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This problem is actually very simple, acetic acid is a weak acid, and its acid ions will be hydrolyzed, even if it reacts completely with hydrochloric acid, the reaction products will also contain acetate ions, as long as there are acetate ions, acetate ions will be hydrolyzed. It can be said that as long as there is a weak acid ion in the solution, no matter who it reacts with, the weak acid ion in the solution will be hydrolyzed in the end, and as long as it is present, it will be hydrolyzed. (After all, hydrolysis is a very weak process, and the production of hydroxides and acids is very small, almost negligible, so there is no inhibition or effect) Ions that can be hydrolyzed will be hydrolyzed in aqueous solution, unless the ions disappear or are absent or are not hydrolyzed.
If you don't understand, you can continue to ask, hope!
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The equilibrium constant of hydrolysis is usually very small, the hydrolysis of weak acid gives oh- (while the hydrolysis of weak base salt gives proton), when the concentration of oh- in the solution is large relative to the whole equilibrium, the hydrolysis equilibrium proceeds in the direction of negative reaction, and hydrolysis can not be considered at this time.
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Incomplete, hydrolysis cannot be carried out thoroughly.
Most of the time hydrolysis is considered, unless, as otherwise specified, the question is specifically stated
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This is very well explained by the equilibrium constant. Didn't go to high school, you can think so. Hydrochloric acid, in which hydrogen ions, reacts with the hydrolysis of acetate to form hydroxide.
There are both acid and salt forms in the system. The proportion, according to the original amount and the amount of hydrochloric acid added, can be solved by the method of equilibrium constant.
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It can be understood that the weaker the weak acid ions, the smaller the degree of ionization of the weak acid.
The acid-base neutralization reaction is generally a reversible reaction, but the degree of forward reaction is quite large, and salt hydrolysis is the reverse reaction of acid-base neutralization, [because acid-base neutralization is dominant, so salt hydrolysis is very weak] - that is, weak acid and hydrogen ionized by water form weak acid, and cation and hydroxide ionized by water form strong alkali.
For example, acetic acid ionizes about 13 out of every 1000 molecules, while silicic acid is almost insoluble in water, so it is not ionized. Then, relatively speaking, if acetate ions want to hydrolyze back into acetic acid, they also need to risk that about 13 out of every 1000 molecules need to be reionized, and silicate ions will not be ionized again when they become silicic acid, and the amount of ——— and other substances is more hydrolyzed than acetate——— and the weaker the acid ions, the easier it is to hydrolyze.
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The weaker the acid, the more it is willing to stay in the form of molecules, unwilling to ionize, and the corresponding weak acid ions in the salt are easy to rob the hydrogen ions ionized by water to generate weak acids, so the degree of hydrolysis is large, which promotes the ionization of water, and the hydroxide of water ionization is more, and the alkalinity is strong. Accessible enough, right?
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It can be explained by the law of difficulty, e.g. a = reversible = b, a if it is easier to b, then b to a is more difficult. It's like it's easy to go from thrift to luxury, and it's hard to go from luxury to thrift.
Weak acid = reversible = nyogenic ion + hydrogen ion.
If the acid is weaker, the weaker the acid is to ionize, that is, the more difficult it is to move forward, and the easier it is for the weak acid ion to bind hydrogen ions (hydrolysis) to the reverse, and the more alkaline the solution.
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The process of hydrolysis is the process by which anions combine with hydrogen ions in water to form weak acid molecules. Since the weak acid molecules are not ionized, the hydrogen ions in the water are reduced, and the content of hydroxide is relatively increased, making the solution alkaline. Therefore, the weaker the acid, the more hydrogen ions can bind, resulting in the stronger the alkalinity of the solution.
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Theoretically, strong acids cannot be used to make weak acids, but some weak acid acid ions will form insoluble precipitates with cations in the salt solution, so that the hydrogen ions in the weak acid have to be combined with the acid ions of the strong acid in the salt solution to obtain strong acids.
