How to make p nitrobenzaldehyde from benzaldehyde

Generally, this is not done, because the direct nitrification of benzaldehyde is very easy to oxidize, the yield is very low, and the main thing obtained is m-nitrobenzaldehyde. Nitrobenzaldehyde, on the other hand, is easily obtained by oxidation of nitrotoluene.

Ruixiang. in concentrated alkali such as sodium hydroxide.

Under the action, the cannizzaro reaction occurs to produce benzyl alcohol.

and sodium benzoate. This is a disproportionation reaction in which one molecule of benzoic acid is reduced and one molecule of formaldehyde is oxidized.

The mechanism is that the base precedes the carbonyl group of benzoformaldehyde.

Nucleophilic addition takes place and then the hydrogen on the carbon is transferred to the carbonyl carbon of formaldehyde with a pair of electrons in the form of a hydrogen negative inner ion. So after the disproportionation reaction occurs, benzaldehyde is reduced to form benzyl alcohol, and formaldehyde is oxidized to form formic acid.

The cannizzaro reaction is an intermolecular redox reaction of aldehydes without active hydrogen under the action of a strong base.

An organic disproportionation reaction that produces one molecule of carboxylic acid and one molecule of alcohol.

Italian chemist Stanislau Cannizzaro first discovered this reaction in 1895 by treating benzaldehyde with plant ash to obtain benzoic acid and benzyl alcohol, which is called Cannizaro reaction.

Aliphatic aldehydes, aromatic aldehydes or heterocyclic aldehydes that do not contain -hydrogen atoms undergo oxidation and reduction reactions at the same time under the action of concentrated alkalis, resulting in the organic disproportionation reaction of the corresponding carboxylic acids (carboxylates in alkaline solution) and alcohols.

What does benzene, formaldehyde and formaldehyde produce by reaction How to excitimate? I don't understand chemistry, so I don't understand the situation, I can't talk nonsense here, if you don't understand, you don't understand.

The precursor of o-nitroaniline can be o-dinitrobenzene, and there are also aniline. Starting from benzene, nitrobenzene is obtained, and o-dinitrobenzene is obtained, which is achievable; It is also not difficult to synthesize aniline from benzene.

Aniline is first acylated with acetic acid to acetanilide to prevent the amino group from being destroyed during nitrification. Nitrate acetanilide with cold (0-5 degrees Celsius) nitrosulfur mixed acid to obtain p-nitroacetanilide. If the temperature is too high, more ortho-nitrification products will be formed.

p-nitroacetanilide is hydrolyzed to obtain p-nitroaniline.

First of all, we need to prepare nitrobenzene.

Nitrobenzene reacts with acyl chloride to form amides.

Then it is heated with a mixture of concentrated nitric acid and concentrated sulfuric acid to make the nitro selective only in the upper alignment (the steric hindrance of the adjacent position is larger).

Then add sodium hydroxide to hydrolyze to prepare p-nitroaniline.

I won't write the equation, I hope mine is helpful to you.

Summary. When nitrobenzene (C6H5NO2) and formaldehyde (CH2O) react, they form phenylacetaldehyde (C8H9NO2) and water (H2O). This reaction is often referred to as the condensation reaction of nitrobenzene with formaldehyde.

The reaction equation is as follows: C6H5NO2 + CH2O ->C8H9NO2 + H2OThis equation represents the chemical change between the reactant and the product. In this equation, C6H5NO2 stands for nitrobenzene, CH2O stands for formaldehyde, C8H9NO2 stands for phenylacetaldehyde, and H2O stands for water.

During the reaction, the nitro group (NO2) in nitrobenzene reacts with the methyl group (CH3) in formaldehyde to form a new chemical bond that connects the benzene ring and the methyl group, thus forming phenylacetaldehyde. At the same time, water molecules are also released. This reaction is usually carried out in the presence of an appropriate catalyst to facilitate the reaction.

It is important to note that reaction conditions (e.g., temperature, pressure, catalyst, etc.) may have an impact on the reaction rate and product selectivity, and the specific reaction conditions can be adjusted according to the experimental needs.

The reaction between nitrobenzene and formaldehyde is the synthesis of phenylacetaldehyde. The reaction equation is as follows: C6H5NO2 + CH2O ->C8H9NO2 + H2O, where C6H5NO2 represents nitrate, CH2O represents formaldehyde, C8H9NO2 represents phenylacetaldehyde, and H2O represents water.

You've done a great job! Can you elaborate on that?

When nitrobenzene (C6H5NO2) and formaldehyde (CH2O) react, they form phenylacetaldehyde (C8H9NO2) and water (H2O). This reaction is often referred to as the condensation reaction of nitrobenzene with formaldehyde. The reaction equation is as follows:

The equation C6H5NO2 + CH2O ->C8H9NO2 + H2O represents the chemical change between the reactant and the product. In this equation, C6H5NO2 represents nitrobenzene, CH2O represents formaldehyde, C8H9NO2 represents phenylacetaldehyde, and H2O represents water. During the reaction, the nitro group (NO2) in nitrobenzene reacts with the methyl group (CH3) in formaldehyde to form a chemical bond that connects the benzene ring and the methyl group, thus generating phenylacetaldehyde.

At the same time, water molecules are also released. This reaction is usually carried out in the presence of an appropriate catalyst to facilitate the reaction. It should be noted that the reaction conditions (e.g., temperature, pressure, catalyst, etc.) may have an impact on the reaction rate and product selectivity, and the specific reaction conditions can be adjusted according to the experimental needs.

Summary. The p-nitro group is greater than the o-nitro group.

The p-nitro group is greater than the o-nitro group.

Hey, that's the room. Meta-activity is also small.

Para-activity is maximum.