formula of gas a: N2, B: NO, C: NO2, D: HNO3D B: 3Cu + 8HNO3 (dilute) = = 3Cu (NO3) 2 + 2NO + 4H2O
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From the title, it can be obtained: before the reaction, O2 is a gas, and its coefficient is 3, and after the reaction, the two products are gases, and the sum of the coefficients is also 3, so the gas volume remains unchanged.
1.Because the volume of gas before and after the reaction remains unchanged, only O2 is a gas before the reaction, so the volume of O2 is 672ml;
2.Conservation of mass: mass of the product = density * volume = and the mass of xy2 can be found = total mass - mass of oxygen (amount of oxygen substance * relative molecular mass) =
xy2~3o2x 3
x=76g/mol;
After this revision, each step is a detailed step
The last question, which belongs to thinking according to the periodic table, can know that XY2 is carbon disulfide, that is, CS2, which is exactly in line with the mass ratio of 3:16.
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