If x2 6 x 1 0 is known, then the value of x 2 1 x 2 is

It can be seen from the known that x cannot be 0, so then divide the known sides by x, and get x+1 x=6, and the result of the square is x 2+1 x 2+2=36 x 2+1 x 2=36-2=34

First, deform x2-6x+1=0.

x2+1=6x

Divide both sides by x at the same time to get.

x+1/x=6

x 2+1 x 2=(x+1 x) 2 -2=6 2-2=34 If you have any questions, send me a message...

Do you know that x2 is the square of x?

If yes, the answer is as follows.

Obviously x is not zero, divide the known two sides by x, and get x+1 x=6, and the square result is 34

x 5 x +2x+1 means (x 5 x) + 2x+1, does not mean x 5 and age (x Zhengchun + 2x+1). Are you sure you didn't make a mistake? (Oblique fractions don't function as parentheses, unlike horizontal fractions.) ）

Known. x -x-1=0, find the dispersion x to the fifth power.

Divide it. x to the fourth power + 2x to the power of 1

The value of the skillful journey. Solution:

x^2=x+1

x^4=(x+1)^2=x^2+2x+1=x+1+2x+1=3x+2x^5=x*x^4=x(3x+2)=3x^2+2x=3(x+1)+2x=5x+3

x 4+2x+1 =3x+2+2x+1=5x+3=x 5, so Zhenkuan, your result should be 1

x²+1=6x

Divide by xx+1 x = 6 on both sides

Square on both sides. x²+2+1/x²=36

x²+1/x²=34

x²-5x=14

This is equal to x -5x-14=0

x-7)(x+2)=0

So x=7 or x=-2

When x=7, (x-1)(2x-1)-(x+1) +1=6*13-64+1=15

When x=-2, (x-1)(2x-1)-(x+1) +1=15-1+1=15

So the value of (x-1)(2x-1)-(x+1) +1 is 15.

x 5x 1=0 == >> x 1=5x ***** >> both sides divided by x

x 1 x = 5 ===>>> squared on both sides x 2 1 x =25

x²＋1/x²=23

x²+1=5x ;(x=0 no solution).

So x+1 x=5

Square on both sides: x +1 x +2=25

So x +1 x = 23

The x-square is equal to 2/2 (23 plus minus 5, number 21).

x2+1 x2 equals ... Press Computer.