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Anonymous users2024-02-08Solution: 20x 2-6x+3=0
x^2-3x/10+3/20=0
x^2-3x/10=-3/20
x^2-3x/10+(3/20)^2=-3/20+(3/20)^2x-3/20)^2=-51/400
Because: -51 400<0
So: the original equation has no real roots.
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Anonymous users2024-02-07Your problem is wrong and unsolvable, the discriminant formula is less than 0, if you want a formula, it is.
20x^2-6x+3=0
20(x²-3x/10)+3=0
20（x^2-2*3/20*x）+3=0
20(x-3/20)²+3-9/20=0
20(x-3/20)²+51/20=0
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Anonymous users2024-02-06First, the coefficient of the second term is removed and reduced to 1. The constant term is moved to the right, and half of the square of the coefficient of the primary term is added to both sides of the equation.
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Anonymous users2024-02-05Does this have to be matched?,It doesn't seem to be matched.。
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Anonymous users2024-02-043x^2+6x-1=0
x^2+2x-1/3=0
x^2+2x+1-1-1/3=0
x+1)^2-4/3=0
x+1-2 Qingpei3 3)(x+1+2 3 3)=0x=-1+2 The game is disturbing Tongdan3 3 or x=-1-2 3 3
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Anonymous users2024-02-03Move the constant term of the equation x 2 -2x- 1 3 = 0 to the right of the equal sign, and get x 2 -2x= 1 3 The handshake on both sides of the equation and the square of the selling god with half of the coefficient of the first term are added to get x 2 -2x+1 = 1 3 +1 formula (x-1) 2 = 4 3 square to get the middle loss x-1....
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Anonymous users2024-02-022x^2-6x+1=0
It can be used in the matching method.
and formula law drawbacks.
36-4x2=28
x=(6+2 times root number 7) 4 x=(6-2 times root number 7) 4x=(3+root number 7) rent burial roll 2 x=(3-root number 7) 2 hope liquid jujube can help you!
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Anonymous users2024-02-013x^2-2x+1=0
3x^2+2x-1=0
x^2+2/3x=1/3
x^2+2/3x+(1/3)^2=1/3+(1/3)^2x+1/3)^2=4/9
x+1/3=+-2/3
So x=-1 or x=1 3
Let me tell you that learning some one-dimensional quadratic equation matching methods in junior high school is divided into the following steps.
1. The equation is deformed, the coefficient of the quadratic term is positive, and the constant term is placed to the right of the equal sign.
2. The coefficient of the quadratic term is reduced to 1, that is, both sides of the equation are divided by the coefficient of the secondary term of the second chain at the same time.
3. Add half of the square of the coefficient of the primary term on both sides of the equation.
4. The left half becomes perfectly squared, and then opens, paying attention to the two answers.
2x^2-8x-6=0
x^2-4x=3
x^2-4x+(-2)^2=3++(2)^2x-2)^2=7
x-2 = plus or minus root number 7
So x = root number 7 + 2, or x = negative good talk about root number 7 + 2
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Anonymous users2024-01-313x squared - 6x = -2
x squared -2x = -2 Wu Liang 3
x flat cavity mega square - 2x + 1 = 1 3
x-1) squared = 1 3
x-1= guess (1 3).
x=1+√3/3 x=1-√3/3
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Anonymous users2024-01-302x24x-6=0
Divide both sides of the equation by 2 at the same time to get x2
2x-3=0 Qi Xiao.
Shift the giving megaconstant term to get x2
2x=3 formula, the height difference contains x2
2x+1=3+1（x+1）2
Open squared, we get x+1= 2
So, the solution of the original equation is x11, x2
It can be seen from the known that x cannot be 0, so then divide the known sides by x, and get x+1 x=6, and the result of the square is x 2+1 x 2+2=36 x 2+1 x 2=36-2=34
In fact, choosing a reasonable specification is complicated to say, in fact, it is very simple, that is, don't be greedy, many misleading and deceitful businesses, in fact, are using consumers' greed for multiples and other aspects (human nature, but unfortunately human nature is often used as a trap) to achieve the goal. >>>More
Calculate the value of x and check it.
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1) Let f(x)=x 3-x 2-x+m 3, then f'(x) = 3x 2-2x-1, let f'(x)=0, get f'The two zeros of (x) are: -1 3 and 1; f''(x)=6x-2，f''(-1 3)=-4 0, so f(x) takes the maximum value m 3+5 27 at x=-1 3;f''(1)=4 0, so f(x) takes the minimum value m 3-1 at x=1. Obviously, when the maximum value of f(x) is greater than 0 and the minimum value is less than 0, f(x)=0 can have three different real roots, that is, m 3+5 27 0 and m 3-1 0, that is, when -5 (1 3) 3 m 1, f(x)=0 will have three different real roots. >>>More