Mathematics in the first year of high school, how to do this problem

x=0. m=0

x 2-6x=0 yes.

x=6. m=0 or m=6, m=0 matches.

m=6. x 2-18x+144=0 does not match.

So m=0

In the set a, =(4m+6) 2-4 4m 2=48m+36 0, a= ;

That is, when 48m+36 0 m 3 4, a= is a subset of b, which meets the requirements;

At 0, a has two elements, and a is a subset of b, i.e., a=b;

b=,x=0,6 is substituted into a, and when m=0, a= is a subset of b, which meets the requirements.

At 0, m= 3 4, a= is not a subset of b, which does not meet the requirements.

In summary, m3 4 or m=0

If the judgment condition is equal to zero, that is: (4m+6) 2-4*4*m 2=48m+36=0, m=-3 4, then there is only one element in a, a=, which contradicts the condition, so m is not equal to . If m<-3 4,a is an empty set, the condition is met.

If m>0, that is, there are two elements in a, at this time, x1= are the two solutions of the equation, according to what theorem, so, x1+x2=(4m+6), x1*x2=4m2.So m=0In summary, m<-3 4, or m=0

a b, i.e., m=0 when x=0;When x = 6, m = 0 or 6

A=B, that is, A needs to satisfy x(x-6)=0, and x2-6x=0, substituting A, to obtain -6=-(4m-6) and 4m 2=0, and the solution is m=0

So m=0 or m=6

Knowing the function fx=sinx-1 2x, x belongs to 0 to , find the monotonically increasing interval of the function and the tangent equation of the function image at the point x= 3.

f(x)=sinx-(1/2)x

then f'(x)=cosx-1/2

1) Increase the interval.

cosx-1/2>0

cosx>1/2

0 x can be inferred.

Answer: The coupling PQ is a string of a circle, and according to the perpendicular diameter theorem, the diameter of the circle must be on the perpendicular bisector of the chord. Passing through the midpoint of pq, a straight line perpendicular to l must be a straight line passing through the center of the circle. That's how it came about.

Using the perpendicular diameter theorem, the straight line connecting the midpoints of the central chord is perpendicular to the chord.

This is to make use of the property of the line segments associated with the circle, the vertical diameter theorem of the circle.

<> this shoot eggplant like a worm and bury the blind.

<> ginseng Wang Wu and the ants are in ambush.

Let the quadratic function be f(x)=ax 2+bx+c

Because f(0)=2 gives c=2

Because f(x+1)-f(x)=x-1

a(x+1) 2+b(x+1)+c-ax 2-bx-c=x-12ax+a+b=x-1

2a=1,a+b=-1

Get a=, b=

So f(x)=

Only the logarithm of 1 has nothing to do with the base, so (2x+1)=x-1, x=-2, y=0

P-point coordinates (-2,0).

The power of zero of any number is equal to one, except zero. (—1/2，1)

Because a is a respectful orange less than 1.

So loga a is greater than loga 2a, i.e. loga a = 3loga 2a

loga a = 1

The bright culture group is loga 2a = 1 3

So 2a = a (1 3).

Solution: a=(root number 2) 4

First of all, the function is decreasing in the Bichun interval, so the maximum value of the letter is f(a) and the minimum value is f(2a), that is, the confession of f(a)=3f(2a) is brought into the calculation of a=1 4

Solution: 1 cosx 1, a bcosx

The maximum value of y=a bcosx is 32 and the minimum value is 12, and when b 0, a+b=32a b= 12 is solved to a=12,b=1;At this time, y= 2sinbx+a= 2sinx+12, ymax=52, ymin= 32;

When b<0, a b=32a+b= 12 gives a=12, b= 1;At this time, y= 2sinbx+a= 2sinx+12, ymax=52, ymin= 32;

In summary, ymax=52, ymin=32

Find the value of a and b according to the maximum and minimum value of the function, and then bring the value of b into it, which is very easy.