Strange difficult math problems! Find a solution to a somewhat difficult math problem, thank you!

1) 1, xy can take 1, -3 or -1,32, xy can take 2,2; -2，-2 ；1，4 ；-1,-42)1, y= x, y=-2x, draw a picture, see clearly.

2. Because a+b<0, ab<0, one of ab is less than zero.

If a<0, b>0, because a+b<0, then -a>b, so |a|>|b|

If a>0, b<0, because a+b<0, then -b>a, so |a|<|b|

1) Knowing that x and y are both integers, find the value of x+y according to the following conditions.

x + y = ±2

x + y = 4 or 5

2) Compare sizes.

with -2a 2If a+b<0, ab<0, find |a|with |b|size.

If a=0, a = -2a

If a=0, a = -2a

If a=0, a = -2a

Because ab<0, one of a and b is less than 0

If a<0, b>0

a| = -a, |b| = b

0 > a + b = -|a| +b|

So |a| >b|

If a<0, b>0

a| = a, |b| = -b

0 > a + b = |a| -b|

So |a|

,x=-1,y=3,x+y=2,x=-3,y=1,x+y=-2,x=1,y=4, x+y=5

x=2,y=2,x+y=4

2) Compare sizes.

with -2a a>-2a, a>0), a<-2a, a<0)a=-2a, (a=0).

2.If a+b<0, ab<0, find |a|with |b|size.

a>0,b<0 ,|a|<|b|

a<0,b>0 ,|a|>|b|

1 2+1 3+1 9+1 18

1 2+1 3+1 9+1 19+1 Sicong Na 342

There are many answers. This Zheng Que is one of them.

1:5*RMB.

15 yuan" 9 yuan, indicating that the water must be more than 5 square meters.

15-9=6 yuan.

6 2 = 3 squares.

It shows that the monthly water consumption of Xiaohong's family is at least 5 + 3 = 8 cubic meters of water.

2: Set the required decoration fee as:

x based on the idea of the question (building a mathematical model).

40,000 > = 100x + 2000 + 200 * 10 (move items) 36,000 > = 10x

x<=3600

I'm absolutely right.

If you don't understand anything, ask me thank you.

1.The sum of three consecutive odd numbers is m, and the smallest odd number is (m3-2) When m=45, the smallest odd number is (13

2.If a = 5b (not zero), then the greatest common factor of a and 5b is (b) the least common multiple (a).

3.Cut a cube into two identical cuboids, one of which has a surface area fraction of the original cube and a fraction of the volume of the original cube?

Answer: The surface area of one of the cuboids is 2 3 of the original cube and the volume is 1 2 of the original cube.

2 times, 3 times, 4 times.

Takeaway: If you want to find out which of the three balls (ABC) is not qualified, assuming that you will first take A and B ratios:

As long as you are lucky for 1 time, A=B, then C is unqualified, and if you are unlucky, you need to be 2 times, A>B(AC, A is unqualified.

It's easy to scale up to 10 :

The first case: D is not qualified. (Of course, I only learned later, or take ABC first), A=B, B=C, make sure that ABC is qualified.

Then determine which of the 3 in a group is unqualified, and it will take 1-2 times, and the final possible situation is +2; That is, the time.

I found that I wrote it wrong, and in order to mislead everyone, I still sent out the wrong ideas, and everyone came to find fault.

But the final answer is .

Set a ticket to reduce the price by X yuan, and there were originally audience Y people.

So the original total income is 50y, and the reduced income is (50-x) 2y=50y (1+1 5).

So x=20

So the price of a ticket is reduced by 20 yuan.

Assuming that the original 100 audiences, after the price reduction, it is 100 2 = 200 people, and the original income is 100 50 = 5000 yuan.

After the price reduction, the income is 5000 (1+1 5)=6000 yuan, and the price of a ticket is reduced by 50-6000 200 = 20 yuan.

Reduced by 20 yuan.

When the ticket is 30 and 50 yuan, the audience n, the income m, the ticket price after the price is reduced xim = 50 * n type *

So 2x=60n

x = 30 The reduced fare is 30

The price was reduced by 20 yuan.

Ahem, let's say this is a fifth-grade math problem, I thought it was difficult to see the problem.

First, divide 10 into 33

31 Quadruple The first and the second 3 If they are equal, take one and weigh the second as they are, and if they are also equal, then the last 1 is not qualified (this is twice); If it is not equal, then there is a disqualified one in the third 3, and divide the 3 into 1

11, that is, find the unqualified (this is three times).

If the first and the second 3 are not equal, take the first and the third to weigh and equal, then there is an unqualified one in the second, and weigh it again to find the unqualified ball (called three times); If the first and the third are not equal, then there is a disqualification in the first one, and then weigh it again to find the unqualified ball (called three times).

So, at least three times.

It seems that there is a kind of writing that draws pictures, but I forgot it.

Typing tired,,If you don't take it.。 The tile will go. Dirt.

Solution: Set up a total of x books in this batch, each pack of y copies.

From the meaning of the question, 11 18x=14y+40, both sides are divided by 11 18, x=252 11y+720 11, and, x=(14+10)y=24y, the unary equation is obtained, 252 11y+720 11=24y, and the solution is y=60, x=24y=24*60=1440

A: There are 1,440 books in this batch.

(1) The sum of 5 consecutive integers is 55, which are respectively ).

2) The sum of 5 consecutive odd numbers is 45, which are respectively ).

3) The sum of 5 consecutive even numbers is 50, which are ), 12), (14).

4) The sum of 6 consecutive is 57, which are respectively ).

It's too simple. Divide the first three questions by 5 to get the middle number!

Fourth question: I don't know what you mean??

Let's give you a logic question, it's interesting, it's not difficult to figure it out, and it's tangled if you want to make it up Good luck!

There are 3 red hats and 2 white hats. Three of these hats were placed on the heads of A, B, and C. Each of the three men could only see the hats on the heads of the other two, but they could not see the hats on their heads, and they did not know the color of the remaining two hats.

Question A: "What color hat are you wearing?" A said:

I don't know. Then, after thinking about it with the same question, he said, "I don't know."

Finally, he asked, "I know what color my hat is." "Of course, C was made after listening to A and B.

I ask you: What color is the hat that C is wearing?

The first question is 4 Bring x=(a-1) into the root number (x+4a) + under the root number (x-4a+8) and then make the recipe You can sort out the root number under (a+1) + under the root number (a-3) Because -1 a 3 so go to the root number The answer is 4

1.= under the root number (x+2) + under the root number (a-3) = a + 1-3 + a = 4

3 in 2 to the power b, 4 to the power c = 12 What does this sentence mean. Is there a mistake?