Urgently, physically the ball collision problem

Isn't this Newton's cradle?

Principle. The leftmost ball in the diagram next to it gets momentum and is transferred through collision to the ball hanging side by side on the right, and the momentum is transmitted to the right in the four balls. When the rightmost ball is unable to continue to pass momentum, it is ejected.

It's a series of elastic collisions.

It also contains inelastic collisions and momentum. Since there is no other force in the collision, the momentum of the ball at the velocity vl of the left mass m must be transferred to the ball at rest on the right. The r-ball with the right mass m has the same momentum after being collided.

The balls that are collided have a velocity vr to the right and a tendency to move to the right, which is called the conservation of momentum.

The energy before and after the collision must be consistent, and the vibratory motion of the ball is ignored here, writes.

For the first formula, since it is not equal to zero, the velocity is. The first formula, l = r, means that several balls are bounced after being collided during the collision.

Here, the bumpered ball moves at the same velocity, while the remaining ball does not move. When there are more than two balls, energy cannot be conserved.

and conservation of momentum considerations.

In the gravity system, the L-ball on the left collides with the R-ball with velocity Vl on the right side with a velocity of Vr, observing the conservation of energy and momentum, and after the collision, the L-ball continues to move with velocity Vl to the right and the R-ball with velocity Vr to the left. Conversely, the l-ball can be at opposite speedsvl,r balls have opposite velocities

vr。To explain the behavior of the string, it is necessary to think further about how the impact wave is transmitted in the string.

Copy from the encyclopedia.

Just touching the energy is all transferred, so the two balls go up.

The relative velocity of the two small balls before and after the elastic collision.

Unchanged, it is established in the case of speed exchange. This is only the case with the collision velocity exchange (where two balls of equal mass collide elastically, where one ball is stationary and one ball moves, and after the collision the latter stops, the former gets that v). Suppose that the masses of the two objects are m1 and m2 respectively, and the velocities in their centroid system are v1 and v2 respectively, then because they are in the center of mass system m1v1 + m2v2 = 0.

If an elastic collision occurs, the velocity of m1 becomes v3 and the velocity of m2 becomes v4, then the momentum is conserved m1v3+m2v4=m1v1+m2v2=0, v3 v1=v4 v2=k. Because it is an elastic collision, it is not difficult to get k=1 if the kinetic energy of the system does not change. Then it can be proved that v3-v4=v2-v1, that is, the relative velocity is constant.

As for the direction, it can be changed or not, if it is a positive touch, it will not change, otherwise it will change. Ideally, after an object collides, the deformation recovers without heat.

Vocalization, with no loss of kinetic energy, is called elastic collision, also known as fully elastic collision.

True elastic collisions occur only between molecules, atoms, and smaller particles. In life, when a hardwood or steel ball collides, the loss of kinetic energy is small and negligible, and their collision can usually be regarded as an elastic collision.

The collision velocity formula is: v1'=(2m2v2-m2v1v2+m1v1)/(m1+m2)，v2'=(2m1v1-m1v2+m2v2)/(m1+m2）。

Let m1 and m2 denote the masses of the two spheres, respectively. v1 and v2 represent the velocity of the two balls before they collide, respectively. V1 and V2 indicate the velocity of the two balls after they collide.

According to the law of conservation of momentum: m1v1 m2v2 m1v1 m2v2.

Note: 1) Distinguish between internal and external forces: there must be an interaction force between two objects when they collide, because these two objects belong to the same system, the force between them is called internal force; When an object outside the system exerts a judgment, it is called an external force.

2) With a certain total momentum, the momentum of each object can vary greatly. For example, two stationary trolleys are connected by a thin wire with a compressed spring in the middle.

After the thin wire is burned, due to the action of elastic force, the two trolleys move to the left and right respectively, and they both gain momentum, but the vector sum of the momentum is zero. Digging celery.

The collision velocity formula is:

<> assumptions: m1 and m2 represent the masses of the two balls, respectively, and the first and second rows represent the velocity of the balls before the collision, respectively.

