Help you do a few math problems, help do a few math problems

Question 1: 2 (x-5) =

x-5=x=The second question is easy to ask if it is 18 and the positive and negative cancel out the sum of 0

Question 3: You Should Use Your Imagination The sides of the cube are equal in length, so the height of the cube is 1 3 of the length of the sides of the original square

Anyway, this should be done =. =

QuestionSupplementary question: If the subtracted side length is high, then the height of the cuboid is 10 cm; length minus two 10 cm for 25 cm; Width minus 2 pieces of 10 cm for 12 cm. Let's do the math for yourself =. = I'm lazy.

1. The solution of this equation is x=

2x=2x=

2. Yes, these numbers are.

9, their sum is 0 (because they are opposite to each other) open square = 3, that is, the side length of the square is 3 decimeters, to make a small cube drink box, then the side length of the small square subtracted from the four corners is 3 3 = 1 decimeter, that is, the area of 1 small square is 1 1 = 1 square decimeter, and four is 4 square decimeters.

So the total area of the box is 9-4 = 5 square decimeters.

4. The bottom length of this cuboid box is 45-10-10 = 25 cm, the bottom width is 32-10-10 = 12 cm, and the height is 10 cm, so its volume = 25 12 10 = 3000 cubic cm.

1.2.A 82 points, B 79 points, C 87 points, 32 boys were transferred.

Number of girls: 58x (14/29) = 28 (people) 7/15 of girls after transferring to boys 28 divided by (7/15) = 6060-58 = 2 (people).

Let the total amount of work be "1", the planned work efficiency is 1/8, and the actual work efficiency is 1/5

1/5-1/8 = 3/40 (3/40) divided by (1/8) = 3/5 = 60%.

3> 150*(1-40%)*4 (4+5)=40 books for Nursery class, 150*(1-40%)-40=50 books for Kindergarten class.

4> 16 (1 25%-1 45%) = 16 [100 (1 25-1 45)] = 16 (16 9) = 9 blocks.

5> 6-[1-6*(1 15+1 20)] 1 30)=6-30*(1-6*7 60)=6-9=-3 The question is problematic.

6> (360* hours.)

7> 277, 2000*20%, the cost of A is 922 yuan, and the cost of B is 1078 yuan.

8> Now 48 3 = 16 per pile, 16 2 = 8 in the first pile, 8 + 16 = 24 in the third pile, 16 + 24 2 = 28 in the second pile. The first pile was 8 + 28 2 = 22, the second was 28 2 = 14, and the third was 24 2 = 12.

9> 20 2-(3-1)(20 2-8) = 10-4 = 6 minutes.

10>11> 3 2 = 9 times.

13> Let the velocities be x,y, then r=(x+y)t=(x-y)r x y=(t+r) (t-r).

14> The length, width and height of the rectangle are 3, 1, 2, and the surface area = 2 * (3 * 1 + 3 * 2 + 1 * 2) = 2 * 11 = 22

17> 500-(950-500) = 500-450 = 50 people, 50 500 = 10%, 500 950 =, 18> (36 2) 3 = 6 cm.

19> 6*2=12kg.

20> B 81 (1 + 1 + 1 4) = 81 (9 4) = 36 years old, A 81-36 = 45 years old.

It's hard for you to type, I'm sorry, I won't!

< 1>12 Branch 31

3> Small 40 out of 50

4>20 pieces.

5> The question is incorrect.

5 24 = 100 i.e. 100 per minute per typist.

54000 100 (24-6) = 30 bits.

Answer: 2. Same as above, 300000 500 3=200 ml that is, each vehicle needs fuel liters per kilometer.

950 5 liters.

Because 950 liters and 1000 liters, it is enough.

8 4 = 2 units That is, each worker installs 2 units per minute 120 10 2 = 6 people This is the total number of people needed 6-4 = 2 people This is the number of people to be increased Answer:

1.12000 2 24 = 250.

54000 (24-6) 250 = 12 bits.

2.300000 3 500 = 200 ml = liters < 1000 liters.

So it's enough. 3.64 8 4 = 2 units.

120 (2*10)-4=2 people.

1. Because the square (side length is c) is a special rectangle (a, b), if the rectangle is strictly non-square, then by the title: 2(a+b)=4c, a+b=2c, ab<=1 2(a+b)=c, so ab<=c 2, when a=b, the equal sign is true.

The rectangle is strict, that's right, otherwise there is a possibility of waiting.

Two. (The meaning of the question is unclear and cannot be solved).

Three. 2 IV. 3

Fifth, the side length is , the perimeter is 48, no solution.

VI, 17, 4

8. BC A+C

9. >Two and Five-Sixths".

X. 3:5 XI. 10.

Ten. Second, small.

XIII. 6 km.

14. 17 people, 118 trees.

XV, 43, XVI, 16-48

XVII, 8000

Eighteen, 103 branches, down 1 corner 9 points.

Ten. Nine, one, two, day

Aren't you tired? It's better to think about it

Typing is hard work! 1.That's right.

I don't want to fight.

I can't help you do your own thing, you have to do it yourself.

1.In the second quadrant, x<0, y>0 -2m+4>0 gives m<2

k-4) 3,x is a positive integer solution of 1 2 3 4, so (k-4) 3>4 k>16

Piece. A triangle can be formed, and the sum of any two sides is greater than the third side. In other words, the sum of the two smaller sides is greater than the third side, and only 3 3 5 and 3 4 5 can form a triangle.

With this typing time, you're all done.

1.-2m+4<0

2m>4

m>2>43x4k-4>12

k>16

Ratio 3 to 5 3 to 4 to 5

Glad to answer your questions, I hope you can!

Solution: Because p is in the second quadrant.

So -2m+4>0

then m<2

1.Simplification and evaluation.

3x 2-2y 2+(y 2-2x 2)-(6x 2-y 2), where x = -2, y = 3Primitive = -5x 2=(-5)x(-2) 2=-20

2 (2x 3-6x-4)-3 (x 3+x 2-2x-3), where x = -2 3 original = -x 3-3x 2+5 = (8 27) - (4 3) + 5 = (-28 27) + 5 = 107 27

Question 2. Knowing a+b=2, ab=-1, find the value of (4a-5b-ab)-(2a-7b+5ab) in the original formula =2a+2b-6ab=2(a+b)-6ab=2x2-6x(-1)=10

Question 3. If the value of the equation (2x 2+ax-y+6)-(abx 2-3x+5y-1) is independent of the value of the letter x, find the value solution of the equation 1 2a 2-2b+4ab: (2x 2+ax-y+6)-(abx 2-3x+5y-1)=(2-ab)x 2+(a+3)x-6y+7;For this formula to be independent of x, it is necessary.

2-ab=0 and a+3=0.

a=-3,b=(-2 3) so.

1/2a^2-2b+4ab=（9/2)+(4/3)+8=83/6