The problem of chemical pressure, to detail the process, thank you!

1 standard atmosphere can support the meter water column.

First of all, atmospheric pressure is atmospheric pressure, and "how high can a standard atmosphere support a water column" means that the pressure generated by a high water column is equivalent to the size of one standard atmosphere.

First of all, it is necessary to know that 1 standard atmosphere is kilopascals, and kilopascals = 101325 Newtons square meters. That is to say, the pressure per square meter is 101325 Newton, which is considered 1 atmosphere, and the unit of pressure is converted to mass 101325 which is equivalent to about 10,339 kilograms.

If the mass of 10,339 kilograms is water, then its volume is obviously cubic meters, because the bottom area is one square meter, so if you need cubic meters of water, its height must be meters high.

1 standard atmosphere is equal to the pressure produced by a column of 760 mm of mercury.

P mercury = mercury gh

This is the value of 1 standard atmosphere.

According to the formula p water = water gh a standard atmospheric pressure gets:

The height of the water column is. h = p water g

The maximum scramble pressure is one foot for the slow core grinding p=mg s=>

Therefore, it is not possible to pass through the mold safely.

g = pressure of 10 people: 500 160 x 10 4=

so, can't pass.

The gravity of 500N is divided by the area of the two feet to get the pressure, and the known pressure can be compared, greater than the past, I am in the car, did not calculate the imitation tomb, prepare the liquid Qi himself to calculate, the key is the method.

Because when walking, at least one foot is used to dig and prepare the foot, and the limb is traveled.

p=500 (160*10 (-4))=31250pa>, so you can't walk through.

The horizontal desktop area is just a shot of remorse, and I am already a sophomore in high school.

The steps are as follows: Rush forward and return.

Solution: (1) F water pressure = mg = sun and hunger Europe (that is, the letter of density) vg = 15n, s insole = v h =, p inside = f s = 20pa

2)f=（m＋m）g＝20n

p＝f／s＝10pa

The height difference between the mercury column above the CD column in the left tube is smaller than that of the original two tubes, and the gas pressure in the tube is P=P0- P, so it can be seen that the gas pressure in the left tube increases and the volume decreases. Option D

5. Note that the pressure inside the confined gas is equal everywhere. Although the mercury column of the right tube remains the same, the gas pressure remains the same, and the height difference between the two tubes remains the same. Therefore, choose C

1) The height of the column in the A tube is equal to 0.

2) Gas p1 = 75 + (35-10) = 100, v1 = 30p2 = p0 - p p0, you can set the length of pipe b gas to 40. Find p2Namely.

100*30=p2*40 P2=75, which is exactly equal to atmospheric pressure.

Therefore, all the mercury in tube B is returned to the horizontal tube, and the length of gas in tube B is 40cm

A must be wrong The thin sticks are suspended in three cups of liquid, and the buoyancy is equal to the gravitational force, and because the gravitational force is equal, the buoyancy is also equal.

B is right. Because f float = density of liquid v and g, the greater the density, the smaller the volume of water discharged by the object.

C is right. Because p = density * gh, from the above analysis, c density is the largest, h g is equal respectively, so c pair.

D is right. It can be regarded as a calculation of the pressure of the solid, p=f s, s are all equal, analyzed by b, c is the most dense, and v is the same, so c g is maximum, f pressure is maximum, p is maximum, d pair.

aa.Buoyancy = the gravitational force of the water is discharged, so the larger the volume immersed in the water, the greater the float f, a wrong bThe greater the density, the smaller the volume of the object submerged in the water (no matter how small, it will float on it), b to the density *gh, from the above analysis, c is the most dense, so c is to d

The larger the liquid g, the greater the pressure of f, the analysis of b, c density is the largest, and v is the largest, so g is the maximum, f pressure is maximum, p is maximum, and d is paired.

aThe water surface level does not change before and after the ice melts.

If the ice contains other substances that are less dense than water, the water surface will remain the same after melting.

If the density of the substances contained in the ice is greater than that of water, the liquid level will drop after melting.

Because ice is less dense than water, the water surface height does not change.

a p2=p1

The point is that the water surface height does not change before and after the ice melts. This is because the volume of water that becomes when the ice melts is the same as the volume of the part of the ice that is immersed in the water.

When the pressure is increased, why does the concentration of the gas (i.e., the side with the largest gas volume) increase so much that the sum of the measured numbers is larger?

In the equilibrium constant formula, the number of measurements is used as the power number, when the pressure is increased, the concentration changes the same, but the power number is different, the larger number of measurements increases more, and the equilibrium moves in the direction of the small number of measurements.

Increasing or decreasing the pressure, why is the side with a large gas volume affected so much???

The same is true of the above.

1. When the pressure increases, the side with a large gas volume is compressed (the molecular spacing is large, the compressible space is large, and the intermolecular force is relatively small).

2 The same goes for it.

Avogadro's Law.

The reaction always proceeds in the direction of weakening change.