According to the law of stability:

<> fully elastic collision In an ideal case, the physical process of a fully elastic collision is sufficient to maintain the conservation of momentum and energy, which is usually directly referred to in high school physics materials as an elastic collision between the conservation of mechanical energy and the conservation of energy, if the mass of the small collision ball is equal, the equation of conservation of momentum and energy at the time of collision can be solved with the exchange of velocity after the collision of two small balls.

If the ball being hit is initially stationary, then the velocity of the ball being hit is the same as that of the ball being hit, the ball being hit stops, and when multiple balls collide, a similar analysis can be made, in fact, the collision between the balls is not the ideal elasticity, but rather the loss of energy that causes the ball to stop.

Difference Between Internal Force and External Force: There must be an interaction between internal and external forces Jasam is colliding because an object belongs to a system that defines the internal force between the internal forces of a system and what is outside the system is called an external force.

When the total motion is determined, the motion of each object changes significantlyFor example, two small stationary vehicles are connected to a thin line of a central pressurized spring, and after the thin wire is cut, the two small vehicles move to the right and left due to the thrust, and both gain thrust, but the thrust moves towards zero.

What happens when two balls with the same mass and velocity move in opposite directions? Discussed in several situations: Ant Sheng.

1. If it is an elastic positive collision, the exchange speed of the two balls after the collision, that is, the two balls A and B are at the original velocity of the other party** (the total momentum is 0, and the total kinetic energy is conserved).

2. If it is a completely inelastic positive collision, after the collision, the two balls are combined with a velocity of 0 (total momentum is 0).

3. If it is an inelastic collision, the velocity of the two balls is between the above two cases, but the total momentum must be 0 (the two balls move at the opposite constant velocity, and the speed is less than the original velocity).

The momentum (not necessarily velocity) before the collision of the two small balls!! The total momentum of the system is 0, and a completely inelastic collision occurs (the deformation cannot be recovered at all, and it is glued together after the collision), and the motion stops after the collision.

If the two balls with the same mass and the same speed move in the opposite direction, if the elastic collision is positive, the two balls exchange speed after the collision, that is, both A and B balls are reversed at the original speed of the other party (the total momentum is 0, and the total kinetic energy is conserved).

First of all, the momentum is conserved, and the second is to see the conditions for you, if there is no energy loss (elastic collision), the energy conservation should be considered, and if there is an energy loss, the loss should be found according to the subject conditions, and the direction should be judged according to the initial momentum.

The four situations in which the ball collides are as follows:

1.Fully elastic collision: In this case, there is no loss of mechanical energy after the collision of the small ball, and the small ball bounces back in one direction with a velocity equal to the magnitude of the incident velocity, but in the opposite direction.

2.Completely inelastic collision: In this case, the mechanical energy loss is greatest after the ball collision, and the ball sticks together at a lower velocity in the direction of the ball with the larger resultant momentum.

3.Elastic collision: In this case, there is a loss of mechanical energy after the collision of the small ball, but this loss is smaller than that of a completely inelastic collision.

In an elastic collision, if the two balls have equal masses, they will move in opposite directions with the same velocity after the collision. If the mass of a small ball is significantly greater than the mass of the other ball, then the ball will be after the collision and the other ball will move in the opposite direction of its previous motion.

4.Incomplete elastic collision: In this case, there is also a loss of mechanical energy after the collision of the small ball, but this loss is smaller than that of an elastic collision.

In a non-early slag fully elastic collision, a small ball will come to rest after the collision, while the other ball will move in the opposite direction of its previous direction.

The above are the four situations in which the ball collides.

There are three cases:

1. Completely elastic collision, no mechanical energy loss.

2. Completely non-elastic segmental collision, the most devastating loss of mechanical energy, is the kind that sticks together after the collision.

3. Elastic collision, there is mechanical energy loss. The movement situation should be based on the type of object. Completely elastic, with the same mass, velocity exchange occurs when one is static and one is moving; If the small touches the big one, it will go back to the big one, and the small stop will go big.

