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Program Problem 1: include
int main(void)
printf("I am a college student");
return 0;
Program Problem 2: include
int f(int x)
return x * x + 2 * x + 1;
int main(void)
printf("f(5) = %d", f(5));
return 0;
For reference, you still have to write it yourself. C is not difficult to get started.
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Student, I just learned C language, this is not very difficult programming! I suggest you think about it, it should be possible to do it, if you look at other people's ** now, the later exams are very dangerous, and it is more difficult to take the second level! For the final exam, let's take a look at the book now!
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#include
int main(void)
printf("I am a college student");
return 0;
Annotate your own name, professional class, and other information here.
#include
float f(float i)
return (i+1)*(i+1);
int main(void)
printf("f(x)=x*x+2*x+1");
printf("f(5)=%f",f(5));
return 0;
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First of all, columnar. 1) x+y+z = 8, x is the number of 10 rings, y is the number of 7 rings, z is the number of 5 rings.
In columnar form. 2) 10*x+7*y+5*z=53, from 1) formula, x=8-y-z;
Bring in 2) got.
80-10*y-10*z+7*y+5*z = 53, and finally simplified to obtain 3*y+5*z = 27, z=(27-3*y) 5;
Okay, now we can program.
int x, y, z ;
int ret ;
Guess that y is between 0 and 8 based on the proposal.
for ( y=0;y<=8;y++)
I haven't compiled it, but that's the idea.
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Let them be A, B, and C rings, respectively.
then there is a+b+c=8
10a+7b+5c=53
where a<5, b<8, c<11 (this should not be explained) include
void main()
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Write your thoughts. int x,y,z;x, y, and z are 10, 7, and 5 rings, respectively.
int total=8;
for(x=0;x<=total;x++)for(y=0;y<=total-x;y++)for(z=0;z<=total-x-y;z++)
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Landlord, do you change to: define(x,y) (x>y?x:y) Give it a try.
Change this place a bit, and the output is correct. Here's why.
Why, the specific reasons have not been analyzed.
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It should be: 353
bSince there are no curly braces after if, this one only has t=a; This statement is t=a under this judgment;
The value of t after this sentence is executed is 3
a=c;The value of a after this sentence is executed is 5
c=t;The value of c after this sentence is executed is 3
aSince there are no curly braces after if, t=b; In this judgment, but a=5, b=4, c=3, because the condition is not satisfied, so t=b; Not executed.
b=a;The value of b after this sentence is executed is 5
a=t;The value of a after this sentence is executed is 3
Therefore, the final output is 353
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#include
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