C Language Programming Questions Quick!! It s simple .

#include

using namespace std;

int main()

float j=-1;

float sum=0;

for(int i=1;i<=10;i++)j=j*(-1);

sum=sum+j/i;

cout<<"1-1/2+1/3-1/4……+1 9-1 10 and yes"I guess your problem must be a mistake in the use of division.

int int: quotient of integers.

int%int: integer remainder.

float int, float float, int float: get the result of the float type.

The password is 5 digits, which is the least common multiple of and 104.

Hello for your inquiry; Ok, here are some C language practice questions for your reference:1Enter two integers a and b, and output their sum, difference, product, quotient, and remainder.

2.Enter a positive integer n and output all odd numbers from 1 to n. 3.

Enter a positive integer n to determine if it is prime (a prime number is a number that is only divisible by 1 and itself). 4.Enter a positive integer n and output its factorial (n!).

5.Enter a string to count the number of uppercase letters, lowercase letters, digits, and other characters.

6.Enter a string that converts all lowercase letters into uppercase letters. 7.

Enter a string to determine if it's a palindrome string (a palindrome string is a string that is read both forward and backwards). 8.Enter a string of characters sorted in lexicographic order from smallest to largest.

9.Enter an array of elements sorted from smallest to largest. 10.

Enter a positive integer n to output the first n terms of the Fibonacci sequence (the Fibonacci number refers to the division of the good one.

Answer: A Error correction.

int p;

scanf("%d",&p);

int *p,a;

p=&a;scanf("%d",p);

Both of the above are fine.

Analysis: The compiler does not initialize the "local variable", the global variable is initialized to 0

Answer A cannot be used because it is not initialized before using the pointer variable p.

2.Answer B Error correction.

int *s,k;

s=&k;*s=100;

Pass a, both are pointers that are not initialized before use.

3.Answer C is correct.

4.Answer d is incorrect.

s=p;is wrong.

This is because s is an integer pointer and p is a character pointer. Two variables with different pointer types cannot be assigned.

I hope mine was helpful to you and it was a pleasure to learn and discuss C programming with you.

The pointers of A and B are null pointers, and D cannot be implicitly converted in C++, and an error will be reported.

CD is fine, AB is used without allocating memory.

Only C should be correct, and the last 2 lines of D have memory out-of-bounds issues.