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1. The difference between the two cargo locations is 78-42 36
After transporting the same difference, it is still 36, and now the difference is twice that of the second location, and 36 2 18 is the number of the second location.
Then 42-18 24 24 is the quantity of each of the two locations.
The speed ratio of two people is 2:3, which is 200 seconds for A to run two laps, and B to run three laps, and the two meet on the starting line
3. The total area is 60*30 1800
Half is 1800 2 900
Rubbing a circle is to subtract the length and width of the 2 blackboards, and the area of the remaining rectangle is 900 wide
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Each 24 meets each 160 and 240 meters respectively.
So, the fifth encounter is at the beginning.
Think for yourself why you don't use 30-10*2
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1. Shetu pulls away the x box, then: 78-x=3(42-x)[Note here.]"2 times more", that is, 3 times].
Solution: x=24
2.Let it run for x seconds, then: 6x-4x=400k, k=1,2,3....
Solution: When k takes 1, x has a minimum value of 200That is, it took 200 seconds for them to meet for the first time.
3.If the width is xcm, then: 60*30=(60-10)*(30-x)*2 solve the problem by yourself.
In this problem, it is easier to solve the area of the part that has not been erased, i.e., (60-10)*(30-x)].
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Each 24 meets each 160 and 240 meters respectively.
So, the fifth encounter is at the beginning.
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Each 24 meets each 160 and 240 meters respectively.
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I am a 6th grader.
Glad to help you...
4.Three out of ten.
12/2=6 12*6+12*6+12*12=4887.The age difference remains the same: +4=30 years.
If the son is one-third of the mother's, then their difference is two-thirds, 30 2 = 15 years 15-5 = 10 years.
10.Equation: Solution: Let the skipping rope be xyuan, the soccer ball is 34+x, and the money y yuan is 30*(x+34)=y
30x+34*x=y
x=2,y=1080
Answer: Buy 15, 270 with skipping rope... It's more appropriate.
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1.When the height of a cuboid is reduced by 2 cm, the surface area is reduced by 48 square centimeters, making it a cuboid. The volume of this cube is (216) cubic centimeters.
2.A cube with a volume of 64 cubic centimeters was cut from a six-centimeter-long cuboid, and the surface area of the cuboid turned out to be (128) square centimeters.
3.Some money is used to buy fruits, you can buy 4 kg of oranges and 5 kg of apples, or 2 kg of oranges and 8 kg of apples, if you buy all this money for apples, you can buy apples (11) kg in total.
4.A simplest fraction, if the numerator plus one equals two-fifths; If the numerator minus one equals one-fifth, the simplest fraction would be (three-tenths).
The following application questions don't help you do it, and the points are too few, and you have to calculate the formula.
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(1)216
2) 128 (square centimeters).
3) Buy 11 kg of apples in full.
One. 72/6=12 12/2=6 12*6+12*6+12*12=488
Two. 4+26=30
Three. The daughter's age this year should be 35 7 = 5 years old.
After X years, the mother's age is exactly three times that of her daughter.
3*(5+x)=35+x
Solve x=10
Four. (12-5)*9+5=72
Five. Set up a school to come up with x dollars.
1/30x-1/540x=34
The solution is x=1080
I've been thinking about it for a long time, and I hope it can be adopted).
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, set dad: y mom: y-4 me: y-30y+1-(y-30+1)=30
8. Set the age x, this year's daughter is 35 7 = 5
35+x=(5+x)*3 x=10
9. 12 this year, 11 the year before 11 Grandpa 5 years ago: 11 * 9 = 99 This year: 99 + 1 = 100
10. Equation: set skipping rope x yuan, football 34 + x, money y yuan 30 * (x + 34) = y, 540x = y x = 2, y = 1080
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I really want to help you.
6.Lazy counting.
10.Lazy counting.
OK figure it out for yourself.
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Question 1: The circumference of a bicycle is centimeters.
10 minutes to 10 200 = 2000 weeks.
The distance of 10 minutes is: 2000 cm = 4396 meters Answer: The distance from Xiao Ming to the school is 4396 meters.
Question 2: The area of the grass that this sheep eats is the area of a circle with a radius of 3 meters, is:
Square Meter A: The maximum area of grass that this sheep can eat is square meters.
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Solution: Circumference of a circle: 2
Distance: A: The distance from Xiao Ming to the school is 4396 meters.
Solution: The area of the circle is the maximum area that the sheep can eat grass
A: The maximum area of grass that this sheep can eat is square meters.
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1. The bicycle can walk per minute: 70 * 200 * 10 100 = 1400 (meters).
10 minutes: 1400 *10=14000 (m).
Square metre.
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It should be 140 jiao each, because the total value of the 2 jiao stamps that Xiaojun bought is equal to the total value of the 5 jiao stamps, so half of the money he spent should be a multiple of 10, because the 2 jiao stamps that Xiaojie bought are equal to the number of 5 jiao stamps, so the money he spent should be a multiple of 7, so considering the two known conditions of Xiaojun and Xiaojie, the money they each spent should be a multiple of 140, which is 140 jiao each, a total of 280 jiao.
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Suppose they spent a total of 2x money to buy stamps, 2 jiao = yuan, 5 jiao = the total value of the 2 jiao stamps bought by Yuan Xiaojun is equal to the total value of 5 jiao stamps, the quantity ratio = 5:2, the average price: = (
The number of 2 jiao stamps and 5 jiao stamps bought by Xiaojie is equal, the number ratio: = 1:1, the average price: = (
The least common multiple of the denominator of 2 7,7 20 is 140,140*2=280, the answer is not unique, at least they spend a total of 280 yuan to buy stamps.
