Can anyone give me a question type or exercise for a function!

(1) To make the intersection of the function image and the y-axis above the x-axis, b should be greater than 0, so 2-n is greater than 0, n<2, k should not be equal to 0, so 2m-3 is not equal to 0, and m is not equal to 3 2Answer: n<2, m is not equal to 3 2.

2) To make the image of the function pass through the first.

1, 3, 4 quadrants, so that k>0, b<0

So 2m-3>0,2-n<0, get m>3 2,n>2Answer: m>3 2,n>2.

Solution: (1) from the problem, 2-n>0, n<2;

2) After 134 quadrants, 2m-3 0,m3 2; 2-n<0,n>2;

1. If someone uses an IC card recharged with 50 yuan to make a long-distance call from place A to place B, he will be charged according to the call time, and he will be charged for 3 minutes, and he will be charged 1 yuan for every more than 1 minute after walking. If the person makes the first call for T minutes (3 T 45), the relationship between the remaining fee Y (yuan) and T (minutes) on the IC card is

2. The charging standard for collective tickets for a scenic spot is 25 yuan per person for less than 20 people (including 20 people), and 10 yuan per person for more than 20 people.

1) Write the functional relationship between the receivable admission fee y (yuan) and the number of visitors x (people);

2) Use the function relationship in (1) to calculate how much money was spent on tickets for a class of 54 students to visit the scenic spot?

3) If a total of 2,000 yuan is spent on the purchase of tickets, how many people are in the tour group?

3. The current annual output value of a school-run factory is 300,000 yuan, and if it increases by 1,000 yuan, the output value can increase by 2,500 yuan a year. Then the functional relationship between the total output value y (10,000 yuan) and the increased investment amount x (10,000 yuan) is

4. Let the circumference of an isosceles triangle be 45, a waist is x, and the bottom is y, write y and use x to represent the function relationship to determine the value range of the independent variable x

Find the value of y when x=15 and indicate what kind of triangle is at this time?

5, Yangzhou railway freight station existing A kind of goods 1530 tons, B kind of goods 1150 tons, arrange with a train of freight cars to this batch of goods to Guangzhou, this train of freight cars can hang A, B two different specifications of the cargo compartment 50 sections, known with a section A type cargo compartment freight is tons of 10,000 yuan, with a section of B type cargo compartment freight is 10,000 yuan.

1) Let the total freight of this batch of goods be y (10,000 yuan), and the number of sections of type A goods is x (sections), and try to write the functional relationship between y and x;

2) It is known that 35 tons of A cargo and 15 tons of B cargo can be filled with a type A cargo box, 25 tons of A cargo and 35 tons of B cargo can be filled with a B type cargo box, according to this requirement to arrange the number of sections of A and B cargo compartments, what are the transportation schemes? Please design it.

3) Using the nature of the function, which of these scenarios has the least total shipping cost? How much is the minimum shipping cost?

Solution: Let y=kx+3 be too noisy and cautious a(-6,0) points to ascend to respect.

Get y=let y=kx+1 pass c(,0) point.

y=2x+1

Because the line A1 has an intersection point with the line A2.

So the solution is x=4 3

Substituting x=4 3 into y=2x+1, so y=11 3 so g(4 3, 11 3).

So the area of the selling triangle GAC = 11 2 * 11 3 * 1 2 = 121 12

A is an acute angle, COSA is positive, COSA = 1 --- sina square under the root number = 3, 5sin2a = 2sinacosa

cos2a = 1-2sina square.

tan（a-4/5π) tana+tan4/5π)/1-tanatan4/5π)

tana=sina/cosa

Count the rest.

Solution: If the original investment environment remains unchanged, as long as 400,000 yuan is invested from the 600,000 yuan special fund every year, the maximum profit of 100,000 yuan can be obtained, so that the maximum value of the total profit in 10 years is w 10 10 100 (10,000 yuan).

If the product is developed, then in the first 5 years, when x 30, pmax (75 8), the total profit for the first 5 years is.

w1 (75 8) 5 (375 8) (10,000 yuan).

In the next 5 years, X million yuan will be used for local sales investment, and 60 x million yuan will be used for non-local sales investment, and the total profit will be made.

w2＝〔－1／160）（x－40）2＋10〕×5＋〔－159／160）x2＋（119／2）x〕×5��＝5（x－30）2＋4500．

So when x 30, the maximum profit of W2 is 45 million yuan, so the maximum profit of the total profit in 10 years is 375 8 45 million yuan

375 8 4500 100, the project has great development value.