For example: H2S + CuSO4 ==Cus + H2SO4
hi + agno3 ==agi↓ +hno3
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The acid salts of weak acids can be seen as the product of the ionization of H+ by the alkali of multiple weak acids!
For example, H2CO3 is ionized to form HCO3- after ionizing one H+, that is to say, 1 H2CO3 and 1 NaOH react, and the 2 H+ ionized by carbonic acid can only be neutralized by one!
H2CO3 + NaOH = NaHCO3 + H2O, and another hydrogen ion is present in the salt to form sodium bicarbonate!
However, sodium bicarbonate is still a weak salt, so when a stronger acid than carbonic acid is added to the system, carbonic acid (CO2+H2O) is obtained
HCO3- +H+ = H2CO3=CO2+H2O (i.e., HCO3- has a tendency to combine 1 H+ to form H2CO3).
As I mentioned above, HCO3- is the product of the ionization of H2CO3 by the partial neutralization of H+ by the base, so when H2CO3 is all neutralized by the base, that is, when both H+ are lost, CO3 2- is generated
NaHCO3 + NaOH = Na2CO3 + H2O (the carbonic acid partially neutralized in the previous step, i.e., sodium bicarbonate will further react with NaOH to form a positive salt) (i.e., HCO3- has a tendency to combine 1 OH - to form CO32-).
To sum up, the acid salts of weak acids are amphoterior!
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Strong base: A base that can be completely ionized when dissolved in water.
Slippery strong acid: An acid that can be completely ionized when dissolved in water.
Ionization refers to the process of dissociating substances into free anions and cations under the action of water molecules after being dissolved in water.
The principle of salt hydrolysis is that anions or cations can combine hydrogen ions or hydroxide ions ionized by water to form weak acids or weak bases, while strong acids and strong bases are completely ionized in water, so strong acids and strong alkali salts do not undergo hydrolysis.
Hydrolysis of salts:
Definition: The process by which the ions of salt in solution are ionized with the hydrogen ions or hydroxide ions ionized by water to form a weak electrolyte.
Conditions: The salt must be soluble in water, and the salt must be able to ionize weak acid ions or weak base cations.
Substance: The generation of weak electrolytes destroys the ionization of water and promotes the process of changing the ionization balance of water.
Rules: insoluble and not hydrolyzed, only when there is weakness, no weak is not hydrolyzed; Whoever is weak is hydrolyzed, the weaker the more hydrolyzed, and all weak are hydrolyzed; Who is strong and who is sexually (applicable to positive salt), the same strong is neutral, and the weak is specific; The weaker it is, the more hydrolyzed, the hotter it is, the more hydrolyzed, and the thinner it is, the more hydrolyzed.
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Ionization refers to the rapid dissolution of a substance in water after it is in the water molecules.
The process of dissociation into free yin and yang mask collapse ions.
For example, NaCl can be ionized in water to form free molecules, and the principle of hydrolysis of Na+ and Cl- salts is anion.
cation) can bind H+(OH-) ionized by H2O to form a weak acid (weak base).Strong acids and bases are completely ionized in water, so strong acids and strong alkali salts cannot be hydrolyzed.
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You missed Pei Xian and said it wrong!!
The greater the pH of the solution in the strong alkali weak salt (the stronger the alkalinity), the weaker the acidity of the corresponding acid in the backshot;
And the weaker the acid, the more acid ions it has.
The stronger the hydrolysis ability, the greater the pH of the corresponding strong alkaline brine solution.
Like the one on my picture, bicarbonate.
The more severe the hydrolysis, the more OH is generated, and the stronger the alkalinity of Zhongkai.
In this reaction, there is only the electron gain and loss of nitrogen element, the valency has risen and decreased, so C is wrong, the increase of nitrogen in metadimethylhydrazine is oxidized, it is a reducing agent, so a is wrong, the reaction is the recombination of atoms, so there is an endothermic and exothermic process, C is wrong, D is left, of course, there are eight electrons transferred from two N2O4 to N2 D is correct.
Organic substitution can also be understood as replacement.
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