High school chemistry, I cried again, sophomore chemistry in high school. Tears and kneeling for ans

1. Water is used as an oxidant, and sodium is used as a reducing agent.

2 The chemical equation is written incorrectly, it should be Na2O+H2O=2NaOH This is not a redox reaction.

There is no change in valency, so water is neither an oxidizing agent nor a reducing agent.

3 It can be seen that sodium peroxide reacts with water first to form sodium hydroxide and hydrogen peroxide, which is a metathesis reaction.

Then hydrogen peroxide is split into water and oxygen, so water is neither an oxidant nor a reducing agent, but the whole reaction is a redox reaction.

4 The valence of hydrogen and oxygen in water does not change, so water is neither an oxidant nor a reducing agent but a redox reaction.

5 This is not a redox reaction.

I analyzed it very clearly, don't be superstitious about the answer, don't worry, as long as your question is correct, I promise it is 3 and 4

That's what I eat.

The equation is written incorrectly Correct 2Na2O + H2O = 2NaOH Both equations have elemental valence, but not the elemental valence of water, so choose 34 and ask again Don't hurt people upstairs! Topic requirements.

Neither oxidizing agent nor reducing agent for redox reactions.

That's it! Oxidants or reducing agents will change their chemical valence in chemical reactions, but the chemical valence of these two water has not changed! So it's and .

Three and four, I didn't see the title clearly.

See the standard answer:

1. Ethane is a carbon-carbon single bond, which is a bond; Ethylene is a carbon-carbon double bond, where the two bonds are not the same, a bond and a bond, and the bond bond energy is less than the bond, ( bond + bond) bond, so the carbon-carbon double bond energy of ethylene is greater than the bond energy of the carbon-carbon single bond of ethane.

Since the bonds are very stable, and the bonds are unstable and easy to break, ethylene is chemically active, and the bonds in its molecules are easy to break.

2. There should be one less circle in the middle of your **. It is not benzene, it should be o-xylene, and its monochlorinated form should be three isomers, of which there are two isomers on the benzene ring. The judgment method mainly depends on the symmetry of the molecule.

There are carbon-carbon double bonds in ethylene, which are more likely to break during the reaction.

Ethane has a single bond, so the properties of ethane are more stable.

1. Alkanes are saturated bonds, so ethane is more stable than ethylene with unsaturated bonds.

2. I can't see the picture. There are a lot of isomers.

1. Because ethylene is a chemical bond and a double bond, the stability is relatively weak.

The isomers of benzene are divided into positional isomerism, structural isomerism, and functional group isomerism.

If you look at the position, you can look at the neighbors, counterpoints, interpositions, structures, and functional groups, and it is the same as ordinary organic matter.

1.The main reason is that ethylene contains carbon-carbon double bonds, which are unsaturated bonds and are easy to be oxidized. Whereas, ethane contains only carbon, and the carbon single bond is a saturation bond, which (you can compare it to methane) and is therefore more stable.

2.Generally speaking, there are three isomers of benzene: "o-", "inter" and "pair".

1. The bond energy of a double bond in ethylene is less than twice that of a single bond in ethane, and one bond is easy to break.

2 Due to symmetry, the chlorine at the topmost vertex and the bottommost vertex of the hexagon in the figure are equivalent, as are the chlorine on the two vertices on the left. Isomerism of benzene? You should be referring to the position of the two methyl groups on the benzene ring. There are three types: neighbors, interferals, and pairs.

Hehe, I've thought about it before, in fact, you have to think like this.

Here's the equation.

nan3===na+3 2n2 right? This equation illustrates that N mol of Nan3 can produce (3 2) nn2mol of nitrogen. The two are not equal.

The question you're asking is to make the two equal, right? Then you can only multiply the latter by 2 3 to make them equal.

<> guy smashed you wrong with the formula.

Preview the basics.

Identify concepts. Review the questions carefully.

Answer the questions carefully. Summarize in a timely manner.

Look for the cause of the error.

I think that the most important thing to learn chemistry is to summarize more, don't do too much questions, do a type of questions, then digest a type, when doing a multiple-choice question to judge right or wrong, carefully figure out the intention of the questioner (remember), don't fall into the trap, for to memorize the knowledge points, it is best not to memorize, it is recommended that you ask the teacher, let him tell you the principle, so that the impression is deep.

Chemistry is actually a very simple thing, you can memorize it and do more exercises to deepen your impression!

Hope it helps you in your studies.

Feel free to ask o( o

Good luck with your studies