The specific heat capacity of the third year of physics, the specific heat capacity of the third yea

What does LZ want to express?

Why is the specific heat capacity of water higher than that of alcohol?

Why is water cooler than alcohol?

In the middle school context, it is simply defined as:

The amount of heat absorbed (or the amount of heat released by a decrease1 of a unit mass) of a substance as its temperature increases1 is called the specific heat capacity of that substance. The unit is j (kg·) which is read as joule per kilogram of Celsius. The unit of specific heat capacity is also often written as j (kg·k), which is read as "joules per kilogram of kei".

The specific heat capacity of water looks like 4200, and the specific heat capacity of alcohol is 2400 units j (kg· ) When alcohol and water of the same mass are heated for the same amount of time, the temperature of water is lower than that of alcohol because the specific heat capacity of water is greater than that of alcohol.

When absorbing the same amount of heat, the temperature rises less than the heat capacity is higher.

q=c*m*(t1-t2)

Among them, the large C (T1-T2) is smaller, and the two things T2 are the same, and the water of T1 is lower than that of alcohol.

q=cm(t2-t1)

Equal to m and q, the specific heat capacity c is inversely proportional to the temperature increase (t2-t1), the alcohol temperature is higher than the water temperature, and of course the specific heat capacity of water is higher than the alcohol temperature.

This is because the specific heat capacity of water is higher (the specific heat capacity of alcohol is only multiplied by 10 cubic joules).

The temperature of natural water is higher than that of alcohol, provided that the heating time is the same and the quality is the same.

In the case of equal mass, equal heat is absorbed or released, and the specific heat capacity is inversely proportional to the amount of temperature change.

q=c*m*(t1-t2)

In the case of equal mass, the specific heat capacity of the same heat absorption and temperature change is smaller.

q=cm t can be known to the cubic j(kg.) of q=Celsius) * 1kg * (80-20) = cubic power.

Q = Q water + Q pot = to the third power J(kg.).degrees Celsius) * 2 kg * (80-20) + cubic j (kg.)Celsius) * 1kg * (80-20) = cubic power.

Just remember the formula! Hope it helps!

Iron pot 1kg of the cubic j(kg.Celsius.

Total iron pot + water.

1kg of cubic j(kg.).Celsius + 2 kg to the third power j (kg.).Celsius) think carefully, find the correspondence, and consider it separately, and you can't memorize formulas when learning physics. Hehe.

Heat absorbed by iron q1 = cm (end of t - beginning of t) = = j

Heat absorbed by water Q2 = cm (end of t - beginning of t) = = j

In total, Q total = Q1 + Q2 = J

The specific heat capacity of copper is three times that of lead, copper and iron of equal mass absorb the same heat, and the ratio of their increased temperature is: (1:3), and the mass of B is one-third of that of A, and the temperature of A is twice that of B, then the ratio of heat absorbed by A and B is (6:

1. Just substitute the ratio into the formula.

The ratio of the increase in temperature is: (1:3).

The ratio of heat absorbed is (6:1).

1) M copper: M iron (It's iron!) ) = 3:1, m copper = m iron, q iron = q copper, according to q copper = c copper m copper t q iron = c iron m iron t; Simplified to 1:3.

2) C A = C B, 3m A = M B, T A = 2 t B, according to Q A = C A M A T A Q B = C B M B T B, the ratio is 6:1

The heat capacity of B is larger than A, let the water temperature be t, the temperature heated by A and B is T0, put A into the water and the water temperature rises to T1, and then put B into the water The water temperature is T2. then there are: t1-t=10, t2-t1=10, ca*m*(t0-t1)=cb*m*(t0-t2); Because T2 > T1, CB > CA.

Calorie calculation formula: q=cm t

Q: The amount of heat absorbed (or released).

c: Specific heat capacity (of water).

m: Quality. t: Varying temperature.

It can be seen that q is the same (heat absorbed by water).

In the same way, A first cools down to the same temperature as water, which is set to x (Celsius), and then B raises the water by 10 degrees Celsius, then the temperature of B is 10+x (Celsius).

At the beginning, the temperature of AB is equal, but the temperature of B drops less than that of A, then the heat is calculated according to the formula: Q=CMT

c=q m t, the smaller t, the larger c is. Therefore, the specific heat capacity size b>a

Analysis: It can be assumed that the copper ball is solid, depending on how much heat it should absorb, and more than 24j is hollow, which is equal to solid.

Process: Assuming the copper ball is solid, the mass of the ball:

M = PV = to endothermy: q cm (t-t0) = >24j

In other words, the ball has not absorbed enough heat to rise to 20 degrees Celsius, indicating that it is hollow.

Answer: B hollow.

Please click here, you can ask if you don't know.

Solution When the copper ball is solid, Q=Q= can be known by obtaining his t from Q=cm'c) · cubic meter * cubic meter * (20'c-10'c) = >24j Because q is positive with m and v, it is hollow. So choose B

If you calculate how much heat it will absorb if it is all copper (that is, solid), it will absorb so much heat, if it is greater than 24, it means that it should be hollow, because the mass is not as large as 1 cubic centimeter, so the heat absorption will be smaller than 1m, and the specific answer is judged according to the calculated results.

m copper ball = 3kg m 3 1cm 3 = obtained by q sucking = cm (t-t0) = q sucking c(t-t0) = 24j because m copper ball "m

So for the hollow.

The mass of the copper ball is first calculated according to the formula of heat absorption, and then the density of the copper ball is calculated by using the density formula, and the conclusion can be drawn by comparing it with the density of copper.

；The temperature of 1kg of water increases1 The heat absorbed is;; Water.

specific heat capacity; j (kg· ) the mass of the object; kg；terminal temperature; initial temperature; ℃。

, heat, specific heat capacity, joules per kilogram, j (kg· )1). 2) The water temperature is increased by 1 The heat absorbed is 4200j, (look up the book, I can't remember), and the meaning can refer to the meaning of water. Slow.

1) The specific heat capacity of water is large, q cm t, when the mass and temperature change are the same, the water absorbs (releases) the most heat;

2) The specific heat capacity of sand and gravel and soil is much smaller than that of water, and when the heat is absorbed (released) the same amount, the temperature change of sand and soil of the same mass is much faster than that of water.

3) The temperature difference between day and night in coastal areas is small.

Activity 3: q cm t

1. Q CM T 4200 group stool 168000J2, Q CM T 4200 5 (100 80) 420000J

Sun Sleepy Specific heat capacity Coul per kilogram of Celsius j (kg.).℃

2.The difference is slow.

Known: C Water = ; m water = 100g =; t1=14℃；t2=38℃；m iron = 200g =; t3=98℃

Seeking: C iron = ?kg

Solution: Q suction = C water M water (T2-T1) =

If all the heat released by the hot iron is absorbed by the water and there is no heat loss, then Q suction = Q release:

Q suction = q discharge = C iron M iron (T3-T2).

C iron = q suck [m iron (T3-T2)] ==

Answer: The specific heat capacity of a metal block is.

According to the heat emitted by the metal is equal to the heat absorbed by the water: C1M1ΔT1=C2M2ΔT2

c1*200*（98-38）=

c1= c°