The older brother and younger brother leave home at the same time to go to school, and the older bro

Read the question and learn two key information, first, "go 90 meters, my brother will return the same way to get things, and go to school immediately after getting it", then you can know that my brother walked 180 meters more.

2. "The elder brother walks 120 meters per minute, and the younger brother walks 90 meters per minute." and at the same time to school".

Assuming that the elder brother is x and the younger brother is y, then the equation is 120*x=90*y+180, and the time to solve the equation is 6 minutes, that is, the home to school is 540 meters.

Home to school x meters, from the meaning of the title.

x/90=（x+180)/120

Get x=540

The home is 540 metres from the school.

The elder brother walked 180 meters more than the younger brother when he went home to get something, the elder brother was 30 meters faster than the younger brother in one minute, and 180 meters was 6 minutes. My brother walked 6 minutes from 90 meters to the school, which is 540 meters. So the home to school is 630 meters!

The older brother walks 30 meters more than the younger brother per minute, and the older brother walks 180 meters more than the younger brother, so the walking time is 180 30 = 6 minutes.

Distance from home to school = 90x6 = 540 meters.

Solution: Set up a home away from school x, then:

2×90+x)/120=x/90

x=(2×90×90)/(120-90)

540 (m).

A: The home is 540 meters from the school.

The house is x meters away from the school, x 90 = (x + 90 2) 12012x-9x = 1620

3x=1620

x=1620÷3

x = 540 meters.

If you and your brother start from school at the same time, your brother will definitely be closer, and you can reach the school because your brother knows better.

After walking 90 meters, my brother went back to pick up his things, and went to school immediately after getting them. The elder brother walks 120 meters per minute, and the younger brother walks 90 meters per minute.

Such an older brother is. Let's go! 180 meters! And the younger brother walks 90 meters per minute, and the older brother walks 120 meters per minute. How many minutes did it take? You didn't even tell us.

The two brothers' home is 540 metres from the school.

If the elder brother and younger brother go to school from home at the same time, then it is normal for the family to go to school together, and some children may be willing to play more on the road.

As far as I can tell, well, the home is a total of 980 meters from the school.

The elder brother and the younger brother set off from home at the same time to go to school, and the elder brother and younger brother went to Xiao Jiali's school at the same time. The home moon school should be about fifty meters.

If the elder brother is like you said about this topic and the younger brother's departure time, then you can use a 90 x and replace it with a foreign one.

My brother and brother left home to school at the same time, and my brother and brother returned to school at the same time, and I think that their distance should be the same, and their journey and time are the same, so they should set off together.

Is it from home to school at the same time as my younger brother, and how much is my brother and younger brother at the same time from school? It's not necessary, because there are no conditions, so there is no time, and we can know how far away the school is from home.

The question lacks the necessary conditions, and it is necessary to know how much time it takes for the older brother and younger brother to go to school before a conclusion can be drawn.

The elder brother and the younger brother set off from home to go to school at the same time, and the elder brother and younger brother came home from a young age, how much did the family want, and how far did they go from home?

Normally, the distance between home and school is at least 3 kilometers.

I went to school at the same time in various locations, and my brother must have arrived at school with his geography colleagues, and the distance from the school was about 500 meters, so it was very close.

If you go to school together at the same time, the speed is about the same, then you must arrive at school together and come back at the same time.

Their home is 900 meters away from the school. The elder brother walks 90-60 = 30 meters more per minute than the younger sister.

The elder brother walked a total of 180*2=360 meters more than the younger sister.

So when they met, they walked 360 = 12 minutes.

At this time, my sister walked 60*12=720 meters.

So the school is 720 + 180 = 900 meters from home.

The rules of multiplication:

Digit alignment, starting from the right, use the number on each bit of the second factor to multiply the first factor, and whichever digit is multiplied, the end of the number will be aligned with which digit of the second factor.

1) The square of the mantissa number, written in the single digit, (full decimal place).

2) Multiply the first and last numbers and expand them by two times, and write them in the ten place, (full decimal place).

3) The square of the first number 23 23 = 529 36 36 = 12963 3=9 is written in the unit place 6 6=36 is written in the unit place, the full decimal place 2 3=6 2=12 is written in the ten place, the full decimal place 3 6=18 2=36 is written in the ten place, the full decimal place 2 2=4 is written in the hundred place, and the carry place 1 with the ten place is 5 3 3 = 9 written in the hundred place, plus the carry place of the ten place.

Oral decision: the square of the mantissa number, the first number multiplied by the mantissa number is expanded by 2 times, and the square of the first number.

The elder brother walks 90-60 = 30 meters more per minute than the younger sister.

The elder brother walked a total of 180*2=360 meters more than the younger sister.

So when they met, they walked 360 = 12 minutes.

At this time, my sister walked 60*12=720 meters.

So the school is 720 + 180 = 900 meters from home.

180x2 (90-60) 12 (min) 60x12 10 180 900 (m) Answer: Their home is 900 meters away from the school.