Summary. The velocity at which the ball collides with the ground depends on several factors such as the initial velocity of the ball, its mass, the angle at which it collided, the nature of the ground, etc. When a collision occurs, a part of the kinetic energy will be converted into other forms of energy, such as heat energy, sound energy, etc.

As a result, the velocity of the ball may decrease after a collision. If it is assumed that there are no other factors and that the ground is an ideal rigid plane, the change in velocity on collision can be described by the law of conservation of momentum. The law of conservation of momentum states that the total momentum of the system remains constant during the collision.

According to this principle, the velocity of the ball after colliding with the ground can be calculated. However, it is important to note that the specific circumstances of a collision will vary depending on various factors, such as the degree of elasticity of the collision, the friction of the surface, etc. Therefore, it is not possible to give a specific speed value, but it is necessary to analyze the specific problem and consider the influence of these factors.

The velocity at which the ball collides with the ground depends on a number of factors, such as the initial velocity of the ball, its mass, the angle at which it collides, and the nature of the ground incorporation. When a collision occurs, a part of the kinetic energy will be converted into other forms of energy, such as heat energy, sound energy, etc. As a result, the velocity of the ball may decrease after a collision.

If it is assumed that there are no other factors and that the ground is an ideal rigid plane, the change in velocity on collision can be described by the law of conservation of momentum. The law of conservation of momentum states that the total momentum of the system remains constant during the collision. According to this principle, the velocity of the ball after colliding with the ground can be calculated.

However, it is important to note that the specific circumstances of a collision will vary depending on various factors, such as the degree of elasticity of the collision, the friction of the surface, etc. Therefore, it is not possible to give a specific velocity value, but it is necessary to analyze the specific hole of the specific problem and consider the influence of these factors.

Fellow, I really didn't understand, I can be more specific.

The velocity at which the ball collides with the ground depends on a number of factors, such as the initial velocity of the ball, its mass, the angle at which it collides, and the nature of the ground incorporation. When a collision occurs, a part of the kinetic energy will be converted into other forms of energy, such as heat energy, sound energy, etc. As a result, the velocity of the ball may decrease after a collision.

If it is assumed that there are no other factors and that the ground is an ideal rigid plane, the change in velocity on collision can be described by the law of conservation of momentum. The law of conservation of momentum states that the total momentum of the system remains constant during the collision. According to this principle, the velocity of the ball after colliding with the ground can be calculated.

However, it is important to note that the specific circumstances of a collision will vary depending on various factors, such as the degree of elasticity of the collision, the friction of the surface, etc. Therefore, it is not possible to give a specific velocity value, but it is necessary to analyze the specific hole of the specific problem and consider the influence of these factors.

v1'=(2m2v2-m2v1v2+m1v1) (m1+m2), wide v2'=(2m1v1-m1v2+m2v2)/(m1+m2）。

Analysis: Let m1 and m2 represent the masses of the two spheres, respectively;

v1 and v2 represent the velocities of the two balls before the collision, respectively.

v1'，v2'They represent the velocities of the two small balls after the collision.

According to the law of conservation of momentum, there is: m1v1 + m2v2 = m1v1'+m2v2'

According to the conservation of energy: Zambi 1 2m1v1 2+1 2mv2 2=1 2mv1'^2+1/2mv2'^2

Simplified: v1'=(2m2v2-m2v1v2+m1v1)/(m1+m2)

v2'=(2m1v1-m1v2+m2v2)/(m1+m2）<>

Summary. The victim is in front, the hitter is behind, the front and rear two balls must be separated, one in front and one behind, the speed is one large and one is small, and the speed of the rear ball cannot be greater than the speed of the front ball and cross it (the collision process is in the same orbit of the two balls), if not separated the velocity is equal.

Why is the velocity of the ball being struck at the time of the conservation of momentum verified to be greater than the velocity of the ball that was hit before the collision?

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The victim is in front, the hitter is behind, the front and rear two balls must be separated, one in front and one behind, the speed is one large and one is small, and the speed of the rear ball cannot be greater than the speed of the front ball and cross it (the collision process is in the same orbit of the two balls), if not separated the velocity is equal.