High Score !! Pointing the way! Please be serious 20

I can only tell you that in college, it is very difficult to get caught cheating in college, my classmate was arrested at the end of his senior year, he was crazy at the time, and finally the family borrowed from the east and west, and found someone to trust the relationship to cross out the big mistake in the file! So in this way, there is money in the family? ok！

Let's keep reading! But! I advise you, since it's three books now, we're still freshmen, and we're still young, why don't we do it all over again?

It only takes a year, and it doesn't take much money to repeat it, but it's really hard to put the cheating thing right! Think about it! If you reread it, you may get into a different university!

Eat a trench and grow wise, don't do stupid things in the future!

Is it that serious, you can try to talk to the teacher who arrested you first, explain the situation, be respectful, and if he has already reported, go to the academic affairs office to find the teacher to explain the situation. If the counselor is okay, ask him for help. I advise you to finish college as much as possible and not drop out.

You've just finished a semester now, and there's still something to learn! College can be useful to you.

I think you should tell your parents. This society is deformed. It doesn't matter if you're three books or whatever.

After all, it's a college student. It's good to be able to find someone, and it's good to find someone, given that you say it's okay to find it. It's not about who has and who doesn't.

Study it with the instructor and have a look. Ask bluntly if there is any way to remedy it. Then listen to your parents' opinions before making a decision...

Generally, if you are caught cheating, you will not cancel your degree certificate, you will be given a warning or something, just get through it.

1) Equation 1 * 5 gives 5y+15x+85=0 (3)3)-(2) 17x+68=0

So x=-4

Substituting x=-4 into 1 gives y=-5

2x+y+z=12 (1)

x+2y+5z=22 (2)

x=4y (3)

3) Substituting (1) and (2) respectively.

z=12-5y （4）

6y+5z=22 （5）

4) Substitution (5).

6y+5（12-5z）=22

y=2 is substituted into (3) and (4), respectively.

x=4*2=8

z=12-5*2=2

So the solution of the system of equations is x=8;y=2；z=2 )3)x+y+z=26 ⑴

x-y=1 ⑵

2x-y+z=18 ⑶

:2x+z=27(4)

:3x+2z=44(5)

4)*2-(5):x=10

Substitution (4): z=7

Substituting (1)y=9!

4)5（x+2z）=5*12

5x+10z=60

5x-2y=6} is subtracted to give 10z+2y=54 and 2y-z=-1 to get z=5, and x=2, y=2 are brought into the formula

5)x+y-z=11 ①

y+z-x=5 ②

z+x-y=1 ③

Add the three formulas to obtain: x+y+z=17

Get: 2x=12 x=6

Get: 2y=16 y=8

Get: 2z=6 z=3

6)a=-5/4

b=9/4c=9/8

The algorithm is as follows. a-2b-2c=-8 a

a+2c-1=0 b

a+3b-4c=1 c

a+b=2a-2b=-7 d

2b+c=3a+3b=3, i.e., a+b=1 e

Combined with d and e, it can be calculated that a=-5 4, b=9 4 is substituted into b, and c=9 8 is obtained

x+y+z=26 ⑴

x-y=1 ⑵

2x-y+z=18 ⑶

:2x+z=27(4)

:3x+2z=44(5)

4)*2-(5):x=10

Substitution (4): z=7

Substituting (1)y=9!

I'm exhausted!