Ask a simple math problem in the first year of junior high school as follows

m-n) to the power of 3 times (n-m) to the 2nd power = (m-n) to the 3rd power times (m-n) to the 2nd power = (m-n) to the 5th power.

m-n and n-m are inverse numbers to each other, and if they are to the power of even, they are unchanged. If it's odd power, it's the other way around.

m-n）³*n-m）²

m³-n³）（n²-m²）

m³（n²-m²）-n³（n²-m²）

m n -m to the 5th power) - n to the fifth power + n m m (m-n -m -n to the fifth power + n to the 5th power) = m (m-n -m).

Multiply the index outside the brackets, remove the brackets, add the index to the base, and then come up with the common letter and the lowest index, and merge the same kind to get the final result.

Even powers can be considered as absolute values, and the order does not matter.

Add a negative sign in front of the odd times to change the fire

It can be converted by the opposite number, n-m=-(m-n), the original formula =-(m-n) 5

Symbols can be multiplied by adding symbols for different symbols, and the same is true for factorization, which I myself love for factoring.

n-m) to the power of 2 is equal to the power of (m-n) to the power of 5 (m-n) to solve according to the binomial.

It's not like it's not the first year of junior high school, it should be the second year of junior high school, the product of the multiplication.

It can be changed to the 3rd power of (m-n) multiplied by the 2nd power of [-(m-n)].

Dishonesty.

Set the purchase price of the commodity to be X yuan.

The original selling price is (1+50%)x=

The selling price is 20% off.

Xiao Ming pays 168 yuan, then.

Find x=140

So the purchase price is 140 yuan.

Merchants earn 168-140 = 28 yuan, not 8 yuan.

The merchant is not honest.

What a bounty......

Add some ......

For the sake of my hard work......

List price: 168 yuan).

Purchase price: 210 yuan).

168-140 = 28 (yuan) ≠ 8 (yuan).

Answer: It means that the store is not honest.

1 Because the sum of the inner angles of a polygon is divisible by 180, and the remainder of 2000 divided by 180 is 20, this outer angle is 20 degrees.

2 Since the sum of the outer angles of the polygon is equal to 360 degrees, it can be set to be an n-sided shape, then there is 180(n-2)=4*360

Solution: n=10

So this is a 10-sided shape.

3 The sum of the outer angles of the polygon is 360 degrees, and the sum of the inner angles is divisible by 180, so the sum of all angles is also divisible by 180, and the integer part of 1350 divided by 180 is 7, so the sum of all the angles of this polygon is 180*7

If this is an n-side, then there is.

180（n-2）+360=180*7

180n=180*7

n=7 so it is a 7-sided shape.

4 Because the sum of the inner angles of a polygon can be integer by 180, and each inner angle is less than 180 degrees, the sum of the inner angles of this polygon is greater than 2750 and divisible by 180, and the integer part of 2750 divided by 180 is 15, so this inner angle is 180*16-2750 130 degrees.

1: Let the number of sides be n, because the outer angle is between 0 and 180, so 2000-180<(n-2)*180<2000, the solution is 109 9, so n=13, and the outer angle = 2000-(13-2)*180=20

2: Obtained from the sum of the outer angles = 360: (n-2)*180=4*360 to obtain n=10

3:"All corners"It means that all the inner angles are the same as 1 q, n = 9, if"All corners"refers to the inner and outer angles, then subtract the sum of the outer angles.

There are (1350-360)-180< (n-2)*180<1350-360 solution 4: since the inner angle is between 0 and 180, so 2750<(n-2)*180<2750+180, solution: 311 18 solution: n=18, inner angle = (18-2)*180-2750=130

1.Because 2000° = 180° * 11 + 20 ° = 180 ° * (13-2) + 20 °

So the number of sides of this polygon is 13, and the number of outer angles is 20° 180 + 2=10

3.Because 1350° = 180° * 7 + 90 ° = 180 ° * (9-2) + 90°

So the number of sides of this polygon is 9

4.Because 2750° = 180° * 15 + 50 ° = 180 ° * 15 + 180 ° - 130 ° = 180 ° * 16-130 °

Therefore, the number of internal angles is 130°

Baby, you're too little.

1.The square of x and the cube of y lead take.

2.-ab cube.

3.-1 2ABC is the first side of the square.

4.c. The number of items can be excited, and you don't need to look at them. That is, the exponent of b to the power of m-1 b is four, then m=4

Or the exponent of -3x is 1, as long as the exponent of y is 4.

One-third minus one-half absolute plus one-quarter minus one-third absolute plus one-fifth minus one-quarter absolute plus. Add 1/2010 minus 1/2009 in absolute.

The number in the small circle b is: 26 0

The number in the small circle c is: 22/7 10 and 2/11 The number in the large circle A is: minus five.

The great circle a represents: a set of rational numbers.

Answer: The triangle ABC is an isosceles triangle.

Reason: Since ad=be, ab is common, and two perpendicular angles, then the triangle adb and the triangle bea are congruent.

So, angular abc = angular bac

Therefore, it can be obtained: the triangle ABC is an isosceles triangle.

Isosceles triangle.

From ad=be ab and two perpendicular angles, the triangle adb and the triangle bea are congruent, so the angle abc = angle bac so the triangle abc is an isosceles triangle.

Isosceles triangle. Because 1 2*bc*ad=1 2*ac*be, and ad=be, therefore ac=bc

All are isosceles triangles.

Isosceles triangle. BC=AC, because the area of the triangle s=BC*AD*1 2=AC*BE*1 2, because AD=BE, so BC=AC, and the length of AB cannot be judged, so it is only an isosceles triangle

Isosceles triangle.

Triangular area = bcxad 2 = acxbe 2

So ac=bc

P.S. And because ac=bc, the angle c is an acute angle. So the triangle is also an acute triangle.

Isosceles triangle.

Because, ad=be, angular adc=angular bec=90 degrees. Angle ECB = Angle DCA, so the triangle ADC is all equal to the triangle BEC

So ac=bc, i.e. the original triangle is an isosceles triangle.

The isosceles triangle ac=bc because the triangle area is ac*be 2 or bc*ad 2 because ad=be, so bc=ac, so it is an isosceles triangle.

Isosceles triangle, because the area is certain, since the height is equal, the bottom is also equal, that is, bc=ac