Several math age problems synchronous growth .

1.The daughter is x years old, and the mother is 35-x years old.

35+5-x=4（x+5）=4x+20

x = 4 daughters are 4 years old and mothers are 31 years old.

2.Set for x years.

43-x=4（13-x）=52-4x

x=33.Set for x years.

38+x=3(x+10)=3x+30

x=not equal to 54

So it can be seen that Xiao Ming is 3 years old this year.

My sister is 5 years old.

Parental age sum = 69-5-3 = 61

Suppose the mother is x years old and the father is x + 1 years old.

x+x+1=61

So the mother is 30 years old.

My father was 31 years old.

1. Let the mother be x years old this year: (x+5) (35-x)=4 to obtain: x=27, so this year the mother is 27 and the daughter is 8 years old.

2. (43-x) (13-x)=4, we get: x=3So three years ago the mother was 4 times older than the son.

3, (38+x) (10+x)=3, yielding: x=4

1。Mother x daughter y

x+y=35

x+5=4(y+5) gives x=30 y=5 30+1=312Is it that the father is 4 times older than the son? If so, let it be 43-x=4 (13-x) before x to get x=33

Is it 3 times the age of a father to a son? If so, 38+x=3(10+x).

x=4 Father 31

First question: 31 4

2 3 Ask ......... I don't know if I have a relationship with my mother

35+2 5) (4+1)=9 Female: 9-5=4 Female: 35-4=3143-13) (4-1)=10 13-10=3 years ago.

38-10) (3-1) = 14 14-10 = 4 years later.

69-3-5=61 (61+1) 2=31 years.

Solution: She Xiaoguang is x years old this year.

Grandpa is 73 years old.

When Grandpa was 85 years old, Xiaoguang was X+ (85-73) in age

Daddy's age is 2 (x+(85-73)).

This year, Grandpa is 73 years old.

Dad's age is 2 (x+(85-73)))-85-73) and Xiaoguang's age is x

When Xiaoguang is 4 years old, the time will be pushed forward x-4 years.

Grandpa's age is 73- (x-4).

Dad's age is 2 (x+(85-73))-85-73)-(x-4), and grandpa is 2 times older than Dad.

73-（x-4）=2（2（x+（85-73））-85-73）-（x-4））

73-x+4=2(2x+24-12-x+4)77-x=2(x+16)

77-x=2x+32

3x=45x=15

Only four years old means that Xiao Guangxian is older than four years old. So.

Xiaoguang is 15 years old.

Method 1: Let B's original age be x, y years ago, then.

B this year: x+y

C this year: 2x+y

A this year: 17+y

So: x+y+2x+y+17+y = 1133x +3y = 96

x +y = 32

That is, B's age this year is 32 years old.

Method two x 2x 38

17 y 2y

x－2x＝－x＝17－y

2x－38＝y－2y＝－y

x＝7y＝24

That is, a given year is 17 24 48 years old.

Added to a total of 89 years.

113 89) divided by 3 8

So B is 24 8 32 years old.

A x B y C z a year ago x-a=17x+y+z=113

x-a=17

2(y-a)=z-a derives x=2y-z+17 to bring back the first equation.

(2y-z+17)+y+z=113 to solve y=32That is, B is 32 years old.