ReDim and variable assignment issues

Absolutely. The reason why it is a variable is that its value can be changed all the time, so that it can be called a variable.

The same is true for redim, which can change the value of an array variable with an uncertain dimension and the number of elements, or at any time.

Yes, the dim definition is dynamic, in fact, a variable is a specific memory address, just like a container you can put something into, but every time you put it, the previous thing is gone, if you can understand x=x+5

It should be understandable.

The description of the x field read from the database is not a float value, so if something goes wrong, you can modify it

while(

x[i]=;This is the most effective way to try to convert.

What data type is you need to see what type x and y are when you create this table.

Hexadecimal generally starts with 0x, which can also be omitted, but not with a negative sign.

Both octal and hexadecimal numbers can only be positive.

Yes, first of all, the data type of t1 and t2 are the same, they are both structs, and secondly, the mark of t2 is represented by t2, and the mark of t1 is incoherent, but the data type is the same, so it can be assigned, just like the blood type of two brothers, the blood of one brother can be drawn to the other without rejection.

Incorrect. Because mark is an array, it can't be "="."The number is gone; And they are constant pointers and cannot be assigned. can strcpy(,;

Traversing the list such as.

#list test as var>

Don't confuse JS with FreeMarker.

If you have to, use it that way.

#assign i =0 >

alert("$");

float a is like this: 1 is of type int, 8 is also of type int, so 1 8=0 (integer division, there is no decimal in the program, and there is no remainder), float a=0; implicitly convert the integer 0 to float type float a = (float)1 8; That's the decimals.

The book is right, because l = f + l where l is an integer variable, f is a floating-point variable, and f+l results in a floating-point data, and it can't be automatically converted to a long integer.

What is the purpose of a function if it can be done in the class definition.

1. All string is a string type and is not a basic data type int is a basic data type.

It's simple.

Roughly understand what you mean, are you using a database to record variable names?

And then output the value of the variable name set first?

The values read from the database are all strings and must be converted into executable variables using the eval function, which outputs the value of the itemid field by default"a01"

But with the addition of eval(itemid), the value of itemid becomes the value of the variable, and as long as the variable is set in advance, the value of the variable will be output, such as:

eval(rs("itemid"))

Using the eval() function, eval("a01") is the value of the displayed variable a01.

You can do that! Write the following **::

function show(a)

select case a

case "a01"

Test 1")case "a02"

Test 2")end select

end function

Write the following ** on the page: <%call show("a01"%> debug it and try it!

I want to see how it works.