Voltage 6000 volts, common rate 650 kilowatts, how much current

Updated on science 2024-04-12
9 answers
  1. Anonymous users2024-02-07

    The current is calculated as follows:

    DC circuit: p=ui, so i=p u=650x(1000) 6000=650 6=.

    Here p is the DC power, U is the DC voltage, and I is the DC current.

    AC circuits: There are three concepts of AC circuit power:

    a) Active power: p=UICOS(a), (a) is the phase difference between the current and voltage of the circuit, and COS(A) is called the power factor.

    b) Reactive power: q=uisin(a).

    c) Apparent power: s=ui.

    Purely resistive load circuits, such as electric furnaces, incandescent lamps, etc., have a power factor of 1. The power calculation is the same as for DC circuits. p=ui,i=p/u=650x(1000)/6000=。

    Here p is the active power, U is the AC effective voltage, and I is the AC effective current.

    For non-resistive load circuits, such as fluorescent lamps, motors, etc., the power calculation p=uicos(a). In a motor circuit, the power factor is generally , so, i=p (ucos(a)))=650x(1000) (.

  2. Anonymous users2024-02-06

    .5000w is 5 kWh.

    According to the unit conversion, 1000 mA is equal to 1 ampere, then 500 mA is equal to ampere. Therefore, 1 kilowatt-hour of electricity can be charged to about 100,000 milliamperes.

    Extended information: 1 kWh 1 kWh, a power of 1 kWh of electricity consumes 1 kWh of electricity for 1 hour of continuous operation. The calculation formula is: electricity consumption (kW) Power (kW) Usage time (hours).

    KWh. It is what is usually called "degree", which is electrical work.

    The unit of , symbol: kw·h, is calculated as power multiplied by time. Suppose the power of a power-hungry device is 2500 watts, that is, its power consumption in one hour is kilowatt-hours, which is one hour of electricity. The unit of work is joules.

    and kWh, the relationship between them is as follows: 1 joule = 1 watt second 1 kWh = 1 kWh 1 hour = 1000 watts 1 hour = 1000 watts 3600 seconds = 3600000 joules i.e.: 1 kWh = joules.

    The unit of "kilowatt hour" is mainly used to measure electricity, because "kilowatt hour" is more easily understood by the general public than joules and is more easily translated into hours of electrical use. On the other hand, the unit measure of joules relative to "kilowatt hours" is too small to be easily calculated.

  3. Anonymous users2024-02-05

    Summary. The following is an extension of the voltage, current, and power related formulas and deformation forms for you, I hope it can be helpful to you.

    1. Current formula: current (i) = power (p) voltage (u); 2. Voltage formula: voltage (u) = power (p) current (i); 3. Power formula:

    Power (p) = voltage (u) current (i). The higher the voltage, the smaller the current and the smaller the wire cross-section, and vice versa.

    What is the current of 6000 volts 500kw.

    Hello, Bi Chenmao is happy to answer for you. 6,000 volts 500kw current is ampere. The reason is as follows, according to the relationship between the current and the power of the brother's voltage, the current can be obtained from 500000 6000, and the formula of power voltage and current is power = voltage multiplied by Fengxiao current (p = ui).

    The mountain judgment kw is not an international standard unit, when using this formula to calculate the current, kw must be converted to w, that is, 500kw is equal to 500000w

    The voltage, current, and power related formulas and deformation forms that are extended to you are expected to be helpful to you. 1. Current formula: current (i) = power (p) voltage (u); 2. Voltage formula Xiaolu:

    Voltage (U) = Power (P) Current (i); 3. Power formula: power (p) = voltage bizarre (u) current (i). The higher the voltage, the smaller the current and the smaller the wire cross-section, and vice versa.

    The voltage, current, and power related formulas and deformation forms that are extended to you are expected to be helpful to you. 1. Current formula: current (i) = power (p) voltage (u); 2. Voltage formula Xiaolu:

    Voltage (U) = Power (P) Current (i); 3. Power formula: power (p) = voltage bizarre (u) current (i). The higher the voltage, the smaller the current and the smaller the wire cross-section, and vice versa.

    The voltage, current, and power related formulas and deformation forms that are extended to you are expected to be helpful to you. 1. Current formula: current (i) = power (p) voltage (u); 2. Voltage formula Xiaolu:

    Voltage (U) = Power (P) Current (i); 3. Power formula: power (p) = voltage bizarre (u) current (i). The higher the voltage, the smaller the current and the smaller the wire cross-section, and vice versa.

  4. Anonymous users2024-02-04

    220V kilowatt is about current

    The voltage is 220V, and the voltage and current can be calculated using the formula, and the current leakage at 1000W can be directly calculated.

    The single electric power male sock hand is in p=u i, and where p is the power, u is the voltage, i is the current, and then according to the formula, i = p u.

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    Generally, the higher quality air switches, the shell is made of flame-retardant PC material, and the inside is pure copper wire. In addition, the more turns, the better the quality of the circuit breaker.

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  5. Anonymous users2024-02-03

    6 thousand volts 550 kilowatt current Hello dear, happy to answer for you. According to the three-phase electricity formula p=power factor (this formula is applicable to three-phase AC rubber slag generators, but also to 3-phase AC motors) i=p (power factor)=550000 ( (root number 3= voltage u=400v power factor bucket = finish the work Current: I hope it can help you.

    If my answer is helpful to you, please give a thumbs up (in the lower left corner), I look forward to your like, your efforts are very important to me, and your support is also the motivation for my progress. Finally, I wish you good health and a happy mood!

  6. Anonymous users2024-02-02

    Answer: Hello, dear dear, current: according to the three-phase electricity formula p=the rate factor of the power barrier (this formula is applicable to the three-phase alternator, and also applies to the three-phase AC motor) i=p (power factor)=550000 ( (root number 3 = voltage u = 400v power factor = current:

    If you have any questions, you can give me feedback in time! I hope mine is helpful to you, I wish you a happy life, if mine is helpful to you I hope you can give a 5 star like. Thank you for your support.

  7. Anonymous users2024-02-01

    The operating current of 650kW is 1235A. After investigation, it can be seen that the total power of the absolute reserve is 650kw, and the working macro voltage is 380v, so the rough current of the working electric argument is: i=650 (.

  8. Anonymous users2024-01-31

    Calculate the dispersion: 1000000 750 = amps.

    Three-phase electricity calculation is not adapted to this table with Chong He Xun to pat Hu.

  9. Anonymous users2024-01-30

    Voltages of 100 kilowatts and 600 volts can be calculated using Watt's law using the following formula:

    Current (amps) = Power (watts) Voltage (volts) Substitute 100 kW and 600 volts Oakguess into the formula.

    Current (amps) = 100,000 600 current (imitation hidden amps) =

    Therefore, at 100 kilowatts and 600 volts, the current is about amperes.

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