A math problem! Well said 40 points!

Because: medium:day=3:2, medium:korean=4:3

Conversion of points: Medium:Day = 12:8, Medium:Korea = 12:9 Together, that is: Medium:Japan:South Korea=12:8:9

And because the sum of the Japanese and South Korean contributions is 10 million yuan more than the Chinese side.

That is: the sum of 8 + 9 is 10 million yuan more than 12 shares, that is, 5 copies are 10 million yuan, and one copy is 2 million yuan.

Therefore, multiplying 200 by 12 is the contribution of the Chinese side, and the column is as follows.

Medium:Day=3:2, Medium:Korea=4:3

Medium:Day=12:8, Middle:Korea=12:9

Central:Japanese:Korean = 12:8:9

1000 (8+9-12)=200 (10,000 yuan)200 12=2400 (10,000 yuan).

Because the Chinese side: the Japanese side = 3:2, the Chinese side: the South Korean side = 4:3. So China:Japan:Korea = 6:4:3

Let the Chinese side be 4x4x+1000=6x+3x

4x+1000=9x

1000=5x

x=200, so the Chinese side contributes 8 million yuan.

China, Japan and South Korea invest in x, y, and z respectively

Then x y=3 2, x z=3 4

So y=2 3x, z=3 4x

Japan and South Korea have 10 million more than China, so there are: y+z=2 3x+3 4x=x+1000

Solution x=2400

Set the Chinese side out x the Japanese side out y and the Korean side out Z

x/y=3:2

x/z=4:3

y+z-x=1000

The solution is: x=2400 y=1600 z=1800

1 5 = 1/5 1 4 = 1/4 1-1/5 - 1/5 = 1/20 5 4=

1/20 =

A: There was a power outage for 1 hour.

The power outage time is x hours:

1-x/5=

x = 2 (hours).

1. Lose money, let the original unit price be a, the quality is b, then the original selling price is ab, now b =, a =, multiply is equal to 2, set the price increase x, then (a (1 + x), the solution x =, that is.

1.Solution: The journey of three people is 6:12:18=1:2:3, so A: 36x1 6=6 yuan.

B: 36x2 6=12

C: 36x3 6=18 yuan.

2.Solution: According to the title, there is.

A + B + C + D = 128

Since A+3=B-3=C3=D*3, then.

A = D * 3-3, B = D * 3 + 3, C = D * 9 so there is D * 3-3 + D * 3 + 3 + D * 9 + D = 128 solution Ding = 128 16 = 8

So A = 8 * 3 - 3 = 21

B = 8 * 3 + 3 = 27

C = 8 * 9 = 72

12 of the same pumping machines are required for the end of the day.

How many days is 5 pumps for 20 days, which is equivalent to 1 pump? 5 20 = 1006 units pumping for 15 days, which is equivalent to 1 pumping for how many days? 6 15 = 90 (20-15) days of water flowing into the reservoir equivalent to 1 pump, how many days? 100-90=10

How many days does 1 pump of water flowing into the reservoir in 1 day? 10 How many days does the original water in the 5=2 reservoir be equivalent to 1 pump? 100-2 20=60 or 90-2 15=60

How many days is 6 days of water flowing into the reservoir equivalent to 1 pump? 2 How many pumps do I need to pump in 6=126 days? （60+12）÷6=124.The user spends a total of 12 months on the electricity bill (yuan, and the modification fee is 100 yuan.

The electricity consumption before the modification is yuan, so a total of 1272-1008-100 164 yuan is saved.

Hello! 1.Solution: There are many ways to do this, but the more reasonable ones are:

The first 6 kilometers are divided equally among three people, 6 12 B C are evenly shared, and the last 6 kilometers are paid by C.

Equation: 36 18 2 (yuan).

2 6 2 4 (yuan).

4 (12 6) 2 2 10 (RMB).

10 (18 12) 2 22 (RMB).

A: A pays $4, B pays $10, and C pays $22.

This question cannot be calculated by distance).

2.Solution: According to the title, there is.

A + B + C + D = 128

Since A+3=B-3=C3=D*3, then.

A = D * 3-3, B = D * 3 + 3, C = D * 9 so there is D * 3-3 + D * 3 + 3 + D * 9 + D = 128 solution Ding = 128 16 = 8

So A = 8 * 3 - 3 = 21

B = 8 * 3 + 3 = 27

C = 8 * 9 = 72

12 of the same pumping machines are required for the end of the day.

How many days is 5 pumps for 20 days, which is equivalent to 1 pump? 5 20 = 1006 units pumping for 15 days, which is equivalent to 1 pumping for how many days? 6 15 = 90 (20-15) days of water flowing into the reservoir equivalent to 1 pump, how many days? 100-90=10

How many days does 1 pump of water flowing into the reservoir in 1 day? 10 How many days does the original water in the 5=2 reservoir be equivalent to 1 pump? 100-2 20=60 or 90-2 15=60

How many days is 6 days of water flowing into the reservoir equivalent to 1 pump? 2 How many pumps do I need to pump in 6=126 days? （60+12）÷6=124.Set any number to indicate the electricity consumption a (kWh).

Peak and valley electricity: >

So don't use peaks and valleys to save money.

Is there anything else you can ask me again?

I wish the landlord unlimited money and everything!

1. Since three people sat together for 6 + 12 + 18 kilometers, which is equivalent to a total of 36 kilometers, the cost per kilometer per person is: 36 yuan 36 kilometers = 1 yuan kilometer, and the payment is 6 yuan, 12 yuan, and 18 yuan.