Solution: Set up a distance from home to school S meters.

s-180）/60=(s+180)/90

s = 900 (meters).

Wouldn't the elder brother wait for his sister, his parents would break his leg when he came home.

At this time, my sister had already traveled 360 meters.

Summary. Dear, the calculation process is as follows: (3180 + 42 10) (48 + 42) = 3600 90 = 40 minutes for the elder brother to pick up the younger brother.

The elder brother set off from home to pick up his younger brother at a speed of 48 meters per minute, and the younger brother set off from school at the same time to go home at a speed of 42 meters per minute, and the younger brother borrowed books from the library for 10 minutes, and it is known that a total of 3180 meters from home to school is known, so how long does it take for the elder brother to pick up the younger brother? Staring at celery.

Pro, the calculation process is as follows: (3180 + 42 10) (48 + 42) = 3600 90 = 40 points, brother regrets pretending to be a branch brother, and sets off for 40 minutes.

Dear, this problem can also be calculated like this: the elder brother and the younger brother Zheng Yan set off at the same time, and the elder brother took the fan brother to walk the stupid hail for ten more minutes, and then the two of them completed the distance of 3180m. (3180-48 10) (42+48)=2700 90=30 minutes, 30+10=40 minutes, older brother departs, 40 minutes, picks up younger brother.

Roger that. Dear, this question is the relationship between distance, speed and time. Distance = Speed Time Speed = Distance Time Time = Distance Speed.

1400×2÷（200+80）

10 minutes. 600 meters. It took 10 minutes to walk from the departure to meet the sister, and the meeting place is 600 meters from the school.

Peng Yingfang Yin Xinhua, hello:

The elder brother finished the journey and then met his sister on the way back, that is, the brother and sister traveled two full journeys together!

The first whole process is the elder brother's line, the second whole process is the brother coming home from school, the younger sister going to school from home, and then the two meet!

Departure to Encounter: (1400 2) (200 80) 10 (minutes) So Encounter from school: 1400 10 80 600 (m).

My brother arrives at school 1400 200 = 7 minutes.

My sister walked 7 80 = 560 meters in 7 minutes.

The remaining distance is 1400-560 = 840 meters.

Encounter time: 840 (200+80) = 3 minutes.

3 200 = 600 meters from the school at the time of meeting.

Solution: The distance between the home and the school is x meters.

Then the distance taken by the elder brother is (x+180) meters, and the distance taken by the younger sister should be (x-180) meters, and the time taken by the elder brother and sister is the same, according to the title.

x+180) 90=(x-180) 60 solution x=900 meters.

Hello: My brother returned to school, walked 180 meters and met my sister, walked 180 90 = 2 minutes, and walked 2 60 = 120 meters in 2 minutes, indicating that when my brother arrived at school, the distance between me and my sister was 180 + 120 = 300 meters.

The distance to the school, the elder brother walked a total of 300 meters more than the younger sister, and the elder brother walked 90-60 = 30 meters more than the younger sister per minute.

From home to school, my brother's time: 300 30 = 10 minutes, distance from home to school: 90 10 = 900 meters.

Clear? Hope it helps!

Arithmetic methods.

20 (minutes).

1400（m）

Or 60 20+200

1400（m）

Equation solution: Set up a home away from school xm

x+200)÷80=(x-200)÷603(x+200)=4(x-200)

3x+600=4x+800

4x-3x=800+600

x=1400

A: Their home school is 1400m.

40x5 = 200 meters, the younger brother walks 200 meters before the elder brother, 65 40 25 meters, the elder brother walks 25 meters more per minute, 200 25 8 minutes, the elder brother catches up with the younger brother in 8 minutes, 8x65 520 meters, their house is 520 meters away from the school or the younger brother walks first for 5 minutes plus the elder brother catches up for 8 minutes.

8+5 13 mins 13x40 520 m.

Based on the equal distance, we list the equations. It takes x minutes for my brother to get to school. 40 5 + 40 x = 65x, x = 8, 65 8 = 520 (m), their house is 520 m from the school.

Set the time when your brother is gone to x. The column formula is 65x=(x+5)x40, x=8, and the home school is 520 meters.

(15-12) Divide by 12

3 divided by 12 quarters.

Calculation method: 1) The numerator and the integer are multiplied, and the product obtained is the numerator, and the denominator remains unchanged;

2) The calculation result should be reduced to the simplest score.

Calculation method: 1) multiply the molecule by the numerator, and the product obtained is taken as the numerator; The denominator is multiplied by the denominator, and the resulting product is used as the denominator;

2) The calculation result should be reduced to the simplest score.

For the sake of simplicity, if the calculation process can be reduced, it can be reduced first, and then calculated. (Format: Cut out the number of numerators and denominators that can be divided, and write the reduced numbers above and below them.) )

If the distance from school to home is 1, then the speed of the elder brother is 1 12The younger brother has a speed of 1 15, and the older brother is 1 12-1 15 = 1 60 faster than the younger brother