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Let Xiaojun buy 2 jiao stamps x, 5 jiao stamps y, Xiaojie buy 2 jiao stamps z, 5 jiao stamps Z, according to their same amount of money to buy 2 jiao, 5 jiao year of the rabbit stamps issued by the post office column equation 2x + 5y = 7z 1 formula;
According to the total value of the 2 jiao stamps bought by Xiaojun and the total value of the 5 jiao stamps, the equation is 2x=5y 2;
Replace 5y with 2x in Eq. 1 to get 4x=7z; Since xyz is the number of stamps, it can only be an integer. So x=7,z=4,there is 2x+5y=7z,y= take the least common multiple to get x=35,y=14,,z=20
The total cost is 35 * 2 + 14 * 5 + 20 * (2 + 5) = 280
I think there's more than one answer
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If the number of stamps bought by Xiaojie is 2x, then Xiaojie spent 14x yuan and Xiaojun bought the two stamps with equal total value, then the total value of the 2 jiao is 7x yuan, and the total of 5 jiao is 7x yuan, because 7x must be the least common multiple of 2 and 5.
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Question 1: There are 12 (1+1 4)=12 5 4=150,000 unemployed workers in city B, and 12 (1-1 4)=12 3 4=12 4 3=160,000 unemployed workers in city C.
Question 2: After the first use, the remaining part has 15 (3 5) = 15 5 3 = 25 meters This piece of cloth is 8 + 25 = 33 meters.
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The number of unemployed in city B is 120,000 * (5 4) = 150,000 C The number of unemployed in city C is 120,000 (1-1 4) = 160,000, let the original length be x
x-8)*(3/5)=15
The equation x=33 is 15 (3 5)+8=33
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1. The number of unemployed workers in city B is 1/4 more than that in city A, and there are 12 5 4 = 150,000 in city B.
The number of unemployed workers in city A is 1/4 less than that in city C, and in city C there are 12 4 3 = 160,000 people2, the second time 3/5 of the remaining part is used, the second time exactly 15 meters are used, and the remaining 15 5/5 = 25 meters.
25 + 8 = 33 meters.
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12 (1 1 4) = 16 (10,000 people) There are 160,000 unemployed workers in the city c.
15 3 5 8 = 33 (m) This piece of cloth is 33 m long.
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City B: 12*(1 4+1)=15 (10,000).
City C: 12*(1-1 4)=9 (10,000).
The remainder is 15 divided by 3/5 equals 25 meters.
This piece of cloth is 25 + 8 = 33 (m) long
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Do your own research or listen to the answers while the teacher proofreads.
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1.First of all, you need to know that the product of each factor 2 and factor 5 will add 1 0932 = 2*2*233 at the end
There are 2 factors 2 and 3 factors 5
To make there are 4 0s at the end, you also need 2 factors 2, 1 factor 5, so the minimum in parentheses should be: 2*2*5=20
2.Each trip up the mountain is 1 km and takes 1 to 3 hours.
The descent is 1 km per line and takes 1 to 5 hours.
1 km round trip, a total of 2 km.
Required: 1 3 + 1 5 = 8 15 hours.
The average speed is: 2 8 15 = km/h.
3.The round-trip journey is the same.
The return speed is 4 5 out of the road
Then the time taken to drive out is 4 5 to drive back
Sail out takes: 6 (4 5) (4 5 + 1) = 8 3 hours Maximum departure of the ship: 30 8 3 = 80 km.
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It's better for you to search online on your own.
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1. The greatest common factor is.
So the side length of the cut square is decimeter.
2 4 7=28 blocks).
A: At least 28 pieces can be cut.
7 25 = 535 and the least common multiple of 25 is 7 5 = 175.
The square has a side length of 175 centimeters.
175 175=30625 square centimeters
A: The area of this square is 30,625 square centimeters.
5 7=35 blocks
A: 35 rectangular pieces of paper were used.
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1. Turn the decimal into an integer, find the greatest common factor, and then find the minimum number of pieces that can be cut.
Decimeter 35 cm, 2 decimeter 20 cm.
The greatest common factor is 5.
The length can be cut 35 5 7 pieces, and the width can be cut 20 5 4 pieces, a total of 7 4 28 pieces.
2. Find the least common multiple, and then find the answer.
The greatest common factor is 175, i.e. the square side length is 175 cm.
The side length in the long direction should be 175 35 5 (sheets), and the side length in the wide direction should be 175 25 7 (sheets), a total of 7 5 35 (sheets).
The area is: 175 175 30625 (square centimeters).
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cm=5cm*7, 20cm=5cm*4, at least 7*4=28 can be cut.
The least common multiple of 25 is 175, 35*5=175, 25*7=175, so 5*7=35 rectangular pieces of paper are used.
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1, the maximum divisor with 2 is, so cut into small squares with side length of decimeters, there can be no leftovers.
block) 2, 35 and 25 The least common multiple is 175, the area 175 * 175 = 30625 (cm2), 175 35 = 5, 175 25 = 7, 5 * 7 = 35 (block.
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Expand 35, find the least common multiple of 35 and 25, it's too simple, top 1 down, add q2532933271
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1. Decimeter = 35 cm 2 decimeter = 20 cm, the maximum common factor of 35 and 20 is 5, 35 5 = 7, 20 5 = 4, 4 * 7 = 28 (block).
The least common multiple of and 25 is 175, the area is 175*175=30625 (cm2), 175 35=5, 175 25=7, 5*7=35 (block).
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Decimeter = 35 cm.
2 decimeters = 20 centimeters The common factor is 5, so the side length is a square of 5 centimeters.
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