2. Let the score be: A, B, C, D, then there is A + B + C + D = 128, where 3 D = C 3 = B - 3 = A + 3

Know: D = A 3 + 1, C = 3 A + 9, B = A + 6, know: A + A + 6 + 3 A + 9 + A 3 + 1 = 128

A = 21, B = 27, C = 72, D = 8

3. Let the inventory be z, the daily water intake is y, and the pumping water of each pump per day is x, then there is 5x*20=20y+z(1); 6x*15=15y+z（2）；There is (1)-(2) formula, 5y=10x, know y=2x, thus know z=60x, if m machines are needed to drain, then there is 6mx=6y+z, and m=(6y+z) 6x=12 (sets) are obtained

4. The original fee is: 200 (degree month) * 12 (month) * yuan degree) = 1272 yuan.

After the new meter is adopted, the cost is: 100 (degree month) * 12 (month) * yuan) + 100 (degree month) * 12 (month) * yuan) + 100 yuan = 1108 yuan, that is, you know that you can save 1272-1108 = 164 yuan.

1.Solution: The journey of three people is 6:12:18=1:2:3, so A: 36x1 6=6 yuan.

B: 36x2 6=12

C: 36x3 6=18 yuan.

Question 1: I think the title is like this.

If the polynomial -3(x 2)y (m+1) +x 2)(y 2)-2x 3-6 is a fifth-order polynomial then m=

Solution: x is already 2 times, then y is 3 times, m=2

Question 2: I think the question goes like this: Knowing x a=3 , x b=2 then x (2a+3b)=

Solution: x (2a+3b) = (x 2a)(x 3b) = [x a) 2][(x b) 3]=72

Question 3: If x 2 + 2 (a + 4) x + 36 is a perfect square formula, then a =

Solution: If a=2, is the square of (x+6); If a=-10, it is the square of (x-6).

Question 4: If 1 a+a=3, then the value of 1 (a 2)+a 2 is .

Solution: (1 a+a) 2=1 (a 2)+a 2+2=9, then 1 spine cherry (a 2)+a 2=7

Question 5: If x(y-1)-y(x-1)=4 find (1 2)(x 2+y 2) -xy

Solution: x(y-1)-y(x-1)=xy-x-xy+y=y-x=4 ; 1/2)(x^2+y^2) -xy= (1/2)[(y-x)^2]=8

Question 6: If a+b=5 ab=3 find the algebraic equation (a 3) b-2(a 2)(b 2) + a(b 3).

Solution: Wild Servant (A 3) B-2 (A 2) (B 2) + A (B 3) = Ab (A 2 - 2AB + B 2) = AB[(A-B) 2] = Ab[(A + B) 2 - 4AB] = 39

Question 7: If n satisfies (n-2006) 2+(2008-n) 2=1 find the value of (2008-n) (n-2006)!!

Solution: [(n-2006)+(2008-n)] 2=(n-2006) 2+(2008-n) 2+2(2008-n)(n-2006).

At the same time, [(n-2006)+(2008-n)] 2=[n-2006+2008-n] 2=2 2=4

So 2(2008-n)(n-2006)=3 ; （2008-n）（n-2006）=

1、m=22、x^2a+3b

x^a*x^a*x^b*x^b*x^b

a+4) = 12 or 2(a+4) = -12

Get a=2 or a=-10

4、(1/a²)+a²

1/a+a)²-2

5. x(y-1)-y(x-1)=4 can be slag annihilated and transported to.

x-y=-4

2/2 x 2 + y 2 -xy

1/2)*(x²+y²-2xy)

x-y)²/2

6. a+b=5 can be obtained.

a+b)²=a²+b²+2ab=25

Because ab=3, change the front, so a + b + 2ab-4ab = 25-4ab, that is, (a-b) = 13

a^3b-2a^2b^2+ab^3

a^3b-a^2b^2+ab^3-a^2b^2a²b(a-b)-ab²(a-b)

a-b) (a e.g. beam b-ab).

ab(a-b)²

7. (n-2006) 2+(2008-n) 2(n-2006+2008-n) -2(2008-n)(n-2006)4-2(2008-n)(n-2006)=1 (2008-n)(n-2006)==3 2

Question 1 is equal to 5

2 questions equals 72

3 questions are equal to 2,-10

4 questions equals 75 questions with an infinite number of solutions.

6 questions and other friends are registered at the age of 39

7 questions equals 3 2

Note: If the fifth question ends with 2xy, the answer is 8

7. No, but it always feels like it has something to do with the unit circle.

The purchase price of the retailer is 20 yuan on the basis of 60 yuan plus 60 yuan, which is: 60 (1 + 20) = 72 yuan.

The purchase price of a set of customers is 10 yuan added to 72 yuan on the basis of 72 yuan, which is: 72 (1+10) = yuan.

(1) 60 20% = 12 (yuan) 60 + 12 = 72 (yuan) Answer: retailers need 72 yuan to purchase.

2) 60 + (60 20%) = 72 (yuan) 72 + (72 10%) = yuan) Answer: Customers need yuan to buy a set.

(1).60*20%+60=72 (yuan).

Or: 60*(1+20%)=72 (yuan).

Answer: Retailers need 72 yuan to buy a set of toys.

2).72*10%+72=RMB).

Or: 72*(1+10%)=RMB).

Answer: Customers buy a set of toys for yuan.

(1) 20% = 1/5 60 times (1 + 1/5) (2) 10% = 1/10 72 times (1 + 1/10) (1) The retailer buys a set of toys for 72 yuan.

2) Customers buy a set of toys for yuan.

(1) The manufacturer earns 20%, so the purchase ** is 60 (1+20%)=72 yuan.

2) The retailer earns 10%, so the customer's purchase price is 72 (1+10%) = yuan.