A few questions, help you! A topic, everyone to help!

Except for question 5 of zer789, it is basically correct.

The fifth question is wrong, Tokyo is in the East 9th Zone, one time zone away from Beijing. Arrive in Beijing at 9 a.m.

Question 8: The solar terms are about 15 days apart. Reference.

P.S. Question 6 10 degrees east longitude should be geographically completely in the first east zone, but politically it passes through part of Libya in Africa, and Libya uses the time of the second east zone.

4a at the beginning of each month of the lunar calendar.

Beyond the Arctic and Antarctic Circles, beyond the Tropic of Capricorn, is the temperate zone between the north and the south.

The time used in our country is the district time of the East 8th District.

Tokyo is east of Beijing, so coming from Tokyo should be +2 hours, which is 10 o'clock.

East Zone 1. The summer solstice or the winter solstice.

24 To be precise, it should be different, and there may be a problem with this topic.

0° meridian is the prime meridian.

Zone Time Line Zone Time.

High Low.

1.-4a2.At the beginning of each month of the lunar calendar.

3.The Tropic of Cancer to the Arctic and Antarctic Circles is the temperate zone between the north and the south.

It should be +2 hours, which is 10 o'clock.

6.East Zone 1.

7.The summer solstice or the winter solstice.

15 It should be different to be precise.

9.Warp 10Zone Time Line Zone Time.

11.Low High.

1, -4a2, around the fifteenth day of the lunar calendar.

3. North and south temperate zones.

4. BC6, East Zone 1.

7. Winter 99 takes the winter solstice as the starting point, and Xia 99 is the summer solstice.

15 (Actually, there are changes).

9. Prime meridian.

10. When the standard warp area.

11. High and low.

1, -4a2, the beginning of the month.

3. Temperate zone. 4、b

Degree 30 minutes 157 degrees 30 minutes.

7. Winter solstice, 15

9. Weft. 10. Zone time line, ** meridian.

11. Low, high.

1, minus 4a2, the first day of the lunar calendar.

3. Temperate zone. 4，c

5,10 points.

Borrowed 1000, repaid 20, remaining 10, to be repaid 980, spent 970. According to the meaning of the title, the relationship between (to be repaid) and (surplus), then (to be repaid borrowed - repaid), (borrowed surplus + spent + repaid). Then (to be repaid surplus + spent + repaid - repaid surplus + spent).

To be returned and decayed, the remainder is the relationship between "addition" and "and". The return question is "and" + "addition", which is not valid (this statement is incorrect). If you have to say "and" + "add" to get 990, then this 990 has nothing to do with "borrowing", it only means to be repaid + the remaining money.

I think most of the people who missed it should understand.)

(1) From the figure of question 27-3, it can be seen that the image of y2 passes through the points (0, 60) and (60, 90), and the solution: substituting x=0, y=60, x=60y=90 into y=tx+b, gets:

60=0t+b, solution {b=60

90=60t+b, get: {t=1 2

The functional relationship between y2 and t in the figure 27-3 is y2=(1 2)t+60

2) the coordinates of point a (120 11, 720 11), point a is the intersection of y=6t(0t 30) and y2=(1 2)t+60;

The coordinates of point b (600 13, 1080 13), point b is the intersection of y=-6t+360(30 t 60) and y2=(1 2t)+60.

3) PS: Actually, I think the practical significance of the second question is that when the minute hand turns how much it coincides with the clock, it is more practical.

It turns out that there are x books on the finch cavity of the bookshelf A and Y books on the second shelf.

x+5=5(y-5)

x-5=3(y+5)

x=95y=25

2. When setting uphill, there are x kilometers of uphill roads, and there are y kilometers of noisy downhill roads.

x/20+y/35=9

x/35+20/y=15/2

x=140y=70

The two liters of town are 210 miles apart and 140 uphill when they go

x+7y+z=315 (1)

4x+10y+z=420 (2)

2)-(1) gives x+3y=105 (3).

1)-2*(3).

x+y+z=105

A total of 105 yuan is required.

The radius r of the circle is related to the perimeter of the rectangle: perimeter = 2 r + 2r = (1) perimeter: 2 r + 2r =

2), the solution is r=4 (cm).

Circumference: 2 r=2

Circle area: r2 = square centimeter) or (square centimeter).

Circumference of an approximate rectangle = circumference of the circle + 2 radii = 3 2 +3 2 = 6 Find the radius of the circle first, r=

The circumference of the circle c=2 r=2

The area of the circle s= r =

Solution: Let car B travel x kilometers per hour, 3 hours travel 3x, and car A travels 48 * 3 hours 48 * 3 = 288-18

3x=126

x=42km

A: Car B travels 42 kilometers per hour.